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7.( x-6 )= 4x +9
=> 7x - 42 - 4x = 9
=> 3x = 51
=> x = 17
a) \(\left(17x-25\right):8+65=9^2\)
\(\left(17x-25\right).\frac{1}{8}+65=81\)
\(\frac{17}{8}x-\frac{25}{8}=81-65\)
\(\frac{17}{8}x-\frac{25}{8}=16\)
\(\frac{17}{8}x=16+\frac{25}{8}\)
\(\frac{17}{8}x=\frac{128}{8}+\frac{25}{8}\)
\(\frac{17}{8}x=\frac{153}{8}\)
\(x=\frac{153}{8}:\frac{17}{8}\)
\(x=\frac{153}{8}.\frac{8}{17}\)
\(x=\frac{153}{17}\)
\(x=9\)
vay \(x=9\)
b) \(80-\left(4.5^2-3.2^3\right)=2^{10}-\left(x-4\right)\)
\(80-\left(100-24\right)=1024-x+4\)
\(80-76=1028-x\)
\(x=1028-80+76\)
\(x=1024\)
vay \(x=1024\)
\(\text{Gọi: }i=\left(a,c\right)\Rightarrow a=ia';c=ic'\left(với\left(a',c'\right)=1\right)\Rightarrow a'b=c'd\Rightarrow b\text{ chia hết cho c}'\)
\(d\text{ chia hết cho a}'\Rightarrow b=c'l;d=a'k\left(l,k\text{ tự nhiên}\right)\Rightarrow a'c'l=a'c'k\Rightarrow l=k\Rightarrow\)
\(b=c'l;d=a'l\Rightarrow A=\left(l+i\right)\left(c'+a'\right)\text{ là hợp số}\)
a, 70 - 5 : ( x - 3 ) = 4
=> 5 : ( x - 3 ) = 66
=> x - 3 = \(\frac{5}{66}\)
=> x = \(\frac{203}{66}\)
b, => 10 + 2x = 16
=> 2x = 6
=> x = 3
c, => 12x - 33 = \(\frac{1}{3}\)
=> 12x = \(\frac{100}{3}\)
=> x = \(\frac{25}{9}\)
d, => [ ( 2x + 14 ) : 2 ^ 2 - 3 ] : 2 = 1
=> ( 2x + 14 ) : 2^2 -3 = 2
=> ( 2x + 14 ) : 4 = 5
=> 2x + 14 = 20
=> 2x = 6
=> x = 3
ab + ba= (a.10+b)+(b.10+a)
=a.11+b.11
=11.(a+b) chia hết cho 11
mà 33=3.11
*Nếu a+b chia hết cho 3 thì UCLN(ab+ba ; 33)=33
*Nếu a+b ko chia hết cho 3 thì UCLN(ab+ba ; 33)=11
\(a,TH1:x-2021=0=>x=2021\)
\(Th2:x-2022=0=>x=2022\)
Vậy \(x\in\left\{2021;2022\right\}\)
\(b,x\left(8-5\right)=1080\)
\(x.3=1080\)
\(x=360\)
\(c,x^3=216< =>6^3=216=>x=3\)
\(d,5^5=3125\)
a) ( x- 2021) * ( x- 2022) = 0
=> \(\orbr{\begin{cases}x-2021=0\\x-2022=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2021\\x=2022\end{cases}}}\)
b) b. 8x - 5x = 2022
=> 3x = 2022
=> x = 674
c) \(5\cdot x^3=1080\)
=> \(x^3=216\)
=> \(x^3=6^3\)
=> x = 6
d) \(5^x=3125\)
=> \(5^x=5^5\)
=> x = 5
1) 2x = 1- 3
2x = -2
x = -2 : 2
x = -1
2) 2x = 5 - 3
2x = 2
x = 2 : 2
x = 1