Câu hỏi của Hoàng Duy Đạt

Question

$1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0$

💥Hoàng Thị Diệu Thùy 💦 · Accepted Answer

$1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0$$\Rightarrow1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0$$\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1$$\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{53}{3}$$\Rightarrow\frac{43}{8}+x=\frac{53}{3}+\frac{173}{24}$$\Rightarrow\frac{43}{8}+x=\frac{199}{8}$$\Rightarrow x=\frac{199}{8}-\frac{43}{8}$$\Rightarrow x=\frac{156}{8}=\frac{39}{2}$Câu trả lời: $1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0$$\Rightarrow1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0$$\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1$$\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{53}{3}$$\Rightarrow\frac{43}{8}+x=\frac{53}{3}+\frac{173}{24}$$\Rightarrow\frac{43}{8}+x=\frac{199}{8}$$\Rightarrow x=\frac{199}{8}-\frac{43}{8}$$\Rightarrow x=\frac{156}{8}=\frac{39}{2}$

Kim Mingyu · Answer

$1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0$$< =>1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0$$< =>1\left(\frac{43}{8}+x-\frac{173}{24}\right)=0$$< =>\frac{43}{8}+x-\frac{173}{24}=0$$< =>\frac{43}{8}+x=\frac{173}{24}$$< =>x=\frac{173}{24}-\frac{43}{8}$$< =>x=\frac{11}{6}$Câu trả lời: $1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0$$< =>1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0$$< =>1\left(\frac{43}{8}+x-\frac{173}{24}\right)=0$$< =>\frac{43}{8}+x-\frac{173}{24}=0$$< =>\frac{43}{8}+x=\frac{173}{24}$$< =>x=\frac{173}{24}-\frac{43}{8}$$< =>x=\frac{11}{6}$

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