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NH
1
25 tháng 12 2017
a)
x-3=15
x = 15+3=18
b)
x+7-13=13
x+7 =13-13=0
x = 0-7=-7
c)
x+3-16=-4
x+3 =-4+16=12
x = 12-3=9
d)
26-x-9=-13
-x-9= -13-26=-39
-x =-39+9=-30
x=30
DN
2
4 tháng 2 2021
a, \(\left|x+3\right|=15\)
TH1 : \(x+3=15\Leftrightarrow x=12\)
TH2 : \(x+3=-15\Leftrightarrow x=-18\)
b, \(\left|x-7\right|+13=15\Leftrightarrow\left|x-7\right|=2\)
TH1 : \(x-7=2\Leftrightarrow x=9\)
TH2 : \(x-7=-2\Leftrightarrow x=5\)
4 tháng 2 2021
c, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)
TH1 : \(x-3=12\Leftrightarrow x=15\)
TH2 : \(x-3=-12\Leftrightarrow x=-9\)
d, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)
TH1 : \(x+9=39\Leftrightarrow x=30\)
TH2 : \(x+9=-39\Leftrightarrow x=-48\)
NT
8
3 tháng 2 2016
a,|x-3|-16=-4
=>|x-3|=12
TH1:x-3=12
=>x=15
Th2:x-3=-12
=>x=-9
b,26-|x+9|=-13
=>|x+9|=26-(-13)
=>|x+9|=39
TH1:x+9=39
=>x=30
TH2:x+9=-39
=>x=-48
NP
2
15 tháng 1 2016
a) /x-3 / - 16 =-4
x-3 - 16=-4 hoặc x-3-16=4
x-13=-4+16 hoặc x-3 =4+16
x-13=12 hoac x-3 =20
x=12+13 hoac x =20+3
x=26 hoac x=23
b)26-/x+9/=-13
26-x+9=-13 hoac26-x+9=13
x+9=26--13hoac x+9=26-13
x+9=39hoac x+9=13
x=39-9hoacx=13-9
x=30hoac x=4
3 tháng 3 2020
a,\(x+3=15\)
\(=>x=15-3=12\)
b,\(x-7+3=25\)
\(=>x=25+7-3=29\)
c,\(x-3-6=-4\)
\(=>x=-4+6+3=5\)
d,\(26-x+9=-13\)
\(=>26-x=-13-9=-22\)
\(=>26+22=x\)
\(=>x=48\)
3 tháng 3 2020
x+3=15
x=15-3
x=12
Vậy x=12
x-7+3=25
x-7=25-3
x-7=22
x=22+7
x=29
Vậy x=29
x-3-6=-4
x-3=-4+6
x-3=2
x=2+3
x=5
Vậy x=5
26-x+9=-13
26-x=-13-9
26-x=22
x=26-22
x=4
Vậy x=4
18 tháng 4 2023
\(1,-\dfrac{4}{7}+\dfrac{2}{3}\times\dfrac{-9}{14}\)
\(=\dfrac{-4}{7}+\dfrac{-18}{42}\)
\(=\dfrac{-4\times6}{7\times6}+\dfrac{-18}{42}\)
\(=\dfrac{-20}{42}+\dfrac{-18}{42}\)
\(=-\dfrac{38}{42}\)
\(=-\dfrac{19}{21}\)
\(2,\dfrac{17}{13}-\left(\dfrac{4}{13}-11\right)\)
\(=\dfrac{17}{13}-\dfrac{4}{13}+11\)
\(=\dfrac{13}{13}+11\)
\(=1+11\)
\(=12\)
\(3,8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)
\(=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)\)
\(=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}\)
\(=\dfrac{58}{7}-\dfrac{30}{7}-\dfrac{31}{9}\)
\(=\dfrac{28}{7}-\dfrac{31}{9}\)
\(=\dfrac{28\times9}{7\times9}-\dfrac{31\times7}{9\times7}\)
\(=\dfrac{252}{63}-\dfrac{217}{63}\)
\(=\dfrac{35}{63}\)
\(=\dfrac{5}{9}\)
\(5,\left(\dfrac{2}{3}-1\dfrac{1}{2}\right):\dfrac{4}{3}+\dfrac{1}{2}\)
\(=\left(\dfrac{2}{3}-\dfrac{3}{2}\right):\dfrac{4}{3}+\dfrac{1}{2}\)
\(=\left(\dfrac{2\times2}{3\times2}-\dfrac{3\times3}{2\times3}\right):\dfrac{4}{3}+\dfrac{1}{2}\)
\(=\left(\dfrac{4}{6}-\dfrac{9}{6}\right):\dfrac{4}{3}+\dfrac{1}{2}\)
\(=\dfrac{-5}{6}:\dfrac{4}{3}+\dfrac{1}{2}\)
\(=\dfrac{-5}{6}\times\dfrac{3}{4}+\dfrac{1}{2}\)
\(=\dfrac{-15}{24}+\dfrac{1}{2}\)
\(=\dfrac{-15}{24}+\dfrac{1\times12}{2\times12}\)
\(=\dfrac{-15}{24}+\dfrac{12}{24}\)
\(=\dfrac{-3}{24}\)
\(=-\dfrac{1}{8}\)
\(6,\dfrac{-5}{13}+\dfrac{2}{5}+\dfrac{-8}{13}+\dfrac{3}{5}-\dfrac{3}{7}\)
\(=\left(\dfrac{-5}{13}+\dfrac{-8}{13}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)-\dfrac{3}{7}\)
\(=\dfrac{-13}{13}+\dfrac{5}{5}-\dfrac{3}{7}\)
\(=-1+1-\dfrac{3}{7}\)
\(=-\dfrac{3}{7}\)
\(7,\dfrac{6}{5}\times\dfrac{3}{7}+\dfrac{6}{5}:\dfrac{7}{10}+\dfrac{6}{5}\)
\(=\dfrac{6}{5}\times\dfrac{3}{7}+\dfrac{6}{5}\times\dfrac{10}{7}+\dfrac{6}{5}\)
\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+1\right)\)
\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+\dfrac{1\times7}{1\times7}\right)\)
\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+\dfrac{7}{7}\right)\)
\(=\dfrac{6}{5}\times\dfrac{20}{7}\)
\(=\dfrac{120}{35}\)
\(=\dfrac{24}{7}\)
O
2
26-3.|x+9| =-13
3.|x+9|=26-(-13)
3.|x+9|=39
|x+9|=39:3
|x+9|=13
--> x+9=13 hoặc x+9= (-13)
x=13-9 x=(-13)-9
x=4 x=(-22)
Vậy x thuộc {4;-22}
26-3.|x+9|=-13
3.|x+9|=26-(-13)
3.|x+9|=39
|x+9|=39:3
|x+9|=13
* x+9=13 * x+9=-13
x=13-9 x=-13-9
x=4 x=-22
Vậy x=4 hoặc x=-22