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\(\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+\frac{1}{40}+\frac{1}{60}+\frac{1}{84}
\)
\(=\frac{210}{840}+\frac{70}{840}+\frac{35}{840}+\frac{21}{840}+\frac{14}{840}+\frac{10}{840}\)
\(=\frac{210+70+35+21+14+10}{840}\)
\(=\frac{360}{840}\)
\(=\frac{3}{7}\)
\(\frac{1}{2011x}+\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{2010.2011}=1\)
\(\Rightarrow\frac{1}{2011x}+\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2010.2011}=1\)
\(\Rightarrow\frac{1}{2011x}+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2010}-\frac{1}{2011}=1\)
\(\Rightarrow\frac{1}{2011x}+1-1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2010}-\frac{1}{2011}=0\)
\(\Rightarrow\frac{1}{2011x}-\frac{1}{2011}=0\)
\(\Rightarrow2011x-2011=0\Rightarrow x=1\)
\(\frac{1}{2011x}+\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+....+\frac{1}{2010x2011}=1\)
=> \(\frac{1}{2011x}+\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+........+\frac{1}{2010x2011}\)= 1
=> \(\frac{1}{2011x}+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}+...........+\frac{1}{2010}-\frac{1}{2011}\)= 1
=> \(\frac{1}{2011x}+1-1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-...............+\frac{1}{2010}-\frac{1}{2011}\)= 0
=> \(\frac{1}{2011x}-\frac{1}{2011}=0\)
=> 2011x - 2011 = 0
=> x = ( 0 + 2011 ) : 2011 = 2011 : 2011 = 1
\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
\(=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+...+\frac{1}{13\cdot15}\)
\(=\frac{1}{2}\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{13\cdot15}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{15}\right)\)
\(=\frac{1}{2}\cdot\frac{14}{15}\)
\(=\frac{7}{15}\)
Sửa đề chút nhé:
\(\left(1+3+5+7+...+2009+2011\right).\left(125125.127-127127.125\right)\)
\(=\left(1+3+5+7+...+2009+2011\right).\left(125.1001.127-127.1001.125\right)\)
\(=\left(1+3+5+7+...+2009+2011\right).0\)
\(=0\)
Ý b tham khảo bài bạn nguyen thi thuy linh nhé
1 (3y - 0,8 ) : y + 14,5 = 15
( 3y - 0,8 ) : y = 0,5
3y : y - 0,8 : y = 0,5
3 - 0,8 : y = 0,5
0,8 : y = 2,5
y = 0,8 : 2,5
y = 0,32
Ta có :
Tử số = 2012 x 14 + 1997 + 2010 x 2011
= ( 2011 + 1 ) x 14 + 1997 + 2010 x 2011
= 2011 x 14 + 1 x 14 + 1997 + 2010 x 2011
= 2011 x 14 + 14 + 1997 + 2010 x 2011
= ( 2011 x 14 ) + ( 14 + 1997 ) + ( 2010 x 2011 )
= 2011 x 14 + 2011 + 2010 x 2011
= 2011 x ( 14 + 1 + 2010 )
= 2011 x 2025
Mẫu số = 2011 x 5 + 2011 x 1008 + 1012 x 2011
= 2011 x ( 5 + 1008 + 1012 )
= 2011 x 2025
=> \(A=\frac{2011\times2025}{2011\times2025}=1\)
a) 3 3/4 . x = 1 1/2
<=> 15/4 . x = 3/2
<=> x = 3/4 . 4/15
<=> x = 1/5
Vậy x = 1/5
b) 1 1/4 x + 1 1/2 = 1 1/4
<=> 5/4 . x + 3/2 = 5/4
<=> 5/4 . x = 5/4 - 3/2
<=> 5/4 . x = -1/4
<=> x = -1/4 . 4/5
<=> x = -1/5
Vậy x = -1/5
c) ( 3 1/3 - 1 1/2 x ) : 5/6 = 1 1/2
<=> ( 10/3 - 3/2 x ) : 5/6 = 3/2
<=> 10/3 - 3/2 x = 3/2 . 5/6
<=> 10/3 - 3/2 x = 5/4
<=> 3/2 . x = 10/3 - 5/4
<=> 3/2 . x = 25/12
<=> x = 25/12 . 2/3
<=> x = 25/18
Vậy x = 25/18
d) ( 3/7 x - 1 ) : 4 = -1/28
<=> 3/7 . x - 1 = -1/28 . 1/4
<=> 3/7 . x - 1 = -1/112
<=> 3/7 . x = -1/112 + 1
<=> 3/7 . x = 111/112
<=> x = 111/112 . 7/3
<=> x = 37/16
Vậy x = 37/16
e) | x - 3/4 | = 1
<=> x - 3/4 = 1
hoặc x - 3/4 = -1
<=> x = 1 + 3/4
hoặc x = -1 + 3/4
<=> x = 7/4
hoặc x = -1/4
Vậy x = 7/4 ; x = -1/4
f) | 2/3 . x + 1/3 | = 5/6
<=> 2/3 . x + 1/3 = 5/6
hoặc 2/3 . x + 1/3 = -5/6
<=> 2/3 . x = 5/6 - 1/3
hoặc 2/3 . x = -5/6 - 1/3
<=> 2/3 . x = 1/2
hoặc 2/3 . x = -7/6
<=> x = 1/2 . 3/2
hoặc x = -7/6 . 3/2
<=> x = 3/4
hoặc x = -7/4
Vậy x = 3/4 ; x = -7/4
\(\dfrac{1}{2011}.x=\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)\)
\(\dfrac{1}{2011}.x=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}\)
\(\dfrac{1}{2011}.x=\dfrac{1}{4}\)
=> \(x=\dfrac{1}{4}:\dfrac{1}{2011}\)
=> \(x=\dfrac{2011}{4}\)