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\(\frac{2}{7}\)+ \(\frac{5}{14}\)+\(\frac{1}{7}\)+ \(\frac{3}{14}\)=\(\frac{4}{14}\)+\(\frac{5}{14}\)+\(\frac{2}{14}\)+\(\frac{3}{14}\)=\(\frac{14}{14}\)=1
469x281+489x719=469x281+(469+20)x719=469x281+469x719+20x719=469x(281+719)+1438=469x1000+1438=469000+1438=470438
a\(\frac{2}{5}\)+\(\frac{5}{14}\)+\(\frac{1}{7}\)+\(\frac{3}{14}\)=\(\frac{53}{70}\)+\(\frac{1}{7}\)=\(\frac{9}{10}\)+\(\frac{3}{14}\)=\(\frac{39}{35}\)
b\(\frac{1995.1997-1}{1996.1995+1994}\)=3984008001
c 469x281+489x719
=(489-469)x(281+719)
=20x1000
=20000
a) \(\frac{35}{14}=\frac{5\times7}{2\times7}=\frac{5}{2}\)
\(\frac{125}{50}=\frac{5\times5\times5}{2\times5\times5}=\frac{5}{2}\)
b)\(\frac{4\times5+4\times11}{8\times7+4\times3}=\frac{4\times\left(5+11\right)}{4\times\left(2\times7+3\right)}=\frac{16}{17}\)
c) \(\frac{3\times11+7\times11}{22\times2+11\times6}=\frac{11\times\left(3+7\right)}{22\times\left(2+3\right)}=\frac{11\times10}{22\times5}=\frac{11\times2\times5}{11\times2\times5}=1\)