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\(a,\left(\frac{5}{7}+\frac{9}{7}\right)x\frac{21}{28}\)
\(C1:=\frac{14}{7}x\frac{21}{28}=\frac{3}{2}\)
\(C2:=\frac{5}{7}x\frac{21}{28}+\frac{9}{7}x\frac{21}{28}=\frac{15}{28}+\frac{27}{28}=\frac{3}{2}\)
\(b,\frac{4}{5}x\frac{13}{14}+\frac{13}{14}x\frac{1}{5}\)
\(C1:=\frac{26}{35}+\frac{13}{70}=\frac{13}{14}\)
\(C2:=\frac{13}{14}x\left(\frac{4}{5}+\frac{1}{5}\right)=\frac{13}{14}x1=\frac{13}{14}\)
học tốt ~~~
\(a.\frac{4}{3}-\frac{3}{2}:X=\frac{1}{6}\)
\(\frac{3}{2}:X=\frac{4}{3}-\frac{1}{6}\)
\(\frac{3}{2}:X=\frac{8}{6}-\frac{1}{6}\)
\(\frac{3}{2}:X=\frac{7}{6}\)
\(X=\frac{3}{2}:\frac{7}{6}\)
\(X=\frac{3}{2}\times\frac{6}{7}\)
\(X=\frac{9}{7}\)
\(b.\left(X+\frac{2}{3}\right):\frac{1}{3}=\frac{41}{3}\)
\(X-\frac{2}{3}=\frac{41}{3}.\frac{1}{3}\)
\(X-\frac{2}{3}=\frac{41}{9}\)
\(X=\frac{41}{9}+\frac{2}{3}\)
\(X=\frac{41}{9}+\frac{6}{9}\)
\(X=\frac{47}{9}\)
\(\left(2.8x-32\right):\frac{2}{3}=90\)
\(2.8\cdot x-32=90\cdot\frac{2}{3}\)
\(\frac{14}{5}x-32=60\)
\(\frac{14}{5}x=60+32\)
\(\frac{14}{5}x=92\)
\(x=\frac{230}{7}\)
B , c , d tương tự
Bài 1:
a) \(\frac{3}{4}×\frac{4}{7}=\frac{3×4}{4×7}=\frac{3}{7}\)
\(\frac{12}{35}:\frac{3}{5}=\frac{12}{35}×\frac{5}{3}=\frac{12×5}{35×3}=\frac{4.}{7}\)
\(\frac{4}{7}×\frac{3}{5}=\frac{4×3}{7×5}=\frac{12}{35}\)
b) \(\frac{13}{11}×2=\frac{13×2}{11}=\frac{26}{11}\)
\(\frac{26}{11}:\frac{13}{11}=\frac{26}{11}×\frac{11}{13}=\frac{26×11}{11×13}=\frac{2×1}{1×1}=\frac{2}{1}=2\)
\(\frac{26}{11}:2=\frac{26}{11}×\frac{1}{2}=\frac{26×1}{11×2}=\frac{13×1}{11×1}=\frac{13}{11}\)
\(2×\frac{13}{11}=\frac{2×13}{11}=\frac{26}{11}\)
k giúp mik ✅
Bài 2:
a) \(\frac{4}{7}×\:x\:=\frac{1}{3}\)
\(\Rightarrow\)x = \(\frac{1}{3}-\frac{4}{7}\)
\(\Rightarrow\)x = \(\frac{7}{21}-\frac{4}{21}\)
\(\Rightarrow\)x = \(\frac{3}{21}=\frac{1}{7}\)
b) x : \(\frac{2}{5}=\frac{2}{9}\)
\(\Rightarrow\)x = \(\frac{2}{9}×\frac{2}{5}\)
\(\Rightarrow\)x = \(\frac{4}{45}\)
\(\frac{1}{2}:\frac{3}{2}:\frac{5}{4}:\frac{6}{5}:\frac{7}{6}:\frac{8}{7}\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{4}{5}\cdot\frac{5}{6}\cdot\frac{6}{7}\cdot\frac{7}{8}\)
\(=\frac{1\cdot\left(2\cdot5\cdot6\cdot7\right)}{8\cdot3\cdot\left(2\cdot5\cdot6\cdot7\right)}\)
\(=\frac{1}{24}\)
\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot\frac{5}{6}\cdot\frac{6}{7}\cdot\frac{7}{8}\cdot\frac{8}{9}\cdot\frac{9}{10}\)
\(=\frac{1\cdot\left(2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9\right)}{\left(2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9\right)\cdot10}\)
\(=\frac{1}{10}\)
Ta có: 272727x28 - 282828x27 = 27x10101x28 - 28x10101x27 = 0
Vậy, phép tính đã cho bằng 0
4) \(\frac{29x101-101}{2x19x101+4x101}\)
= \(\frac{\left(29-1\right)x101}{\left(38-4\right)x101}\)
=\(\frac{28}{34}=\frac{14}{17}\)
5) \(\left(\frac{2}{7}+\frac{11}{7}+\frac{1}{7}\right)-\frac{3}{8}-\frac{5}{8}+\frac{1}{3}\)
= \(\frac{14}{7}-\frac{8}{8}+\frac{1}{3}\)
= \(2-1+\frac{1}{3}=\frac{4}{3}\)
Nhớ tk cho mình nhé
1\(\frac{423133x846267+423134}{423133x846267+423134}=1\))
\(\frac{\left(423133+1\right)x846267-423133}{423133x846267+423134}\)
=\(\frac{423133x846267+846267-423133}{423133x846267+423134}\)
= \(\frac{423133x846267+423134}{423133x846267+423134}\)
= 1
Nhớ tk cho mình nhé (các câu sau làm riêng cho đỡ dài
\(\left(1-\frac{2}{5}\right)\times\left(1-\frac{2}{7}\right)\times\left(1-\frac{2}{9}\right)\times\left(1-\frac{2}{11}\right)\times\left(1-\frac{2}{13}\right)\)
\(=\frac{3}{5}\times\frac{5}{7}\times\frac{7}{9}\times\frac{9}{11}\times\frac{11}{13}=\frac{3}{13}\)