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\(a.132-\left[116-4^2\right]\) \(c.120:\left\{300:\left[150-\left(2.125-8.25\right)\right]\right\}\)
= \(132-\left[116-16\right]\) = \(120:\left\{300:\left[150-\left(250-200\right)\right]\right\}\)
= \(132-100\) = \(120:\left\{300:\left[150-50\right]\right\}\)
= \(32\) = \(120:\left\{300:100\right\}\)
= \(120:3\)
= \(40\)
132 - [ 116 - ( 132 - 128 )2 ] { 46 - [( 16 + 71 , 4 ) : 15 ]} -2 Ý cuối cùng mình làm luôn cứ thế mà
= 132 - [ 116 - 16 ] = { 46 - [ 87,4 : 15] } - 2 chép.
=132 - 100 = { 46 - 5,8266 } - 2 = 120 : { 300 : [ 150 - ( 210 - 200) ]}
= 32 = 40,1734 - 2 = 120 : { 300 : [ 150 - 10 ]}
=38,1734m = 120 : { 300 : 140 }
= 120 : 2,1428
= 56,0014
SAI THÌ THÔI NHA !
Giải;
1) \(347.222-222.\left(216+184\right):8\)
\(=347.222-222.400:8\)
\(=347.222-222.50\)
\(=222.\left(347-50\right)\)
\(=222.297\)
\(=65934\)
2) \(132-\left[116-\left(132-128\right).22\right]\)
\(=132-\left[116-4.22\right]\)
\(=132-\left[116-88\right]\)
\(=132-28\)
\(=104\)
3) \(16:\left\{400:\left[200-\left(37+46.3\right)\right]\right\}\)
\(=16:\left\{400:\left[200-\left(37+138\right)\right]\right\}\)
\(=16:\left\{400:\left[200-175\right]\right\}\)
\(=16:\left\{400:25\right\}\)
\(=16:16\)
\(=1\)
4) \(\left\{184:\left[96-124:31\right]-2\right\}.3651\)
\(=\left\{184:\left[96-4\right]-2\right\}.3651\)
\(=\left\{184:92-2\right\}.3651\)
\(=\left\{2-2\right\}.3651\)
\(=0.3651\)
\(=0\)
5) \(46-\left[\left(16+71.4\right):15\right]-2\)
\(=46-\left[\left(16+284\right):15\right]-2\)
\(=46-\left[300:15\right]-2\)
\(=46-20-2\)
\(=24\)
6) \(3^3.18+72.4^2-41.18\)
\(=18.\left(27-41\right)+72.16\)
\(=18.-14+1152\)
\(=-252+1152\)
\(=900\)
Giải: (tiếp)
7) \(\left(56.46-25.23\right):23\)
\(=\left(2576-575\right):23\)
\(=2001:23\)
\(=87\)
8) \(\left(28.54+56.36\right):21:2\)
\(=\left(1512+2016\right):21:2\)
\(=3528:21:2\)
\(=84\)
9) \(\left(76.34-19.64\right):\left(38.9\right)\)
\(=\left(2584-1216\right):342\)
\(=1368:342\)
\(=4\)
10) \(\left(2+4+6+...+100\right).\left(36.333-108.111\right)\)
\(=\left(2+4+6+...+100\right).\left(11988-11988\right)\)
\(=\left(2+4+6+...+100\right).0\)
\(=0\)
11) \(\left(5.4^{11}-3.16^5\right):4^{10}\)
\(=5.4^{11}:4^{10}-3.16^5:4^{10}\)
\(=5.4-3.1\)
\(=20-3\)
\(=17\)
12) \(7256.4375-725:3650+4375.7255\)
\(=4375.\left(7256+7255\right)-\dfrac{29}{146}\)
\(=4375.14511-\dfrac{29}{146}\)
\(=63485624,8\)
Câu 12 ko chắc!
\(132+[116-\left(132-128\right)^2]\)
\(=132+[116-4^2]\)
\(=132+[116-16]\)
\(=132+100\)
\(=232\)
\(=\left(152-148\right)+\left(144-140\right)+\left(136-132\right)+\left(128-124\right)+\left(120-116\right)+\left(112-108\right)+\left(104-100\right)\\ =4+4+4+4+4+4+4=28\)
1) 22.25.17.+5.20.27+102.56
=4.25.17+5.20.27+100.56
=100.17+100.27+100.56
=100(17+27+56)
=100.100
=10000
2) 132-[116-(132-1282)]
=132-[116-(132-16384)]
=132-[116-(-16252)]
=132-(116+16252)
=132-16368
=-16236
3) 4.52-81:32
=4.25-34:32
=100-34-2
=100-32
=100-9
=91
Bài 1 :
Theo bài ra, ta có :
a chia 15 dư 8 => a=15k+8=>a+22=15k+30=15(k+2) chia hết cho 15 => a+22 chia hết cho 15 ;
a chia 35 dư 13 => a=35k+13=> a+22=35k+35=35(k+1) chia hết cho 35=> a+22 chia hết cho 35
và a là STN nhỏ hơn 500
=> a+22 \(\in\)BC(15.35) và a<500 hay a+22< 522
Có: 15= 3.5
35=5.7
=>BCNN(15,35)=3.5.7=105
=>BC(15,35)=B(105)={0;105;210;315;420;525;..}
=> a+22=420
=>a=398 thỏa mãn điều kiện của đề bài
Vậy a=398
Mik mệt wá nên chỉ làm đến đây thôi, mai mik giải nốt cho. mik nha !!!!!
132-[116-(132-128)^2)]
132-[116-4^2]
132[116-16]
132-100
32