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Đặt \(A=25\times4-0,5\times40\times5\times0,2\times20\times0,25\)
\(\Leftrightarrow A=100-\left(0,5\times0,2\right)\times\left(40\times0,25\right)\times\left(5\times20\right)\)
\(\Leftrightarrow A=100-0,1\times10\times100\)
\(\Leftrightarrow A=100-100=0\)
Vậy theo đề bài, ta có :
\(\frac{25\times4-0,5\times40\times5\times0,2\times20\times0,25}{1+2+8+...+128+256}=\frac{0}{1+2+8+...+128+256}=0\)
Vậy ..................
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\(\frac{25\times4-0,5\times40\times5\times0,2\times20\times0,25}{1+2+4+8+...+128+256}\)
\(=\frac{100-\left(20\times5\right)\times\left(0,5\times0,2\times0,25\times40\right)}{1+2+4+8+...+128+256}\)
\(=\frac{100-100\times\left(\frac{1}{40}\times40\right)}{1+2+4+8+...+128+256}\)
\(=\frac{100\times\left(1-1\right)}{1+2+4+8+...+128+256}\)
\(=0\)
\(\frac{25\times4-0,5\times40\times5\times0,2\times20\times0,25}{1+2+4+8+...128+256}\)
\(=\frac{100-\left(0,5\times20\right)\times\left(40\times0,25\right)\times\left(5\times0,2\right)}{1+2+4+8+...+128+256}\)
\(=\frac{100-10\times10\times1}{1+2+4+8+...+128+256}\)
\(=\frac{100-100}{1+2+4+8+...+128+256}\)
\(=\frac{0}{1+2+4+8+...+128+256}=0\)
thay b=2/3, ta có: A=1/3x(2/3-2/5):7/5=4/63
thay A= 3/7, ta có: 3/7=1/3x(b-2/5):7/5
1/3x(b-2/5):7/5=3/7
1/3x(b-2/5) =3/7x7/5
1/3x(b-2/5) = 3/5
b-2/5 = 3/5:1/3
b-2/5 = 9/5
b = 9/5+2/5
b = 11/5
2:
=1-1+1-1=0
3:
a: =>34*(100+1)/2:a=17
=>a=101
b: =>5/3(x-1/2)=5/4
=>x-1/2=5/4:5/3=3/4
=>x=5/4
1a, \(\dfrac{2005}{2001}\) = 1+\(\dfrac{4}{2001}\); \(\dfrac{2009}{2005}\)=1+\(\dfrac{4}{2005}\)vì\(\dfrac{4}{2001}\)>\(\dfrac{4}{2005}\)nên\(\dfrac{2005}{2001}\)>\(\dfrac{2009}{2005}\)
1b,\(\dfrac{1313}{1515}\)=\(\dfrac{1313:101}{1515:101}\)= \(\dfrac{13}{15}\); \(\dfrac{131313}{151515}\)=\(\dfrac{131313:10101}{151515:10101}\)=\(\dfrac{13}{15}\)
Vậy \(\dfrac{13}{15}\)=\(\dfrac{1313}{1515}\)=\(\dfrac{131313}{151515}\)
- Tính giá trị biểu thức:
a) (2/5 x 25/29) + (3/5 x 25/29)
= (50/145) + (75/145)
= 125/145
b) (5/2 x 3/7) - (3/14 : 6/7)
= 15/14 - (3/14 x 7/6)
= 15/14 - 1/2
= (30/28) - (14/28)
= 16/28
= 4/7
c) (15/4 : 5/12) - (6/5 : 11/15)
= (15/4 x 12/5) - (6/5 x 15/11)
= 180/20 - 90/55
= 9 - 18/11
= (99/11) - (18/11)
= 81/11
= 7 4/11
- Tính giá trị biểu thức:
a) (2/3) + (20/21 x 3/2 x 7/5)
= 2/3 + (60/210)
= 2/3 + 2/7
= (14/21) + (6/21)
= 20/21
b) (5/17 x 21/32 x 47/24 x 0)
= 0
c) (11/3 x 26/7) - (26/7 x 8/3)
= (286/21) - (208/21)
= 78/21
= 3 9/21
= 3 3/7
- Tìm x:
a) (25/8) : x = 5/16
=> (25/8) x (16/5) = x
=> 4 = x
b) x + (7/15) = 6/15
=> x = (6/15) - (7/15)
=> x = -1/15
c) x : (28/49) = 7/12
=> x x (49/28) = 7/12
=> x = (7/12) x (28/49)
=> x = 1/2
- Tìm x:
a) 6 x x = (5/8) : (3/4)
=> 6x = (5/8) x (4/3)
=> 6x = 20/24
=> 6x = 5/6
=> x = (5/6) / 6
=> x = 5/36
câu,b,không,đủ,thông,tin,nhan,bạn.
b1:
a,\(\frac{3}{8}:\frac{5}{4}\)=\(\frac{3}{8}.\frac{4}{5}=\frac{12}{45}=\frac{4}{15}\)
b,\(\frac{4}{7}:\frac{2}{13}=\frac{4}{7}.\frac{13}{2}=\frac{26}{7}\)
b2:
a,25:0,1=250 25x10=250 42:0,01=4200 42x100=4200 72:0,1=720 83:0,01=8300
b,13:0,25=52 13x4=52 42:0,5=84 42x2=84 75:0,5=150 125:0,25=500