Question

[Nguyễn Thành Nam]

Tìm X:
\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]:\left(11+X\right)=3\)

Answer 1

[Kurosaki Akatsu]

\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]:\left(11+x\right)=3\)

\(\left[\left(35\frac{5}{7}-5\frac{5}{7}\right)+2\frac{3}{4}+\frac{1}{4}\right]:\left(11+x\right)=3\)

\(\left[30+3\right]:\left(11+x\right)=3\)

\(33:\left(11+x\right)=3\)
\(11+x=11\)

\(x=0\)

Answer 2

[Đức Phạm]

\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\left(\frac{35\times7+5}{7}+\frac{2\times4+3}{4}\right)-\frac{5\times7+5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\left(\frac{250}{7}+\frac{11}{4}\right)-\frac{40}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\frac{1077}{28}-\frac{167}{28}\right]\div\left(11+x\right)=3\)

\(32,5\div\left(11+x\right)=3\)

\(11+x=32,5\div3\)

\(11+x=\frac{65}{6}\)

\(x=\frac{65}{6}-11=-\frac{1}{6}\)