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\(\frac{4}{5}+\frac{3}{7}+\frac{3}{7}x\frac{1}{5}+\frac{17}{7}\)
\(=\frac{4}{5}+\frac{3}{7}+\frac{3}{35}+\frac{17}{7}\)
\(=\left(\frac{4}{5}+\frac{3}{35}\right)+\left(\frac{3}{7}+\frac{17}{7}\right)\)
\(=\frac{23}{35}+\frac{20}{17}\)
\(\frac{4}{5}×\frac{3}{7}+\frac{3}{7}×\frac{1}{5}+\frac{17}{7}\)
\(=\frac{3}{7}×\left(\frac{4}{5}+\frac{1}{5}\right)+\frac{17}{7}\)
\(=\frac{3}{7}×\frac{5}{5}+\frac{17}{7}\)
\(=\frac{3}{7}×1+\frac{17}{7}\)
\(=\frac{3}{7}+\frac{17}{7}\)
\(=\frac{3+17}{7}\)
\(=\frac{20}{7}\)
\(\left(\frac{2}{3}+\frac{1}{3}:\frac{3}{4}+\frac{5}{9}\right).y-3=25\%+\frac{7}{4}\)
\(\Rightarrow\left(\frac{2}{3}+\frac{4}{9}+\frac{5}{9}\right).y-3=\frac{1}{4}+\frac{7}{4}\)
\(\Rightarrow\left(\frac{2}{3}+1\right).y-3=2\)
\(\Rightarrow\frac{5}{3}.y-3=2\)
\(\Rightarrow y-3=2:\frac{5}{3}\)
\(\Rightarrow y-3=\frac{6}{5}\)
\(\Rightarrow y=\frac{6}{5}+3\)
\(\Rightarrow y=\frac{21}{5}\)
\(\frac{a}{b}+\frac{1}{6}=\frac{5}{3}\)
=> \(\frac{a}{b}=\frac{5}{3}-\frac{1}{6}=\frac{3}{2}\)
\(\frac{a}{b}-\frac{1}{3}=\frac{3}{4}\)
=> \(\frac{a}{b}=\frac{3}{4}+\frac{1}{3}=\frac{13}{12}\)
Tau lạy mi'-'