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\(\left(\frac{3}{5}-\frac{2}{3}x\right)^3=\left(\frac{-4}{5}\right)^3\)
\(\frac{3}{5}-\frac{2}{3}x=\frac{-4}{5}\)
\(\frac{2}{3}x=\frac{7}{5}\)
\(x=\frac{21}{10}\)
\(\left(\frac{3}{5}-\frac{2}{3}.x\right)^3=\frac{-64}{125}\)
\(\Leftrightarrow\left(\frac{3}{5}-\frac{2}{3}.x\right)^3=\left(-\frac{4}{5}\right)^3\)
\(\Rightarrow\frac{3}{5}-\frac{2}{3}.x=-\frac{4}{5}\)
\(\Leftrightarrow\frac{2}{3}.x=\frac{3}{5}-\left(-\frac{4}{5}\right)\)
\(\Leftrightarrow\frac{2}{3}.x=\frac{3}{5}+\frac{4}{5}\)
\(\Leftrightarrow\frac{2}{3}.x=\frac{7}{5}\)
\(\Leftrightarrow x=\frac{7}{5}:\frac{2}{3}\)
\(\Leftrightarrow x=\frac{21}{10}\)
Vậy \(x=\frac{21}{10}\)
\(\left(\frac{3}{5}-\frac{2}{3}x\right)^3=\frac{-64}{125}\)
\(\left(\frac{3}{5}-\frac{2}{3}x\right)^3=\left(\frac{-4}{5}\right)^3\)
\(\frac{3}{5}-\frac{2}{3}x=\frac{-4}{5}\)
\(\frac{9}{15}-\frac{10x}{15}=\frac{-12}{15}\)
\(-\frac{10x}{15}=\frac{9}{15}-\frac{-12}{15}\)
\(\text{ }-10x=9+12\)
\(-10x=21\)
\(x=\frac{-21}{10}\)
k nha
\(\left(0,4x-1,3\right)^2=5,29\)
\(\left(0,4x-1,3\right)^2=\left(\pm2,3\right)^2\)
+) 0,4x - 1,3 = 2,3
0,4x = 3,6
x = 9
+) 0,4x - 1,3 = -2,3
0,4x = -1
x = -2,5
Vậy,........
(0,4x - 1,3)2 = 5,29
(0,4x - 1,3)2 = 2,32
=> \(\orbr{\begin{cases}0,4x-1,3=2,3\\0,4x-1,3=-2,3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}0,4x=3,6\\0,4x=-1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-\frac{5}{2}\end{cases}}\)
B = 1+ 2 + 3 + ... + 98 + 99
số số hạng từ 1 đến 99 là : (99 - 1) : 1 + 1 = 99
=) B = (99+1) . 99 : 2 = 4950
vậy B = 4950
\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)
\(\frac{3}{4}:\left(4x-3\right)^2=\frac{25}{12}\)
\(\left(4x-3\right)^2=\frac{9}{25}=\left(\frac{\pm3}{5}\right)^2\)
+) 4x - 3 = 3/5
4x = 18/5
x = 9/10
+) 4x - 3 = -3/5
4x = 12/5
x = 3/5
Vậy,.........
\(\frac{7}{12}-0,75:\left(4x-3\right)^2=-\frac{3}{2}\)
\(\Leftrightarrow\frac{7}{12}.12\left(4x-3\right)^2-\frac{0,75}{\left(4x-3\right)^2}.12\left(4x-3\right)^2=-\frac{3}{2}.12\left(4x-3\right)^2\)
\(\Leftrightarrow7\left(4x-3\right)^2-9=-18\left(4x-3\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{10}\\x=\frac{3}{5}\end{cases}}\)
-3 + 3 = 0 còn 0 x -2 = 0 vậy đáp án là 0.
bằng 0 nha