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Dấu \("."\) là dấu nhân
\(0,7.y+\frac{3}{10}.y=6,3\)
\(\Rightarrow0,7.y+0,3.y=6,3\)
\(\Rightarrow\left(0,7+0,3\right).y=6,3\)
\(\Rightarrow1.y=6,3\)
\(\Rightarrow y=6,3:1\)
\(\Rightarrow y=6,3\)
Vậy \(y=6,3\)
Chúc bạn học tốt !!!
\((2,5\cdot x+2017)\cdot2018=(7,5+2017)\cdot2018\)
\(\Rightarrow(2,5\cdot x+2017)\cdot2018=4085441\)
\(\Rightarrow2,5\cdot x+2017=2024,5\)
\(\Rightarrow2,5x=7,5\)
\(\Rightarrow x=7,5:2,5=3\)
\(3\frac{1}{5}+\frac{2}{5}\left[x+\frac{1}{3}\right]=\frac{21}{5}\)
\(\Rightarrow\frac{16}{5}+\frac{2}{5}\left[x+\frac{1}{3}\right]=\frac{21}{5}\)
\(\Rightarrow\frac{2}{5}\left[x+\frac{1}{3}\right]=\frac{21}{5}-\frac{16}{5}\)
\(\Rightarrow\frac{2}{5}\left[x+\frac{1}{3}\right]=1\)
\(\Rightarrow x+\frac{1}{3}=\frac{5}{2}\)
\(\Rightarrow x=\frac{13}{6}\)
\(x-\frac{3}{4}=6\cdot\frac{3}{8}\)
\(x-\frac{3}{4}=\frac{9}{4}\)
\(x=\frac{9}{4}+\frac{3}{4}\)
\(x=\frac{12}{4}=3\)
\(\frac{7}{8}\cdot x=3-\frac{1}{2}\)
\(\frac{7}{8}\cdot x=\frac{5}{2}\)
\(x=\frac{7}{8}:\frac{5}{2}\)
\(x=\frac{7}{20}\)
\(x+\frac{1}{2}\cdot\frac{1}{3}=\frac{3}{4}\)
\(x+\frac{1}{6}=\frac{3}{4}\)
\(x=\frac{3}{4}-\frac{1}{6}\)
\(x=\frac{7}{12}\)
0,7 * y + 3/10 * y = 6,3
0,7 * y + 0,3 * y = 6,3
y * [0,7+0,3] =6,3
y * 1 =6,3
y = 6,3 :1
y=6,3
0,7 x y + \(\frac{3}{10}\)x y = 6,3
( 0, 7 + \(\frac{3}{10}\)) x y = 6,3
1 x y = 6,3