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Mình sửa lại để nha \(\left(125^7-625^5-25^9\right)\div99\)
Ta có \(\frac{\left(5^3\right)^7-\left(5^4\right)^6-\left(5^2\right)^9}{99}\)
\(=\frac{5^{21}-5^{20}-5^{18}}{99}\)
\(=\frac{5^{18}.\left(5^3-5^2-1\right)}{99}\)
\(=\frac{5^{18}.99}{99}\)
\(=5^{18}\)
\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\)
= \(1+\frac{3.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}{4.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}\)
= \(1+\frac{3}{4}\)
= \(\frac{4}{4}+\frac{3}{4}\)
= \(\frac{7}{4}\)
HỌC TỐT
`a, = 5^3 xx 3^3 = 15^3`
`b, = 12^3 xx 4^3 = 48^3`
`c, = 625^3 xx 8^3 = 5000^3`
`d, = 625 ^3 xx 125^3 = 78125^3`
`e, = 5^20 : 5^14 = 5^6`
1,\(125\cdot27=5^3\cdot3^3=\left(5\cdot3\right)^3=15^3\)
2, \(12^3\cdot64=12^3\cdot4^3=\left(12\cdot4\right)^3=48^3\)
3, \(25^6\cdot8^3=\left(5^2\right)^6\cdot\left(2^3\right)^3=5^8\cdot2^9\)
4, \(25^6\cdot125^3=\left(5^2\right)^3\cdot\left(5^3\right)^3=5^6\cdot5^9=5^{15}\)
5,\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)
1, \(81\cdot27^3\cdot243^5=3^4\cdot3^9\cdot3^{25}=3^{38}\)
2,\(25^4\cdot125^3\cdot625^7=5^8\cdot5^9\cdot5^{28}=5^{45}\)
3,
\(16^3\cdot8^9\cdot64^5\cdot1024=2^{12}\cdot2^{27}\cdot2^{30}\cdot2^{10}=2^{79}\)