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= 1/1x2 + 1/2x3 + 1/3x4 ...... +1/9x10
= 1-1/2+1/2-1/3+1/3-1/4+........+1/9-1/10
=1-1/10=9/10
đặt A=1/1 x 1/2 + 1/2 x 1/3 + 1/3 + 1/4 + .......... + 1/9 x 1/10
\(A=\frac{1}{1}\cdot\frac{1}{2}+\frac{1}{2}\cdot\frac{1}{3}+...+\frac{1}{9}\cdot\frac{1}{10}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
đặt B=2/1 x 2 + 2/2 x 3 + 2/3 x4 + .............. + 2/98 x 99 + 2/99 x 100
\(B=2\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\right)\)
\(=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\right)\)
\(=2\left(1-\frac{1}{100}\right)\)
\(=2\times\frac{99}{100}\)
\(=\frac{99}{50}\)
A = 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100
A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3
A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)
A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.
A x 3 = 99x100x101 A = 99x100x101 : 3 A = 333300 tích cho mình với, ko chat àh
1/1*2 + 1/2*3 + 1/3*4 + .... + 1/99 * 100
= 1- 1/100
= 99/100
nhờ sự hỗ trợ của máy tính ý
#mã mã#
(1+1+1+.............+1+1):50+2010-12xX=91
(1x50):50+2010-12xX
50:50+2010-12xX=91
1+2010-12xX=91
2011-12xX=91
12xX=2011-91
12xX=1920
x=1920:12
x=160
2S=1x2x3+2x3x3+3x4x3+...+98x99x3+99x100x3
3S=1x2x3+2x3x(4-1)+3x4x(5-2)+...+98x99x(100-97)+99x100x(101-98)
3S=1x2x3-1x2x3+2x3x4-2x3x4+3x4x5-...-97x98x99+98x99x100-98x99x100+99x100x101=99x100x101
S=33x100x101=333300
3xS = 1x 2x 3 + 2x3x3 + 3x4x3 + ...+ 98x99x3 + 99x100x3
= 1x2x3 + 2x3x(4-1) + 3x4x(5-2) +...+98x99x(100-97) + 99x100x(101-98)
= 1x2x3 -1x2x3 + 2x4x4 -2x3x4 + 3x4x5 +...- 97x98x99 +98x99x100 -98x99x199 + 99x100x101
= 99x100x101 = 999900
=> S = 999900 : 3 =333300