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`@` `\text {Ans}`
`\downarrow`
`1)`
\(2x+\dfrac{1}{2}=\dfrac{5}{3}\)
`\Rightarrow`\(2x=\dfrac{5}{3}-\dfrac{1}{2}\)
`\Rightarrow`\(2x=\dfrac{7}{6}\)
`\Rightarrow`\(x=\dfrac{7}{6}\div2\)
`\Rightarrow`\(x=\dfrac{7}{12}\)
Vậy, `x = 7/12`
`2)`
\(\dfrac{1}{7}+\dfrac{4}{5}x=\dfrac{5}{3}\)
`\Rightarrow`\(\dfrac{4}{5}x=\dfrac{5}{3}-\dfrac{1}{7}\)
`\Rightarrow`\(\dfrac{4}{5}x=\dfrac{32}{21}\)
`\Rightarrow`\(x=\dfrac{32}{21}\div\dfrac{4}{5}\)
`\Rightarrow`\(x=\dfrac{40}{21}\)
Vậy, `x = 40/21`
`3)`
\(\dfrac{3}{5}-\dfrac{3}{5}x=\dfrac{1}{7}\)
`\Rightarrow`\(\dfrac{3}{5}x=\dfrac{3}{5}-\dfrac{1}{7}\)
`\Rightarrow`\(\dfrac{3}{5}x=\dfrac{16}{35}\)
`\Rightarrow`\(x=\dfrac{16}{35}\div\dfrac{3}{5}\)
`\Rightarrow`\(x=\dfrac{16}{21}\)
Vậy, `x = 16/21`
`4)`
\(\dfrac{5}{6}-3x=\dfrac{3}{4}\)
`\Rightarrow`\(3x=\dfrac{5}{6}-\dfrac{3}{4}\)
`\Rightarrow`\(3x=\dfrac{1}{12}\)
`\Rightarrow`\(x=\dfrac{1}{12}\div3\)
`\Rightarrow`\(x=\dfrac{1}{36}\)
Vậy, `x = 1/36`
`5)`
\(\dfrac{5}{3}-\dfrac{1}{2}x=\dfrac{3}{7}\)
`\Rightarrow`\(\dfrac{1}{2}x=\dfrac{5}{3}-\dfrac{3}{7}\)
`\Rightarrow`\(\dfrac{1}{2}x=\dfrac{26}{21}\)
`\Rightarrow`\(x=\dfrac{26}{21}\div\dfrac{1}{2}\)
`\Rightarrow`\(x=\dfrac{52}{21}\)
Vậy, `x = 52/21`
`6)`
\(5x+\dfrac{1}{2}=\dfrac{2}{3}\)
`\Rightarrow`\(5x=\dfrac{2}{3}-\dfrac{1}{2}\)
`\Rightarrow`\(5x=\dfrac{1}{6}\)
`\Rightarrow`\(x=\dfrac{1}{6}\div5\)
`\Rightarrow`\(x=\dfrac{1}{30}\)
Vậy, `x = 1/30.`
\(\left(x+2\right)-2=0\)
\(\Rightarrow x+2-2=0\)
\(\Rightarrow x=0\)
\(\left(x+3\right)+1=7\)
\(\Rightarrow x+3+1=7\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=3\)
\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)
\(\Rightarrow3x=12\)
\(\Rightarrow x=4\)
\(\left(5x+4\right)-1=13\)
\(\Rightarrow5x+4-1=13\)
\(\Rightarrow5x+3=13\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=2\)
\(\left(4x-8\right)-3=5\)
\(\Rightarrow4x-8-3=5\)
\(\Rightarrow4x-11=5\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=4\)
\(8-\left(2x+4\right)=2\)
\(\Rightarrow8-2x-4=2\)
\(\Rightarrow4-2x=2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(7+\left(5x+2\right)=14\)
\(\Rightarrow7+5x+2=14\)
\(\Rightarrow9+5x=14\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=1\)
\(5-\left(3x-11\right)=1\)
\(\Rightarrow5-3x+11=1\)
\(\Rightarrow16-3x=1\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
a: \(2x+36:12=5\cdot3\)
\(\Leftrightarrow2x+3=15\)
hay x=6
Tính phải k nhỉ?
`1)`
`2x + 3x + 5x`
`= (2 + 3 + 5)x`
`= 10x`
`2)`
`2.x - x + 3.x`
`= (2 - 1 + 3)x`
`= 4x`
`3)`
`9.x - 3 - 3.x`
`= (9 - 3)x - 3`
`= 6x - 3`
`4)`
Thiếu dấu, bạn bổ sung thêm
`5)`
`x - 0,2x - 0,1x`
`= (1 - 0,2 - 0,1)x`
`=0,7x`
`6)`
\(\dfrac{7}{2}x-\dfrac{1}{2}x=\left(\dfrac{7}{2}-\dfrac{1}{2}\right)x=3x\)
\(\left|-\frac{2}{5}x-\frac{1}{5}\right|-\frac{1}{4}=\frac{3}{4}\)
\(\Leftrightarrow\left|-\frac{2}{5}x-\frac{1}{5}\right|=\frac{3}{4}+\frac{1}{4}\)
\(\Leftrightarrow\left|-\frac{2}{5}x-\frac{1}{5}\right|=\frac{4}{4}\)
\(\Leftrightarrow\left|-\frac{2}{5}x-\frac{1}{5}\right|=1\)
\(\Leftrightarrow\orbr{\begin{cases}-\frac{2}{5}x-\frac{1}{5}=1\\-\frac{2}{5}x-\frac{1}{5}=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-3\\x=2\end{cases}}\)
Vậy x = -3 hoặc x = 2
\(\left|-\frac{2}{5}x-\frac{1}{5}\right|-\frac{1}{4}=\frac{3}{4}\)
=> \(\left|-\frac{2}{5}x-\frac{1}{5}\right|=1\)
=> \(\orbr{\begin{cases}-\frac{2}{5}x-\frac{1}{5}=1\\-\frac{2}{5}x-\frac{1}{5}=-1\end{cases}}\)
=> \(\orbr{\begin{cases}-\frac{2}{5}x=\frac{6}{5}\\-\frac{2}{5}x=-\frac{4}{5}\end{cases}}\)
=> \(\orbr{\begin{cases}x=-3\\x=2\end{cases}}\)
\(\dfrac{3}{5}x-\dfrac{1}{2}x=\dfrac{3}{2}-0\)
\(\left(\dfrac{3}{5}-\dfrac{1}{2}\right)x=\dfrac{3}{2}\)
\(\dfrac{1}{10}\cdot x=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}:\dfrac{1}{10}\)
\(x=15\)
\(\dfrac{3}{5x}-\dfrac{1}{2x}=\dfrac{3}{2-0}\)
\(\dfrac{3}{5x}+\dfrac{-1}{2x}=\dfrac{3}{2}\)
\(\dfrac{3}{5}+\dfrac{-1}{2}=\dfrac{3}{2}\cdot x\)
\(\dfrac{1}{10}=\dfrac{3}{2}\cdot x\)
\(\dfrac{3}{2}\cdot x=\dfrac{1}{10}\)
\(x=\dfrac{1}{10}\div\dfrac{3}{2}\)
\(x=\dfrac{2}{30}\)
\(x=\dfrac{1}{15}\)
`a)` `2/3 - 1 =` `-``1/3`
`b)` `4/5``x =``-`3/5`
`x = -``3/5` `: 4/5`
`x = -0,03`
\(\frac{2}{3}-1\frac{4}{5}x=-\frac{3}{5}\)
=> \(\frac{9}{5}x=\frac{2}{3}+\frac{3}{5}\)
=> \(\frac{9}{5}x=\frac{19}{15}\)
=> \(x=\frac{95}{135}\)