Mọi người giúp mik bài IV ạ
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IV
1 moon
2 when
3 for
4 from
5 living
6 understands
7 hungry
8 developes
VI
1 is written
2 is folded
3 is put
4 is sent
5 is collected
6 is sorted
7 is taken
8 is delivered
4.2:
a: x^2-x+1=x^2-x+1/4+3/4
=(x-1/2)^2+3/4>=3/4>0 với mọi x
=>x^2-x+1 ko có nghiệm
b: 3x-x^2-4
=-(x^2-3x+4)
=-(x^2-3x+9/4+7/4)
=-(x-3/2)^2-7/4<=-7/4<0 với mọi x
=>3x-x^2-4 ko có nghiệm
5:
a: x^2+y^2=25
x^2-y^2=7
=>x^2=(25+7)/2=16 và y^2=16-7=9
x^4+y^4=(x^2)^2+(y^2)^2
=16^2+9^2
=256+81
=337
b: x^2+y^2=(x+y)^2-2xy
=1^2-2*(-6)
=1+12=13
x^3+y^3=(x+y)^3-3xy(x+y)
=1^3-3*1*(-6)
=1+18=19
4*cos(pi/6-a)*sin(pi/3-a)
=4*(cospi/6*cosa+sinpi/6*sina)*(sinpi/3*cosa-sina*cospi/3)
=4*(căn 3/2*cosa+1/2*sina)*(căn 3/2*cosa-1/2*sina)
=4*(3/4*cos^2a-1/4*sin^2a)
=3cos^2a-sin^2a
=3(1-sin^2a)-sin^2a
=3-4sin^2a
=>m=3; n=-4
m^2-n^2=-7
Ta có:
\(\dfrac{1}{cos^2x-sin^2x}+\dfrac{2tanx}{1-tan^2x}=\dfrac{1}{cos2x}+tan2x=\dfrac{1}{cos2x}+\dfrac{sin2x}{cos2x}=\dfrac{1+sin2x}{cos2x}=\dfrac{cos2x}{1-sin2x}\)
\(\Rightarrow P=a+b=2+1=3\)
Bài 2:
a) \(\left(x^3+5x^2-2x+1\right)\left(x-7\right)\\ =x^4+5x^3-2x^2+x-7x^3-35x^2+14x-7\\ =x^4-2x^3-37x^2+15x\)
b) \(\left(2x^2-3xy+y^2\right)\left(x+y\right)\\ =2x^3-3x^2y+3xy^2+2x^2y-3xy^2+y^3\\ =2x^3+y^3-x^2y\)
c) \(x\left(1-3x\right)\left(4-3x\right)=x\left(4-12x-3x+9x^2\right)=4x-15x^2+9x^3\)
d)\(\left(x-1\right)\left(x+2\right)\left(x-3\right)=\left(x^2+x-2\right)\left(x-3\right)\\ =x^3+x^2-2x-3x^2-3x+6\\ =x^3-2x^2-5x+6\)
Bài 2:
a: Ta có: \(\left(x^3+5x^2-2x+1\right)\left(x-7\right)\)
\(=x^4-7x^3+5x^3-35x^2-2x^2+14x+x-7\)
\(=x^4-2x^3-38x^2+15x-7\)
b: Ta có: \(\left(2x^2-3xy+y^2\right)\left(x+y\right)\)
\(=2x^3+2x^2y-3x^2y-3xy^2+xy^2+y^3\)
\(=2x^3-x^2y-2xy^2+y^3\)
Câu 1
1 C
2 B
3 C
4 A
5 B
6 C
Câu 3
1 with
2 was
3 but
4 island
5 went
6 buy
7 for
8 had
9 took
10 went
1 They had a trip to HLB
2 No, it wasn't
3 They went swimming in the afternoon
4 To buy some gifts
5 Yes,they did
Câu 4
1 C
2 D
3 B
4 B
5 A