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1.Tìm x,y thuộc Z biết
1,x+(-45)=(-62)+17
2,x+29=|-43|+(-43)
3,43+(9-21)=317-(x+317)
4,|x|+|-4|=7
5,|x|+|y|=0
6,(15-x)+(x-12)=7-(-5+x)
7,(2x-5)^2=9
8,(2x+6).(x-9)=0
9,(1-3x)^3=-8
10,3x+4y-xy=15
3.Tìm x+y biết
|x|=5
|x|=7
4.Tìm giá trị lớn nhất hoặc nhỏ nhất của các biểu thức sau (x,y thuộc Z)
A=|x-3|+1
B=3-|x+1|
C=|x-5|+|y+3|+7
1) -5x - (-3) = 13
\(\Rightarrow-5x+3=13\)
\(\Rightarrow-5x=10\)
\(\Rightarrow x=-2\)
Vậy: \(x=-2\)
2) 15 - ( x - 7) = -21
\(\Rightarrow15-x+7=-21\)
\(\Rightarrow15+7-x=-21\)
\(\Rightarrow22-x=-21\)
\(\Rightarrow x=-22-21=-43\)
Vậy: \(x=-43\)
3) 45 - ( x - 9) = -35
\(\Rightarrow45-x+9=-35\)
\(\Rightarrow45+9-x=-35\)
\(\Rightarrow54-x=-35\)
\(\Rightarrow x=-54-35=-89\)
Vậy: \(x=-89\)
4)/x-2/=3\(\Rightarrow\)ta có 2 t/h:
t/h1: x-2=3\(\Rightarrow\)x=2+3=5
t/h2: x-2=-3\(\Rightarrow\)x=2+(-3)=-1
Vậy x=5 hoặc -1
a) \(\left(x+5\right)\left(3x-12\right)>0\)
\(\left(x+5\right).3.\left(x-4\right)>0\)
\(\Rightarrow\hept{\begin{cases}x+5>0\\x-4>0\end{cases}}\) hoặc \(\hept{\begin{cases}x+5< 0\\x-4< 0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x>-5\\x>4\end{cases}}\) hoặc \(\hept{\begin{cases}x< -5\\x< 4\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x>4\\x< -5\end{cases}}\)
vậy...
a,|x-2|=3
=>x-2= 3 hoặc -3
-với x -2 =3 =>x=1
-với x-2 = -3 =>x= -1
Vậy x ∈ {1;-1}
b, |x-3|-7=13
=>|x-3|=13-7=6
=>x-3=6 hoặc -6
-với x-3 =6 => x=9
-với x-3= -6 => x=-3
Vậy x ∈ {9;-3}
c,72-3.|x+1|=9
=>3.|x+1|=72-9=63
=>|x+1|=63:3=21
=>x+1 = 21 hoặc -21
-với x+1 = 21 => x=20
-với x+1 = -21 => x= -22
Vậy x ∈ {20;-21}
d,17-(43-|x|)=45
=>43-|x|=17-45= -28
=>|x|=43-(-28)=71
=> x =71 hoăc -71
Vậy x ∈ {71;-71}
f, 3|x-1|-5=7
=>3|x-1|=7+5=12
=>|x-1|=12:3=4
=>x-1=4 hoặc -4
-với x-1=4 =>x=5
-với x-1=-4=>x=-3
Vậy x ∈ {5;-3}
CHÚC BẠN LÀM BÀI TÔT NHA
a) \(\left|x-2\right|=3\\ \Rightarrow\left[{}\begin{matrix}x-2=3\\x-2=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3+2\\x=-3+2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)Vậy \(x\in\left\{5;-1\right\}\)
b) \(\left|x-3\right|-7=13\\ \left|x-3\right|=13+7\\ \left|x-3\right|=20\\ \Rightarrow\left[{}\begin{matrix}x-3=20\\x-3=-20\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=20+3\\x=-20+3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=23\\x=-17\end{matrix}\right.\)
Vậy \(x\in\left\{23;-17\right\}\)
c) \(72-3\cdot\left|x+1\right|=9\\ 3\left|x+1\right|=72-9\\ 3\left|x+1\right|=63\\ \Rightarrow\left[{}\begin{matrix}x+1=63\\x+1=-63\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=63-1\\x=-63-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=62\\x=-64\end{matrix}\right.\)
Vậy \(x\in\left\{62;-64\right\}\)
d) \(17-\left(43-\left|x\right|\right)=45\\ 43-\left|x\right|=17-45\\ 43-\left|x\right|=-28\\ \left|x\right|=43-\left(-28\right)\\ \left|x\right|=43+28\\ \left|x\right|=71\\ \Rightarrow x\in\left\{71;-71\right\}\)Vậy \(x\in\left\{71;-71\right\}\)
e) \(\left|x\right|< 3\\ \left|x\right|\in\left\{0;1;2\right\}\\ \Rightarrow x\in\left\{0;\pm1;\pm2\right\}\)Vậy \(x\in\left\{0;\pm1;\pm2\right\}\)
f) \(3\left|x-1\right|-5=7\\ 3\left|x-1\right|=7+5\\ 3\left|x-1\right|=12\\ \left|x-1\right|=12:3\\ \left|x-1\right|=4\\ \Rightarrow\left[{}\begin{matrix}x-1=4\\x-1=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4+1\\x=-4+1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-3\end{matrix}\right.\)
Vậy \(x\in\left\{5;-3\right\}\)
\(a.\dfrac{3}{2}+\dfrac{-1}{3}< \dfrac{x}{6}< \dfrac{1}{9}+\dfrac{31}{18}\)
\(\Leftrightarrow\dfrac{7}{6}< \dfrac{x}{6}< \dfrac{11}{6}\)
\(\Leftrightarrow7< x< 11\)
\(\Leftrightarrow x\in\left\{8;9;10\right\}\)
\(b.\dfrac{-5}{12}+\dfrac{7}{12}+\dfrac{-1}{12}< \dfrac{x}{12}< \dfrac{2}{15}+\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{1}{12}< \dfrac{x}{12}< \dfrac{1}{3}\)
\(\Leftrightarrow\dfrac{1}{12}< \dfrac{x}{12}< \dfrac{4}{12}\)
\(\Leftrightarrow1< x< 4\)
\(\Leftrightarrow x\in\left\{2;3\right\}\)
\(43+\left(9-21\right)=317\left(x+317\right)\)
\(\Rightarrow317-\left(x+317\right)=43+\left(9-21\right)\)
\(\Rightarrow317-\left(x+317\right)=43+\left(-12\right)\)
\(\Rightarrow317-\left(x+317\right)=31\)
\(\Rightarrow x+317=317-31\)
\(\Rightarrow x+317=286\)
\(\Rightarrow x=286-317\)
\(\Rightarrow x=-31\)
Vay x = -31
\(b.\left(15-x\right)+\left(x-12\right)=7-\left(-5+x\right)\)
\(\Rightarrow15-x+x-12=7+5+x\)
\(\Rightarrow15-12=12-x\)
\(\Rightarrow3=12-x\)
\(\Rightarrow12-x=3\)
\(\Rightarrow x=12-3\)
\(\Rightarrow x=9\)
Vay x = 9
....
a) 43+(9-21) = 317-(x+317)
43+(-12) = 317-(x+317)
317-(x+317) = 31
x+317 = 317-31=286
x = 286-317=(-31)
Tạm thời câu b mình chưa nghĩ ra nha.
a. \(\left|x-3\right|-7=13\Leftrightarrow\left|x-3\right|=20\)
TH1: \(x-3=20\Leftrightarrow x=23\)
TH2: \(x-3=-20\Leftrightarrow x=-17\)
b. \(72-3.\left|x+1\right|=9\Leftrightarrow\left|x+1\right|=21\)
TH1: \(x+1=21\Leftrightarrow x=20\)
TH2: \(x+1=-21\Leftrightarrow x=-22\)
c. \(17-\left(43-\left|x\right|\right)=45\Leftrightarrow\left|x\right|=71\)
TH1: \(x=71\)
TH2: \(x=-71\)
d. \(3\left|x-1\right|-5=7\Leftrightarrow\left|x-1\right|=4\)
TH1: \(x-1=4\Leftrightarrow x=5\)
TH2: \(x-1=-4\Leftrightarrow x=-3\)
e. \(-12\left(x-5\right)+7\left(3-x\right)=5\Leftrightarrow-12x+60+21-7x=5\Leftrightarrow-19x=-76\Leftrightarrow x=4\)
a.
\(\left|x-3\right|-7=13\)
\(\left|x-3\right|=13+7\)
\(\left|x-3\right|=20\)
\(x-3=\pm20\)
- \(x-3=20\)
\(x=20+3\)
\(x=23\)
- \(x-3=-20\)
\(x=-20+3\)
\(x=-17\)
Vậy x = 23 hoặc x = - 17.
b.
\(72-3\times\left|x+1\right|=9\)
\(3\times\left|x+1\right|=72-9\)
\(3\times\left|x+1\right|=63\)
\(\left|x+1\right|=63\div3\)
\(\left|x+1\right|=21\)
\(x+1=\pm21\)
- \(x+1=21\)
\(x=21-1\)
\(x=20\)
- \(x+1=-21\)
\(x=-21-1\)
\(x=-22\)
Vậy x = 20 hoặc x = - 22.
c.
\(17-\left(43-\left|x\right|\right)=45\)
\(43-\left|x\right|=17-45\)
\(43-\left|x\right|=-28\)
\(\left|x\right|=43-\left(-28\right)\)
\(\left|x\right|=71\)
\(x=\pm71\)
Vậy x = 71 hoặc x = - 71.
d.
\(3\times\left|x-1\right|-5=7\)
\(3\times\left|x-1\right|=7+5\)
\(3\times\left|x-1\right|=12\)
\(\left|x-1\right|=12\div3\)
\(\left|x-1\right|=4\)
\(x-1=\pm4\)
- \(x-1=4\)
\(x=4+1\)
\(x=5\)
- \(x-1=-4\)
\(x=-4+1\)
\(x=-3\)
Vậy x = 5 hoặc x = - 3.
e.
\(-12\times\left(x-5\right)+7\times\left(3-x\right)=5\)
\(-12\times x+\left(-12\right)\times\left(-5\right)+7\times3-7\times x=5\)
\(-12\times x+60+21-7\times x=5\)
\(-19\times x+81=5\)
\(-19\times x=5-81\)
\(-19\times x=-76\)
\(x=\frac{-76}{-19}\)
\(x=4\)
Chúc bạn học tốt
1. x + (-7) = -20
=> x = -20 - (-7)
=> x = -20 + 7
=> x = -13
Vậy x = -13
2. x + (-15) = 5
=> x = 5 - (-15)
=> x = 5 + 15
=> x = 20
3. (-95) + x = 10
=> x = 10 - (-95)
=> x = 10 + 95
=> x = 105
4. 8+ x = 12
=> x = 12 - 8
=> x = 4
5. x + (-45) = -62 + 17
=> x + (-45) = -45
=> x = -45 - (-45)
=> x = -45 + 45
=> x = 0
6 . x + 29 = |-43| + (-43)
=> x + 29 = 43 + (-43)
=> x + 29 = 0
=> x = 0 - 29
=> x = -29
7 . 43 + (9 - 21) = 317 - (x + 317)
=> 43 + (-12) = 317 - x - 317
=> 31 = 317 - x - 317
=> 317 - x - 317 = 31
=> 317 - x = 31 + 317
=> 317 - x = 348
=> x = 317 - 348
=> x = -31
Mỏi tay quá , bn tự làm nốt nha :)
a)-12(x-5)+7(3-x)=5
-12x-(-60)+21-7x=5
-12x+60+21-7x=5
-12x-7x=5-60-21
-19x=-76
x=-76/-19
x=4. Vậy x=4
ặc, bạn ghi ít ít thôi, ghi thế này nhiều quá