Question

[Cà Ngọc Thu]

2³.4².5³

9.3^{3.\(\dfrac{1}{81}\).}3²

3².5².\((\dfrac{2}{3})\)²

\((\dfrac{1}{3})\)².\(\dfrac{1}{3}\).9²

Answer 1

[Hjhjhjhjhjhjhjhj]

 \(2^3. 4^2 . 5^3 \)\(= 8 . 16 . 125 = 16000\)

\(9.3^3.\dfrac{1}{81}.3^3=\left(9.81\right)\left(\dfrac{1}{81}.81\right)=729\)

\(3^2.5^2\left(\dfrac{2}{3}\right)^2=9.25.\dfrac{2^2}{3^2}=9.25.\dfrac{4}{9}=100\)

\(\left(\dfrac{1}{3}\right)^2.\dfrac{1}{3}.9^2=\dfrac{1}{9}.9.\dfrac{1}{3}.9=3\)

Answer 2

[Joyce Nguyễn]

\(2^3.4^2.5^3=\left(2^3.5^3\right).4^2=10^3.4^2=1000.16=16000\)

\(9.3^3.\dfrac{1}{81}.3^2=\left(9.\dfrac{1}{81}\right).\left(3^3.3^2\right)=\dfrac{1}{9}.3^5=\dfrac{3^5}{3^2}=3^3=81\)

\(3^2.5^2.\left(\dfrac{2}{3}\right)^2=5^2.\left[3^2.\dfrac{2^2}{3^2}\right]=5^2.2^2=10^2=100\)

\(\left(\dfrac{1}{3}\right)^2.\dfrac{1}{3}.9^2=\left(\dfrac{1}{3}\right)^2.\left(\dfrac{1}{3}.9^2\right)=\dfrac{1}{9}.\dfrac{9^2}{3}=\dfrac{9}{3}=3\)