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a: \(\Leftrightarrow3^x\cdot\left(\dfrac{2}{3}\cdot3-7\right)=405\)
\(\Leftrightarrow3^x=-81\)(vô lý)
b: \(\left(0,4x-1,3\right)^2=5,29\)
=>0,4x-1,3=2,3 hoặc 0,4x-1,3=-2,3
=>0,4x=3,6 hoặc 0,4x=-1
=>x=9 hoặc x=-2,5
c: \(5\cdot2^{x+1}\cdot2^{-2}-2^x=284\)
\(\Leftrightarrow2^x\cdot5\cdot2\cdot2^{-2}-2^x=284\)
\(\Leftrightarrow2^x\cdot\left(\dfrac{5}{2}-1\right)=284\)
\(\Leftrightarrow2^x=\dfrac{568}{3}\)(vô lý)
d: \(\Leftrightarrow4^x\left(1+4^3\right)=4160\)
\(\Leftrightarrow4^x=64\)
hay x=3
a/ \(\frac{2}{3}.3^{x+1}-7.3^x=405\)
<=> 2.3x-7.3x=-405
<=> 5.3x=405
<=> 3x=81 = 34
=> x=4
b/ (0,4x-1,3)2=5,29=(2,3)2
=> \(\hept{\begin{cases}0,4x-1,3=2,3\\0,4x-1,3=-2,3\end{cases}}\)=> \(\hept{\begin{cases}x=9\\x=-\frac{5}{2}\end{cases}}\)
c/ 5.2x+1.2-2-2x=384
<=> 5.2x-1-2.2x-1=384
<=> 3.2x-1=384
<=> 2x-1=128=27
=> x-1=7 => x=8
d/ 3x+2.5y=45x
<=> 3x+2.5y=32x.5x
=> \(\hept{\begin{cases}x+2=2x\\x=y\end{cases}}\)=> x=y=2
B)|2x-1|=8
Chia lam hai trường hợp
2x-1=8hoac. 2x-1=-8
2x=8+1 2x=-8+1
2x=9. 2x=-9
x=9:2. X=-9:2
. X=-4,5
x=4,5
x +30%x=-1,3
x(1+\(\frac{30}{100}\))=-1,3
x.\(\frac{130}{100}\)=-\(\frac{130}{100}\)
x=-\(\frac{130}{100}\):\(\frac{130}{100}\)=-1
theo mình 30 còn rút gọn được nữa\(\dfrac{30}{100}=\dfrac{3}{10}\)
a, y + 30%y = -1,3
1.y + 30/100y = -13/10
1.y + 3/10y = -13/10
(1 + 3/10). y = -13/10
13/10 .y = -13/10
y = -13/10 : 13/10
y = -13/10 . 10/13
y = -1
b, y - 25%y = 1/2
1.y - 25/100.y = 1/2
1.y - 1/4.y = 1/2
(1 - 1/4) y = 1/2
3/4 .y = 1/2
y = 1/2 : 3/4
y = 1/2 . 4/3
y = 2/3
câu c mik chưa nghĩ ra
câu1
\(x+30\%=-1,3\)
\(x+\frac{3}{10}=\frac{-13}{10}\)
\(x=\frac{-13}{10}-\frac{3}{10}\)
\(x=\frac{-10}{10}=-1\)
Bài 2: Theo đầu bài ta có:
a) \(137^{15}\)
\(=\left(137^4\right)^3\cdot137^3\)
\(=\left(...1\right)^3\cdot\left(...3\right)\)
\(=\left(...1\right)\cdot\left(...3\right)\)
\(=\left(...3\right)\)
b) \(234^{44}\)
\(=\left(234^2\right)^{22}\)
\(=\left(...6\right)^{22}\)
\(=\left(...6\right)\)
Bài 1: Theo đầu bài ta có:
1) \(3^{20}:3^{15}\cdot2^7:2^6:3^3\)
\(=\left(3^{20}:3^{15}:3^3\right)\cdot\left(2^7:2^6\right)\)
\(=3^2\cdot2^1\)
\(=9\cdot2\)
\(=18\)
2) \(4^2\cdot3^5:12^2:3^3\)
\(=\left(4^2:12^2\right)\cdot\left(3^5:3^3\right)\)
\(=\left(\frac{4}{12}\right)^2\cdot3^2\)
\(=\left(\frac{1}{3}\cdot3\right)^2\)
\(=1^2\)
\(=1\)
1,1/3+1/2:X= -4
1/2:X= -4-1/3
1/2:X= -13/3
X=1/2 : -13/3
X= -3/26
(0,4x - 1,3 )2 = 5,29 = (2,3)2
=> 0,4x - 1,3 = 2,3
=> 0,4x = 2,3 +1,3 = =3,6
=> x = \(\frac{3,6}{0,4}=9\)
\(\left(0,4x-1,3\right)^2=5,29\)
\(\left(0,4x-1,3\right)=\sqrt{5,29}\)
\(\left(0,4x-1,3\right)=2,3\)
\(0,4x=2,3+1,3\)
\(0,4x=3,6\)
\(x=3,6:0,4\)
\(x=9\)