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Ta có
\(\left(2x-1\right)^2\ge0\) với mọi x
\(\Rightarrow3\left(2x-1\right)^2\ge0\)
\(\Rightarrow5+3\left(2x-1\right)^2\ge5\)
Dấu " = " xáy ra khi 2x+1=0
=>x=-1/2
Vậy MINC=5 khi x= - 1/2
\(5+3\left(2x-1\right)^2\)
\(5+3\left[\left(2x^2\right)-2.2x.1+1^2\right]\)
\(\Rightarrow\left(2x-1\right)^2\ge0\)
\(\Rightarrow8\left(2x-1\right)^2\ge8\)
Vậy giá trị nhỏ nhất là 8
Khi 2x - 1 = 0
2x = 1
x = 1/2
1) 2x . 4 = 128
2x = 128 : 4
2x = 32
2x = 25
=> x = 5
2) (2x + 1)3 = 125
(2x + 1)3 = 53
=> 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 2
các bài khác bạn tự làm nha
10+2 | x |= 3. (42-2)
10+2 | x |= 42
x=42-10
x=32
x=32/2
x=16
Xét vế trái của biểu thức (VT)
\(VT=1+2^2\left(1+1\right)+3^2\left(2+1\right)+4^2\left(3+1\right)+...+10^2\left(9+1\right)\)
\(VT=1+1.2^2+2^2+2.3^2+3^2+3.4^2+4^2+...+9.10^2+10^2\)
\(VT=\left(1+2^2+3^2+4^2+...+10^2\right)+\left(1.2^2+2.3^2+3.4^2+...+9.10^2\right)\)
Đặt \(A=1+2^2+3^2+4^2+...+10^2\)
\(A=1+2\left(1+1\right)+3\left(2+1\right)+4\left(3+1\right)+...+10\left(9+1\right)\)
\(A=1+1.2+2+2.3+3+3.4+4+...+9.10+10\)
\(A=\left(1+2+3+4+...+10\right)+\left(1.2+2.3+3.4+...+9.10\right)\)
Đặt \(B=1.2^2+2.3^2+3.4^2+...+9.10^2\)
\(B=1.2\left(3-1\right)+2.3\left(4-1\right)+3.4\left(5-1\right)+...+9.10\left(11-1\right)\)
\(B=1.2.3-1.2+2.3.4-2.3+3.4.5-3.4+...+9.10.11-9.10\)
\(B=\left(1.2.3+2.3.4+3.4.5+...+9.10.11\right)-\left(1.2+2.3+3.4+...+9.10\right)\)
\(VT=A+B=\left(1+2+3+4+...+10\right)+\left(1.2.3+2.3.4+3.4.5+...+9.10.11\right)\)
Đặt \(C=1+2+3+4+...+10=55\) (Tổng cấp số cộng)
Đặt \(D=1.2.3+2.3.4+3.4.5+...+9.10.11\)
\(4D=1.2.3.4+2.3.4.4+3.4.5.4+...+9.10.11.4\)
\(4D=1.2.3.4+2.3.4\left(5-1\right)+3.4.5\left(6-2\right)+...+9.10.11\left(12-8\right)\)
\(4D=1.2.3.4-1.2.3.4+2.3.4.5-2.3.4.5+3.4.5.6-...-8.9.10.11+9.10.11.12\)
\(4D=9.10.11.12\Rightarrow D=3.9.10.11\)
\(\Rightarrow VT=C+D=55+3.9.10.11=3025=55^2\)
\(\Rightarrow55^2=\left(x+1\right)^2\Rightarrow55=x+1\Rightarrow x=54\)
a)\(\left(9x-2^3\right):5=2\)
\(9x-8=2.5\)
\(9x-8=10\)
\(9x=10+8\)
\(9x=18\)
\(x=18:9\)
\(x=2\)
\(\frac{45^7.9^3.27^{12}.12^8}{2^{26}.5^{14}.3^{16}.81^2}=\frac{\left(3^2\right)^7.5^7.\left(3^2\right)^3.\left(3^3\right)^{12}.\left(2^2\right)^8.3^8}{2^{26}.5^{14}.3^{16}.\left(3^4\right)^2}=\frac{3^{14}.5^7.3^6.3^{36}.2^{16}.3^8}{2^{26}.5^{14}.3^{16}.3^8}\)
\(=\frac{3^{64}.5^7.2^{16}}{2^{26}.5^{14}.3^{24}}=\frac{3^{40}.1.1}{2^{10}.5^7.1}=\frac{3^{40}}{2^{10}.5^7}\)
2.3x = 10.312 + 8.312
2.3x = (10+8).312
2.3x = 18.312
2.3x = 2.32.312
2.3x = 2.314
=> x = 14
2.3^x=10.3^12+8.3^12
2.3^x=3^12.(10+8)
2.3^x=3^12.18
2.3^x=3^12.(3^2+3^2)
2.3^x=3^12.3^2+3^12.3^2
2.3^x=3^15+3^15
2.3^x=3^15.2
=> 3^x=3^15
=> x=15
\(\Leftrightarrow3^x=5.3^{12}+4.\left(3^3\right)^4=5.3^{12}+4.3^{12}.\)
\(\Leftrightarrow3^x=9.3^{12}=3^2.3^{12}=3^{14}\Leftrightarrow x=14\)
bang 14