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\(\dfrac{3}{4}.\dfrac{2}{3}-\dfrac{1}{6}.\dfrac{3}{4}-\dfrac{3}{4}.\dfrac{1}{2}\)
= \(\dfrac{3}{4}.\left(\dfrac{2}{3}-\dfrac{1}{6}-\dfrac{1}{2}\right)\)
= \(\dfrac{3}{4}.0\)
= 0
\(\dfrac{3}{4}\cdot\dfrac{2}{3}-\dfrac{1}{6}\cdot\dfrac{3}{4}-\dfrac{3}{4}\cdot\dfrac{1}{2}\)
\(=\dfrac{3}{4}\left(\dfrac{2}{3}-\dfrac{1}{6}-\dfrac{1}{2}\right)\)
\(=\dfrac{3}{4}\cdot\left(\dfrac{4}{6}-\dfrac{1}{6}-\dfrac{3}{6}\right)\)
=0
\(x:\dfrac{3}{4}=1-\dfrac{2}{5}\\ \Rightarrow x\cdot\dfrac{4}{3}=\dfrac{3}{5}\\ \Rightarrow x=\dfrac{3}{5}:\dfrac{4}{3}=\dfrac{9}{20}\)
\(x:\dfrac{3}{4}=1-\dfrac{2}{5}\)
\(\Rightarrow x:\dfrac{3}{4}=\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{3}{5}\times\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{9}{20}\)
Ta có biểu thức :
\(M=\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)\)
a ) Nếu \(m=\frac{1}{2}\) thì \(M=\frac{11}{6}-\frac{5}{6}\div\left(\frac{1}{2}+\frac{3}{10}\right)=\frac{5}{4}\)
b ) Nếu \(M=\frac{5}{3}\) thì
\(\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(1\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(m+\frac{3}{10}=1\div\frac{5}{3}\)
\(m+\frac{3}{10}=\frac{3}{5}\)
\(m=\frac{3}{5}-\frac{3}{10}\)
\(m=\frac{3}{10}\)
\(\frac{3}{4}+\frac{5}{9}:\frac{4}{5}=\frac{3}{4}+\frac{5}{9}\times\frac{5}{4}\)
\(=\frac{3}{4}+\frac{25}{36}=\frac{27}{36}+\frac{25}{36}=\frac{27+25}{36}=\frac{52}{36}=\frac{13}{9}\)
\(\frac{7}{19}\times\frac{4}{7}-\frac{7}{19}\times\frac{3}{7}=\frac{7}{19}\times\left(\frac{4}{7}-\frac{3}{7}\right)\)
\(=\frac{7}{19}\times\frac{1}{7}=\frac{1}{19}\)
hỏi làm j thằng điên
Đề bài sai bạn nhé