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a)\(\frac{x}{17}=\frac{60}{204}=\frac{5}{17}\Rightarrow x=5\)
b)\(\frac{6+x}{33}=\frac{7}{11}\Rightarrow11\left(6+x\right)=7.33\Rightarrow11.6+11x=231\Rightarrow66+11x=231\)
\(\Rightarrow11x=231-66\Rightarrow11x=165\Rightarrow x=\frac{165}{11}=15\)
c)\(\frac{12+x}{43-x}=\frac{2}{3}\Rightarrow2\left(43-x\right)=3\left(12+x\right)\Rightarrow2.43-2x=3.12+3x\)
\(86-2x=36+3x\Rightarrow86-36=3x+2x\Rightarrow50=5x\Rightarrow x=\frac{50}{5}=10\)
(7 - x) + (10 -x) + (13 - x) + ... + (52 - x) + (55 - x) = 493
<=>7+10+13+...+55-17x=493
<=>(55+7).17:2 - 17x=493
<=>527-17x=493
<=>x=2
x + 3 + x + 5 + x + 7 - x - 9 = 52
2x + 6 = 52
2x = 46
x = 23
a, 2015 - 2 × X = 101
2 x X = 2015 - 101
2 x X = 1914
X = 1914 : 2
X = 957
1a. 2015 - 2 x X = 101
2 x X = 2015 - 101
X = 1914 : 2
X = 957
b. 7 - (11 + X - 13) : \(2\frac{2}{3}\)= 2
(11 + X - 13) : \(2\frac{2}{3}\) = 7 - 2
11 + X - 13 = 5 x \(2\frac{2}{3}\)
11 + X = \(\frac{40}{3}\)+ 13
X = \(\frac{79}{3}\)- 11
X = \(\frac{46}{3}\)
c. 2012 - 5 x X = 17
5 x X = 2012 - 17
X = 1995 : 5
X = 399
d. \(5\frac{3}{4}\)+ (X - 2) x \(\frac{1}{3}\)= \(17\frac{3}{4}\)
(X - 2) x \(\frac{1}{3}\) = \(17\frac{3}{4}\)- \(5\frac{3}{4}\)
X - 2 = 12 : \(\frac{1}{3}\)
X = 36 + 2
X = 38
e. 12 x (X - 5) + 73 = 20
12 x (X - 5) = 20 - 73
X - 5 = -53 : 12
X = \(\frac{-53}{12}\)+ 5
X = \(\frac{7}{12}\)
\(\frac{x}{17}+\frac{19}{34}=2\frac{1}{2}\)
\(\Rightarrow\frac{2x}{34}+\frac{19}{34}=2\frac{1}{2}\)
\(\Rightarrow\frac{2x+19}{34}=2\frac{1}{2}\Rightarrow2x+19=34.2\frac{1}{2}\Rightarrow2x+19=85\Rightarrow2x=66\Rightarrow x=33\)
b) 30% * x + x =52
=> 3/10 * x + x=52
=> x * ( 3/10 + 1 ) = 52
=> x *1,3 = 52
=> x = 52 : 1,3 =40
\(\frac{x}{17}+\frac{19}{34}=2\frac{1}{2}=\frac{5}{2}\)
\(\frac{x}{17}=\frac{5}{2}-\frac{19}{34}\)
\(\frac{x}{17}=\frac{170}{68}-\frac{38}{68}\)
\(\frac{x}{17}=\frac{132}{68}\)
=>\(x.68=17.132\)
\(x.68=2244\)
\(x=2244:68\)
\(x=33\)
vậy x=33
dấu"." chính là phép nhân đó em!!!
chúc em học giỏi...
a) Ta có:
1; 4; 7;...; 100 có (100 - 1) : 3 + 1 = 34 (số)
1 + 4 + 7+ ... + 100 = (100 + 1) × 34 : 2
= 101 × 17
(1 + 4 + 7 + ... + 100) : a = 17
101 × 17 : a = 17
a = 101 × 17 : 17
a = 100
b) (X - 1/2) × 5/3 = 7/4 - 1/2
(X - 1/2) × 5/3 = 5/4
X - 1/2 = 5/4 : 5/3
X - 1/2 = 3/4
X = 3/4 + 1/2
X = 5/4
a) (1 + 4 + 7 +...+ 100) : a = 17
1717 : a = 17
a = 101
b) \(\left(x-\dfrac{1}{2}\right)\times\dfrac{5}{3}=\dfrac{7}{4}-\dfrac{1}{2}\)
\(\left(x-\dfrac{1}{2}\right)\times\dfrac{5}{3}=\dfrac{10}{8}\)
\(\left(x-\dfrac{1}{2}\right)=\dfrac{10}{8}\div\dfrac{5}{3}\)
\(\left(x-\dfrac{1}{2}\right)=\dfrac{10}{8}\times\dfrac{3}{5}\)
\(\left(x-\dfrac{1}{2}\right)=\dfrac{3}{4}\)
\(x-\dfrac{1}{2}=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}+\dfrac{1}{2}\)
\(x=\dfrac{5}{4}\)
a) X x 48 + 52 x X =160
X x ( 48+52) = 160
X x 100 = 160
X = 8/5
b) 7 x ( 8+2xX) =210
8+2xX = 30
2xX= 22
X= 11
c) X x 56 + 44 x X+285 x X =130
X x ( 56+44+285)= 130
X x 385 =130
X = 26/77
d) (x-12) x 17 : 11= 51
( x-12) x17 =561
x-12 = 33
x= 45
e) 915 x X +285 x X =48
X x( 915+285) = 48
X x 1200 = 48
X =1/25
\(48x+52x=160\)
\(x.\left(48+52\right)=160\)
\(100x=160\)
\(x=\frac{160}{100}\)
\(x=1,6\)
Vậy \(x=1,6\)
Đăng ít thôi b
Bài 1: Ta có: \(4\dfrac{3}{5}+\dfrac{7}{10}< X< \dfrac{20}{3}\)
\(\dfrac{23}{5}+\dfrac{7}{10}< X< \dfrac{20}{3}\)
\(\dfrac{138}{30}< X< \dfrac{200}{3}\)
\(\Rightarrow X\in\left\{\dfrac{160}{30};\dfrac{161}{30};\dfrac{162}{30};...;\dfrac{198}{30};\dfrac{199}{30}\right\}\)
Bài 2: \(X-2019\dfrac{2}{13}=3\dfrac{7}{26}+4\dfrac{7}{52}\)
\(\Rightarrow X-\dfrac{26249}{13}=\dfrac{85}{26}+\dfrac{215}{52}\)
\(\Rightarrow X-\dfrac{26249}{13}=\dfrac{385}{52}\)
\(\Rightarrow X=\dfrac{105381}{52}\)
nếu muốn tìm x thì phải cho kết quả rồi mới tìm được chứ