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S=(1-2)+(3-4)+(5-6)+...+(199-200)
S=(-1)+(-1)+...+(-1)
S=(-1).100=-100
S=1+(2-3)+(-4+5)+...+(98-99)+(-100+101)
S=1+(-1)+1+..+(-1)+1
S=1+25.(-1)+25.1
S=1+(-25)+25
S=1+0
=1
\(\frac{4}{3}B=-1+\frac{3}{4}-\left(\frac{3}{4}\right)^2+...+\left(\frac{3}{4}\right)^{99}\)
\(B=-\frac{3}{4}+\left(\frac{3}{4}\right)^2-\left(\frac{3}{4}\right)^3+...+\left(\frac{3}{4}\right)^{100}\)
\(\Rightarrow\)\(\frac{7}{3}B=-1+\left(\frac{3}{4}\right)^{100}\Rightarrow B=\frac{\left(\frac{3}{4}\right)^{100}-1}{\frac{7}{3}}=\frac{3\left[\left(\frac{3}{4}\right)^{100}-1\right]}{7}\)
Như vầy đủ gọn chưa bạn?
\(\left(-\frac{15}{22}\div-\frac{5}{11}\right)\cdot\frac{2}{3}\)
\(=\left(-\frac{15}{22}\cdot-\frac{11}{5}\right)\cdot\frac{2}{3}\)
\(=-\frac{3}{2}\cdot\frac{2}{3}\)
\(=-1\)
các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha
a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)
-\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)
-6 < \(x\) < -4
vì \(x\) \(\in\) Z nên \(x\) = -5
5-[-|-4|+(-3+x-|-6|)]=15-94+|-8|-9
5-[-4+(-3+x-6)] = 15-94+8-9
5-[-4+(-3)+x-6] = (-79)+8-9
5+4-(-3) - x + 6 = -71 - 9
9-(-3) - x + 6 = -80
12 - x + 6 = -80
12-x = -80 - 6
12-x = -86
x = 12 - (-86)
x = 98
mk ko chắc lắm
5 - [ - l -4 l + ( - 3 + x - l - 6 l ) ] = 15 - 94 + l -8 l - 9
5 - [ - 4 + ( - 3 + x - 6 ) ] = - 78 + 8 - 9
5 - [ - 4 - 3 + x - 6 ] = - 70 - 9
5 + 4 + 3 - x + 6 = - 79
9 + 3 - x + 6 = - 79
12 - x + 6 = - 79
12 + ( - x ) + 6 = - 79
12 + ( - x ) = - 79 - 6
12 + ( - x ) = - 85
- x = - 85 - 12
- x = - 97 => x = 97
Vậy x = 97
\(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{4}{5}+\dfrac{5}{6}-\dfrac{6}{7}+\dfrac{7}{8}+\dfrac{6}{7}-\dfrac{5}{6}+\dfrac{4}{5}-\dfrac{3}{4}+\dfrac{2}{3}-\dfrac{1}{2}\)
\(=\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\left(-\dfrac{2}{3}+\dfrac{2}{3}\right)+....+\left(-\dfrac{6}{7}+\dfrac{6}{7}\right)+\dfrac{7}{8}\)
\(=\dfrac{7}{8}\)
Chúc bạn học tốt!!!
\(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{4}{5}+\dfrac{5}{6}-\dfrac{6}{7}+\dfrac{7}{8}+\dfrac{6}{7}-\dfrac{5}{6}+\dfrac{4}{5}-\dfrac{3}{4}+\dfrac{2}{3}-\dfrac{1}{2}\)
= \((\dfrac{1}{2}-\dfrac{1}{2})+(-\dfrac{2}{3}+\dfrac{2}{3})+...+(-\dfrac{6}{7}+\dfrac{6}{7})+\dfrac{7}{8}\)
=\(\dfrac{7}{8}\)
\(\frac{7}{6}+\frac{5}{6}:5-\frac{3}{8}.\left(-3\right)^2\)
\(=\frac{7}{6}+\frac{5}{6}.\frac{1}{5}-\frac{3}{8}.9\)
\(=\frac{7}{6}+\frac{1}{6}-\frac{27}{8}\)
\(=\frac{8}{6}-\frac{27}{8}\)
\(=\frac{32}{24}-\frac{81}{24}\)
\(=\frac{-49}{24}\)
Chúc bạn học tốt !!!