TÍNH NHANH : B=(1+1/2)+(1+1/3)+(1+1/4)+(1+1/5)+(1+1/6)+(1+1/7)
HELP ME CÀNG NHANH CÀNG TỐT!!!!!!!!!!!!!!!!!!!!!!!! Hạn làm bài 19/5/2020
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1,
\(\left(\frac{1}{2}+1\right)\left(\frac{1}{3}+1\right)\left(\frac{1}{4}+1\right)...\left(\frac{1}{2017}+1\right)\)
\(=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot...\cdot\frac{2018}{2017}\)
\(=\frac{2018}{2}=1009\)
2,
\(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\left(\frac{1}{4}-1\right)...\left(\frac{1}{2018}-1\right)\)
\(=\frac{-1}{2}\cdot\frac{-2}{3}\cdot\frac{-3}{4}\cdot...\cdot\frac{-2017}{2018}\)
\(=\frac{-1\cdot2017}{2018}=\frac{-2017}{2018}\)
a) C1
\(\dfrac{1}{8}\times\dfrac{5}{6}+\dfrac{5}{6}\times\dfrac{2}{3}=\dfrac{5}{6}\times\left(\dfrac{1}{8}+\dfrac{2}{3}\right)=\dfrac{5}{6}\times\dfrac{19}{24}=\dfrac{95}{144}\)
C2
\(\dfrac{1}{8}\times\dfrac{5}{6}+\dfrac{5}{6}\times\dfrac{2}{3}=\dfrac{5}{48}+\dfrac{10}{18}=\dfrac{95}{144}\)
b) C1
\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{3}{4}\times\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{3}{4}\times\dfrac{9}{10}=\dfrac{27}{40}\)
C2
\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{21}{20}-\dfrac{3}{8}=\dfrac{27}{40}\)
c) C1
\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
C2
\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\left(\dfrac{5}{6}\times\dfrac{2}{3}\right)+\left(\dfrac{5}{8}\times\dfrac{2}{3}\right)=\dfrac{5}{9}+\dfrac{5}{12}=\dfrac{35}{36}\)
\(A=1-3+5-7+......-2019+2021-2023\)
\(A=\left(1-3\right)+\left(5-7\right)+....+\left(2021-2023\right)\)
\(A=-2+\left(-2\right)+....+\left(-2\right)\left(506 cặp\right)\)
\(A=-2.506\)
\(A=-1012\)
*) A=(1-3)+(5-7)+....+(2021-2023)
<=> A=-2+(-2)+...+(-2)
Dãy A có (2023-1):2+1=1012 số số hạng
=> Có 506 số (-2)
=> A=(-2).506=-1012
( -1/7 + 2/7 - 5/11 ) - ( 1/4 - 5/7 )
= ( 1/7 - 5/11 ) - ( 1/4 - 5/7 )
= 1/7 - 5/11 - 1/4 + 5/7
= 6/7 - 5/11 - 1/4
= 47/308
\(a,x:\left(-\frac{15}{28}\right)=\frac{21}{35}\)
\(x=\frac{21}{35}\times\left(-\frac{15}{28}\right)\)
\(x=-\frac{9}{28}\)
\(b,x-\frac{1}{42}=-\frac{6}{7}\times\frac{5}{7}\)
\(x-\frac{1}{42}=-\frac{30}{49}\)
\(x=-\frac{30}{49}+\frac{1}{42}\)
\(x=-\frac{173}{294}\)
\(c,\left(x-\frac{3}{4}\right):\frac{7}{5}=-\frac{1}{4}\)
\(x-\frac{3}{4}=-\frac{1}{4}\times\frac{7}{5}\)
\(x-\frac{3}{4}=-\frac{7}{20}\)
\(x=-\frac{7}{20}+\frac{3}{4}\)
\(x=\frac{2}{5}\)
a)x:-15/28=21/35
x=21/35.-15/28
x=-9/28
b)x-1/42= -6/7.5/7
x-1/42= -6/7.5/7
x-1/42=-30/49
x=-30/49+1/42
x=-173/294
c)(x-3/4):7/5=-1/4
x-3/4=-1/4.7/5
x-3/4=-7/20
x=-7/20+3/4
x=2/5
có gì sai xin tha thứ giùm nha!
hi hi!!!
=\(\frac{3\left(\frac{1}{1}-\frac{1}{11}+\frac{1}{13}\right)}{5\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{\frac{2}{4}+\frac{2}{6}+\frac{2}{8}}{5\left(\frac{1}{4}+\frac{1}{6}+\frac{1}{8}\right)}\)
=\(\frac{3}{5}+\frac{2\left(\frac{1}{4}+\frac{1}{6}+\frac{1}{8}\right)}{5\left(\frac{1}{4}+\frac{1}{6}+\frac{1}{8}\right)}\)=\(\frac{3}{5}+\frac{2}{5}=\frac{5}{5}=1\)
thật sự mị ko biết
B=1,59(285714)
HOK TỐT