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{8.30-[76-(9-3)2 ]} :50
={240-[76-36]} :50
={240-40} :50
=200:50 =4
\(\left\{2^2.30-\left[76-\left(9-3\right)^2\right]\right\}:50\)
\(=\left[2^2.30-\left(76-6^2\right)\right]:50\)
\(=\left[2^2.30-\left(76-36\right)\right]:50\)
\(=\left(2^2.30-40\right):50\)
\(=\left(4.30-40\right):50\)
\(=\left(120-40\right):50\)
\(=80:50\)
\(=\dfrac{8}{5}\)
\(=1,6\)
={ 2 3 x 30 - [ 76 - ( 9 - 3 ) 2 ] } : 50
={ 6 x 30 - [ 76 - 62 ] } :50
={ 180 - [ 76 - 36 ]} :50
={ 180 - 40 } :50
=140 :50
=2,8
{2^3 x 30-[ 76-(9-3)^2]} : 50
= { 8x30-[76-6^2]} :50
= [240-(76-36)]:50
=( 240-40):50
=200:50
=4
a: =(-3+3)+(7+13)+(-9+50-54)
=20-13
=7
b: \(=-8\cdot21+8\cdot13-8\cdot72-80\cdot21+80\cdot76-80\cdot132\)
=-6800
đề sai thì phải
\(A=\frac{10}{2\cdot12}+\frac{2}{3\cdot5}+\frac{3}{5\cdot8}+\frac{1}{2\cdot3}+\frac{5}{12\cdot17}+\frac{6}{17\cdot23}+\frac{7}{23\cdot30}\)
\(A=\frac{1}{2}-\frac{1}{12}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{2}-\frac{1}{3}+\frac{1}{12}-\frac{1}{17}+\frac{1}{17}-\frac{1}{23}+\frac{1}{23}-\frac{1}{30}\)
\(A=\frac{1}{2}+\frac{1}{2}-\frac{1}{8}-\frac{1}{30}\)
\(A=\frac{101}{120}\)
\(A=\frac{1}{2.12}+\frac{2}{3.5}+\frac{3}{5.8}+...+\frac{7}{23.30}\)
\(=\frac{1}{2}-\frac{1}{12}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...-\frac{1}{23}+\frac{1}{23}-\frac{1}{30}\)
\(=\frac{1}{2}+\frac{1}{2}-\frac{1}{8}-\frac{1}{30}=1-\frac{19}{120}=\frac{101}{120}\)
=(240-(76-62)):50
=(240-40):50
=200:50
=4
nhầm
{23-[76-(9-3)2]} : 50
= 23 - [76 - 36] : 50
= 8 - 40 : 50
= 8 - 4/5
= 36/5