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\(\left(\frac{4}{15}-\frac{7}{20}\right):\left(\frac{5}{18}+\frac{11}{12}\right)\)
\(=\left(\frac{16}{60}-\frac{21}{60}\right):\left(\frac{20}{72}+\frac{66}{72}\right)\)
\(=-\frac{1}{12}:\frac{43}{36}=-\frac{1}{12}.\frac{36}{43}=-\frac{3}{43}\)
\(\left[\frac{16}{60}-\frac{21}{60}\right]:\left[\frac{10}{36}+\frac{33}{36}\right]=-\frac{1}{12}:\frac{43}{36}=\frac{\left(-1\right).36}{12.43}=\frac{\left(-1\right).3}{1.43}=-\frac{3}{43}\)
\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]:\left(11+x\right)=3\)
\(\left[\left(35\frac{5}{7}-5\frac{5}{7}\right)+2\frac{3}{4}+\frac{1}{4}\right]:\left(11+x\right)=3\)
\(\left[30+3\right]:\left(11+x\right)=3\)
\(33:\left(11+x\right)=3\)
\(11+x=11\)
\(x=0\)
\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)
\(\left[\left(\frac{35\times7+5}{7}+\frac{2\times4+3}{4}\right)-\frac{5\times7+5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)
\(\left[\left(\frac{250}{7}+\frac{11}{4}\right)-\frac{40}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)
\(\left[\frac{1077}{28}-\frac{167}{28}\right]\div\left(11+x\right)=3\)
\(32,5\div\left(11+x\right)=3\)
\(11+x=32,5\div3\)
\(11+x=\frac{65}{6}\)
\(x=\frac{65}{6}-11=-\frac{1}{6}\)
a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
22/7-(11-x)+2/3=7/5
22/7-11+x=7/5-2/3
22/7-11+x=11/15
11+x=22/7-11/5
11x=33/35
x=33/35:11
x=3/35
Vậy x=3/35
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