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\(\dfrac{7}{5}:x=\dfrac{25}{37}.\dfrac{13}{21}+\dfrac{2}{7}.\dfrac{13}{21}\)
\(\dfrac{7}{5}:x=\dfrac{13}{21}.\left(\dfrac{25}{37}+\dfrac{2}{7}\right)\)
\(\dfrac{7}{5}:x=\dfrac{1079}{1813}\)
\(x=\dfrac{12691}{5395}\)
a=\(1\times3+\dfrac{2}{3}\times7+\dfrac{3}{7}\times13+\dfrac{4}{13}\times21+\dfrac{5}{12}\times21\)
=3+\(\dfrac{14}{3}\)+\(\dfrac{39}{7}\)+\(\dfrac{84}{13}\)+5=8+\(\dfrac{215}{21}\)+\(\dfrac{84}{13}\)=\(\dfrac{4559}{273}\)+8=\(\dfrac{6743}{273}\)
CÁCH 1:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{35}+\frac{34}{105}=\frac{17}{21}\)
CÁCH 2:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{21}\times(\frac{3}{5}+\frac{2}{5})=\frac{17}{21}\times1=\frac{17}{21}\)
Cách 1:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
\(=\frac{3\times17}{5\times21}+\frac{17\times2}{21\times5}\)
\(=\frac{17}{5\times7}+\frac{34}{105}\)
\(=\frac{17}{35}+\frac{34}{105}\)
\(=\frac{17\times3}{35\times3}+\frac{34}{105}\)
\(=\frac{51+34}{105}\)
\(=\frac{85}{105}\)
\(=\frac{17}{21}\)
Cách 2:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
\(=\frac{17}{21}\times\left(\frac{3}{5}+\frac{2}{5}\right)\)
\(=\frac{17}{21}\times1\)
\(=\frac{17}{21}\)
C1 : 3/5 + 17/21 + 17/21 x 2/5
= 3/5 + 17/21 x ( 1 + 2/5 )
= 3/5 + 17/21 x ( 5/5 + 2/5 )
= 3/5 + 17/21 x 7/5
= 3/5 + 17/15
= 9/15 + 17/15
= 26/15
Cách 1 : \(\dfrac{5}{7}\times\dfrac{3}{21}+\dfrac{2}{7}\times\dfrac{3}{21}=\dfrac{5}{49}+\dfrac{2}{49}=\dfrac{1}{7}\)
Cách 2 : \(\dfrac{5}{7}\times\dfrac{3}{21}+\dfrac{2}{7}\times\dfrac{3}{21}=\dfrac{3}{21}\times\left(\dfrac{5}{7}+\dfrac{2}{7}\right)=\dfrac{1}{7}\times1=\dfrac{1}{7}\)
a) (27 -18) : 3 =?
Cách 1: (27 -18) : 3
= 9 : 3 = 3
Cách 2:(27 -18) : 3
= 27 : 3 - 18 : 3
= 9 - 6 = 3
b) (64 - 32) : 8 = ?
Cách 1:(64 - 32) : 8
= 32 : 8 = 4
Cách 2:(64 - 32) : 8
= 64 : 8 - 32 : 8
= 8 - 4 = 4
Nói thêm: Khi chia một hiệu cho một số, ta có thể chia số bị trừ và số trừ cho số đó (nếu chia hết), rồi trừ hai kết quả cho nhau.
(27 -18) : 3
= 27 : 3 - 18 : 3
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: =17/21(3/5+2/5)=17/21
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: \(=\dfrac{17}{21}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{17}{21}\)
C1:5/7×13/21+2/7×13/21
=65/147+26/147
=91/147
C2=5/7×13/21+2/7×13/21
=(5/7+2/7)×13/21
=7/7×13/21
=91/147
5/7×13/21+2/7+13/21
=(5/7+2/7)×13/21
=1×13/21
=13/21