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2. 3x-x = -14-18
2x=-32 suy ra x=-2
3. 2x-x = -13-52
x= -65
4, 2x-10 - 3x +12 = - 6 - 45
x = 2+51 suy ra x= 53
5, 30x + 60 - 6x +30 -24 x =100 +x
x = -10
x-14=3x+18
<=> x-14-3x-18=0
<=> -2x-32=0
<=>-2x=32
<=>x=-16
Vậy x=-16
x-13=2x+52
<=> x-13-2x-52=0
<=> -3x-65=0
<=>-3x=65
<=>x=-65/3
Vậy x=-65/3
2.(x-5)-3.(x-4)=(-6)+15.(-3)
<=> x-5-3x+12=-6-45
<=> 7-2x=-51
<=> 2x=58
<=>x=29
Vậy x=29
30.(x+2)-6.(x-5)-24x=100+x
<=> 30x+60-6x+30-24x=100+x
<=> 90=100+x
<=>x=-10
Vậy x=-10
\(12\left(x-3\right)=5\left(x-1\right)+4\)
\(\Rightarrow12x-36=5x-5+4\)
\(\Rightarrow12x-5x=-5+4+36\)
\(\Rightarrow7x=35\)
\(\Rightarrow x=5\)
\(-6\left(x-7\right)+2\left(x+10\right)=x-18\)
\(-6x+42+2x+20=x-18\)
\(-6x+2x-x=-18-20-42\)
\(-5x=-80\)
\(x=16\)
\(7\left(2x-1\right)-12\left(x-5\right)=3\)
\(\Rightarrow14x-7-12x+60=3\)
\(\Rightarrow14x-12x=3-60+7\)
\(\Rightarrow2x=-50\)
\(\Rightarrow x=-25\)
\(\left|2x-1\right|=17\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=17\\2x-1=-17\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=9\\x=-8\end{cases}}\)
\(\left|8-3x\right|=14\)
\(\Leftrightarrow\orbr{\begin{cases}8-3x=14\\8-3x=-14\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=\frac{22}{3}\end{cases}}\)
Đáp án :
a) \(135+\left(-2\right).14-135+28\)
\(=135+\left(-28\right)-135+28\)
\(=135-28-135+28\)
\(=135-135+28-28=0\)
b) \(-18.2+18.\left(-6\right)+\left(-18\right).3\)
\(=18.\left(2+6+3\right)=18.11=198\)
a) \(135+\left(-2\right)\cdot14-135+28\)
\(=135+\left(-28\right)-135+28\)
\(=\left(135-135\right)+\left[\left(-28\right)+28\right]\)
\(=0+0\)
\(=0\)
b) \(-18\cdot2+18\cdot\left(-6\right)+\left(-18\right)\cdot3\)
\(=-18\cdot2+\left(-18\right).6+\left(-18\right).3\)
\(=-18\cdot\left(2+6+3\right)\)
\(=-18\cdot11\)
\(=-198\)
\(a)135+\left(-2\right).14-135+28\)
\(=135+\left(-28\right)-135+28\)
\(=135-135+\left(-28\right)+28\)
\(=0+0\)
\(=0\)
\(b)\left(-18\right).2+18.\left(-6\right)+\left(-18\right).3\)
\(=\left(-36\right)+\left(-108\right)+\left(-54\right)\)
\(=\left(-144\right)+\left(-54\right)\)
\(=\left(-198\right)\)
a) Ta có: \(\left(2x-5\right)^3=216\)
\(\Leftrightarrow2x-5=6\)
\(\Leftrightarrow2x=11\)
hay \(x=\dfrac{11}{2}\)
b) Ta có: \(2x-3⋮x+4\)
\(\Leftrightarrow-11⋮x+4\)
\(\Leftrightarrow x+4\in\left\{1;-1;11;-11\right\}\)
hay \(x\in\left\{-3;-5;7;-15\right\}\)
Alo, sugeni two wai phem. Si ga no, you woo be the me that nas te, ai gi da