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13,44 . x - (1,6 + x) . 0,5 - 3,7 . (x - 0,9) =13,618
=> 13,44x - 0,8 - 0,5x - 3,7x + 3,33 - 13,618 = 0
=> 9,24x - 11,088 = 0
=> 9,24x = 11,088
=> x = 1,2
13,44 . x - (1,6 + x) . 0,5 - 3,7 . (x - 0,9) =13,618
=> 13,44x - 0,8 - 0,5x - 3,7x + 3,33 - 13,618 = 0
=> 9,24x - 11,088 = 0
=> 9,24x = 11,088
=> x = 1,2
a) \(12,5.4-x=4,3+2,6.\)
\(\Rightarrow12,5.4-x=6,9\)
\(\Rightarrow50-x=6,9\)
\(\Rightarrow x=50-6,9=43,1\)
b) \(\left(x+0,9\right).\left(1-0,4\right)=2412\)
\(\Rightarrow\left(x+0,9\right).0,6=2412\)
\(\Rightarrow x+0,9=2412:0,6=4020\)
\(\Rightarrow x=4020-0,9=4019,1\)
Ủng hộ mik nha!
a,x.(76,42+23,58)=300
x.100=300
x=3
b,1,2.x=2,9-2,3
1,2.x=0,6
x=0,6:1,2
x=0,5
c,x:3,6=0,17:0,9
x:3,6=0,188888888
x=0,188888888.3,6
x=0,68
d, 1,2.x=5,34-0,54
1,2.x=4,8
x=4,8:1,2
x=4
đúng cho li ke nhé
a, X(76,42+23,58)=300
X.100=300
suy ra X =3
b,1,2.X=2,9-2,3
1,2.X=0,6
X=0,6:1,2
suy ra X=0,5
c,
X=0,17:0,9.3,6
suy ra X=0,68
d,1,2.X=5,34-0,54
1,2.X=4,8
X=4,8:1,2
X=4
a) \(\left(2,4-3x\right).0,5=0,9\)
\(2,4-3x=0,9:0,5\)
\(2,4-3x=1,8\)
\(3x=2,4-1,8\)
\(3x=0,6\)
\(x=0,6:3\)
\(x=0,2\)
b) \(\left(8,8x-50\right):0,4=51\)
\(8,8x-50=51.0,4\)
\(8,8x-50=20,4\)
\(8,8x=20,4+50\)
\(8,8x=70,4\)
\(x=70,4:8,8\)
\(x=8\)
c) \(\left(0,472-x\right):2=1,634\)
\(0,472-x=1,634.2\)
\(0,472-x=3,268\)
\(x=0,472-3,268\)
\(x=-2,796\)
d) \(1,6-\left(x-0,2\right)=6,5\)
\(x-0,2=1,6-6,5\)
\(x-0,2=-4,9\)
\(x=-4,9+0,2\)
\(x=-4.7\)
\(a.2,4-3x=1,8\)
\(3x=0,6\)
\(x=0,2\)
\(b.8,8x-50=20,4\)
\(8,8x=70,4\)
\(x=8\)
\(c.0,472-x=3,268\)
\(x=-2,796\)
\(d.x-0,2=-4,9\)
\(x=-4,7\)
=>X. 1,7=0,9 . 0,25
=> X . 1,7 = 0,225
=> X =0,225 : 0,17
=> \(\frac{0,225}{0,17}\)
Vậy x= \(\frac{0,225}{0,17}\)
x/0.9=0.25/1.7
x*100/90=25/170
x*17*100/1530=225/1530
=>x*17*100=225
x*1700=225
x=225/1700
x=
\(0,81:\frac{x}{2}=\frac{16}{x^4}:\left(-0.9\right)\)
=> \(\frac{81}{100}:\frac{x}{2}=\frac{16}{x^4}:\frac{-9}{10}\)
=> \(\frac{81}{50x}=\frac{160}{-9.x^4}\)
=> \(81.\left(-9\right)x^4=50x.160\)
=> \(-729.x^4=8000.x\)
=> \(x^4:x=8000:\left(-729\right)\)
=> \(x^3=\frac{-8000}{729}\)
=> \(x^3=\frac{-20^3}{9^3}\)
=> \(x^3=\frac{-20}{9}^3\)
=> \(x=\frac{-20}{9}\)