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\(\frac{14^{1005}.5^{1006}}{2^{1007}.35^{1004}}\)
\(=\frac{2^{1005}.7^{1005}.5^{1006}}{2^{1007}.5^{1004}.7^{1004}}\)
\(=\frac{5^2.7}{2^2}=\frac{25.7}{4}=\frac{175}{4}\)
TRẦN TIỂU HY ƠI, BẠN TRÌNH BÀY RA GIÙM MK NHA. MK KO HIỂU LẮM
\(\frac{\left(-5\right)^2.\left(-5\right)^3.16}{5^4.\left(-2\right)^4}=\frac{\left(-5\right)^5.16}{5^4.16}=\frac{\left(-5\right)^5}{5^4}=-5\)
\(\frac{14^{1005}.5^{1006}}{2^{1007}.35^{1004}}=\frac{14^{1005}.5^{1005}.5}{2^{1004}.2^3.35^{1004}}=\frac{\left(14.5\right)^{1005}.5}{\left(2.35\right)^{1004}.2^3}=\frac{70^{1005}.5}{70^{1004}.2^3}=\frac{70.5}{8}=\frac{350}{8}=\frac{175}{4}\)
Chúc bạn học tốt!
Toán lớp 6 ?
\(\frac{\left(-5\right)^2\left(-5\right)^3.16}{5^4.\left(-2\right)^4}=\frac{\left(-5\right)^5.2^4}{5^4.2^4}=-5\)
\(\frac{14^{1005}.5^{1006}}{2^{1007}.35^{1004}}=\frac{14^{1005}.5^{1005}.5}{2^{1004}.35^{1004}.2^3}=\frac{\left(14.5\right)^{1005}.5}{\left(2.35\right)^{1004}.8}=\frac{70^{1005}.5}{70^{1004}.8}=\frac{70.5}{8}=\frac{175}{4}\)
Bài 1 :
a) \(\dfrac{14^{1005}.5^{1006}}{2^{1007}.35^{1004}}=\dfrac{7^{1005}.2^{1005}.5^{1006}}{2^{1007}.5^{1004}.7^{1004}}=\dfrac{7.5^2}{2^2}=\dfrac{7.25}{4}=\dfrac{175}{4}\)
Bài 2 :
Ta có : \(\dfrac{\widehat{A}}{4}=\dfrac{\widehat{B}}{5}=\dfrac{\widehat{C}}{9}\) ( \(\widehat{A}+\widehat{B}+\widehat{C}\) = 180o )
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\dfrac{\widehat{A}}{4}=\dfrac{\widehat{B}}{5}=\dfrac{\widehat{C}}{9}=\dfrac{\widehat{A}+\widehat{B}+\widehat{C}}{4+5+9}=\dfrac{180^o}{18}=10^o\)
\(\dfrac{\widehat{A}}{4}=10^o\Rightarrow\widehat{A}=10^o.4=40^o\)
\(\dfrac{\widehat{B}}{5}=10^o\Rightarrow\widehat{B}=10^o.5=50^o\)
\(\dfrac{\widehat{C}}{9}=10^o\Rightarrow\widehat{C}=10^o.9=90^o\)
Vậy ...
a. \(\frac{2}{7}+\frac{5}{7}:\frac{2}{21}+\frac{19}{21}=\frac{6}{21}+\frac{5}{7}.\frac{21}{2}+\frac{19}{21}=\frac{25}{21}+\frac{15}{2}=\frac{365}{42}\)
b. \(\frac{14^{1005}.5^{1006}}{2^{1007}.35^{1004}}=\frac{14^{1005}.5^{1005}.5}{2^{1004}.2^3.35^{1004}}=\frac{70^{1005}.5}{70^{1004}.8}=\frac{70.5}{8}=\frac{350}{8}=\frac{175}{4}\)
c. \(\left|-2,5\right|+\left|\frac{1}{3}\right|.\left|6\right|-\left|\frac{2}{3}\right|=2,5+\frac{1}{3}.6-\frac{2}{3}=\frac{5}{2}+2-\frac{2}{3}=\frac{23}{6}\)
(x - 2/3)3 = -1/27
=> (x - 2/3)3 = (-1/3)3
=> x - 2/3 = -1/3
=> x = -1/3 + 2/3
=> x = 1/3
Từ bài ra ta có \(\left(x-\frac{2}{3}\right)^3=\left(\frac{-1}{3}\right)^3\)
\(\Rightarrow x-\frac{2}{3}=\frac{-1}{3}\)
\(\Rightarrow x=\frac{-1}{3}+\frac{2}{3}\)
\(\Rightarrow x=\frac{1}{3}\)
Vậy ... nếu đúng thì k nha
\(\frac{5}{x-2}=\frac{15}{6}\)
\(\Rightarrow15x-30=30\)
\(15x=60\)
\(x=4\)
\(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{14}=\frac{y}{21}\)
\(\frac{y}{7}=\frac{z}{4}\Rightarrow\frac{y}{21}=\frac{z}{12}\)
\(\Leftrightarrow\frac{x}{14}=\frac{y}{21}=\frac{z}{12}=\frac{x+y-z}{14+21-12}=\frac{69}{23}=3\)
\(\Rightarrow x=52;y=63;z=36\)
\(\hept{\begin{cases}\frac{x}{2}=\frac{y}{3}\\\frac{y}{7}=\frac{z}{4}\end{cases}\Rightarrow\hept{\begin{cases}\frac{x}{14}=\frac{y}{21}\\\frac{y}{21}=\frac{z}{12}\end{cases}\Rightarrow}\frac{x}{14}=\frac{y}{21}=\frac{z}{12}}\)
Áp dụng tính chất dãy tỉ số bằng nhau:
\(\frac{x}{14}=\frac{y}{21}=\frac{z}{12}=\frac{x+y-z}{14+21-12}=\frac{69}{23}=3\)
\(\Rightarrow\hept{\begin{cases}x=3.14=42\\y=3.21=63\\z=3.12=36\end{cases}}\)
ta có a^1005+b^1005 / c^1005+d^1005
=> a^1005/c^1005=b^1005/d^1005
=a/c=b/d=a+b/c+d=(a+b)^2015/(c+d)^1005
\(\frac{2^{1005}.7^{1005}.5^{1006}}{2^{1007}.5^{1004}.7^{1004}}\)
\(=\frac{7.5^2}{2^2}\)
\(=\frac{175}{4}\)
Chúc bạn học tốt^^
\(\frac{2^{1005}.7^{1005}.5^{1006}}{2^{1007}.5^{1004}.7^{1004}}\)
\(=\frac{7.5^2}{2^2}\)
\(=\frac{175}{4}\)
Chúc bạn học tốt^^