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= 1/2 - 1/4 + 1/4 - 1/6 + 1/6 - 1/8 +......+ 1/2014 - 1/2016
= 1/2 - 1/2016
= 1008/2016 - 1/2016
= 1007/2016
không chắc lắm!!!
\(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{2014.2016}\)
=\(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2014}-\frac{1}{2016}\)
<=>\(\frac{1}{2}-\left(-\frac{1}{2016}\right)=\frac{1}{2}+\frac{1}{2016}=\frac{1009}{2016}\)
\(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+....+\frac{2}{2014.2016}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2014}-\frac{1}{2016}\)
\(=\frac{1}{2}-\frac{1}{2016}=\frac{1008}{2016}-\frac{1}{2016}=\frac{1007}{2016}\)
Ta co : 2/2*4+2/4*6+2/6*8+.....+2/2014*2016
=1/2-1/4+1/4-1/6+1/6-1/8...+1/2014-1/2016
=1/2-1/2016=1007/2016
2/2 x 4 + 2/2 x 6 +2/6 x 8 + ...................... +2/2014 x 2016
=2/2 - 2/4 +2/2 -2/6 + 2/6 +2/8 + .................+2/2014 - 2/2016
rut gon ta duoc con lai: 2/2-2/2016
=1-1/1008
=1007/1008
tk minh nha
chuc ban hoc tot
happy valentine's day
Tham khảo:
b)
c)
7 x 4 + 3 x 4 = (7 + 3) x 4
= 10 x 4
= 40
12 x 2 + 4 x 2 + 4 x 2 = (12 + 4 + 4) x 2
= 20 x 2
= 40
`(3xx4xx7)/(5xx3xx4)=7/5`
`(2xx5xx6xx8)/(6xx2xx8xx9)=5/9`
`(4xx5xx6)/(3xx10xx8)= (4xx5xx6)/(3xx5xx2xx4xx2)= 6/(3xx2xx2)= 6/(6xx2)=1/2`
\(a,\dfrac{3\times4\times7}{5\times3\times4}=\dfrac{7}{5}\)
\(b,\dfrac{2\times5\times6\times8}{6\times2\times8\times9}=\dfrac{5}{9}\)
\(c,\dfrac{4\times5\times6}{3\times10\times8}=\dfrac{2}{4}=\dfrac{1}{2}\)
1) 1/3 x 1/2 x 3/7 = 1/6 x 3/7 = 1/14
2) 5/4 x 1/3 + 1/7 = 5/12 + 1/7 = 47/84
3) 8 x (8/9 - 2/3) = 8 x 2/9 = 16/9
4) 5/6 x 48/20 x 1/2 = 2 x 1/2 = 1
5) (2/5 + 3/4) x 8 = 23/20 x 8 = 46/5
6) 10 x (1/2 - 1/5) = 10 x 3/10 = 3
\(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+....+\frac{2}{2014.2016}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+......+\frac{1}{2014}-\frac{1}{2016}\)
\(=\frac{1}{2}-\frac{1}{2016}\)
\(=\frac{1008}{2016}-\frac{1}{2016}=\frac{1007}{2016}\)
\(\frac{2}{2\times4}+\frac{2}{4\times6}+...+\frac{2}{2014\times2016}\)
=\(\left(\frac{2}{2}-\frac{2}{4}\right)+\left(\frac{2}{4}-\frac{2}{6}\right)+...+\left(\frac{2}{2014}-\frac{2}{2016}\right)\)
=\(\frac{2}{2}-\frac{2}{4}+\frac{2}{4}-\frac{2}{6}+...+\frac{2}{2014}-\frac{2}{2016}\)
=\(\frac{2}{2}-\frac{2}{2016}=\frac{1007}{1008}\)