tìm UCLN
a] 12 ,18
b]13,32,112
c]25,55,75
d] 24,36,160
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UCLN(24, 36, 160 )
Phân tích
24= 23. 3
36= 32. 22
160= 25. 5
UCLN(24, 36, 160 )= 22= 4
BCNN(20, 175, 55 )
phân tích
20= 22. 5
175=3.5.7
55=5.11
BCNN9175, 20, 55 )= 22. 5. 3.7. 11=4620
a) ƯCLN (24,10) BCNN (24,10)
24=3.23 24=3.23
10=2.5 10=2.5
ƯCLN(24,10)=2 BCNN(24,10)=3.23.5=120
Mấy con khác bn tự làm tương tự nha!
3:
a: \(40=2^3\cdot5;24=2^3\cdot3\)
=>\(ƯCLN\left(40;24\right)=2^3=8\)
=>\(ƯC\left(40;24\right)=Ư\left(8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
b: \(12=2^2\cdot3;52=2^2\cdot13\)
=>\(ƯCLN\left(12;52\right)=2^2=4\)
=>\(ƯC\left(12;52\right)=\left\{1;-1;2;-2;4;-4\right\}\)
c: \(36=2^2\cdot3^2;990=2\cdot3^2\cdot5\cdot11\)
=>\(ƯCLN\left(36;990\right)=3^2\cdot2=18\)
=>\(ƯC\left(36;990\right)=\left\{1;-1;2;-2;3;-3;6;-6;9;-9;18;-18\right\}\)
2:
a: \(12=2^2\cdot3;18=3^2\cdot2\)
=>\(ƯCLN\left(12;18\right)=2\cdot3=6\)
b: \(12=2^2\cdot3;10=2\cdot5\)
=>\(ƯCLN\left(12;10\right)=2\)
c: \(24=2^3\cdot3;48=2^4\cdot3\)
=>\(ƯCLN\left(24;48\right)=2^3\cdot3=24\)
d: \(300=2^2\cdot3\cdot5^2;280=2^3\cdot5\cdot7\)
=>\(ƯCLN\left(300;280\right)=2^2\cdot5=20\)
a:UCLN(12;18)=6
BCNN(12;18)=36
b: UCLN(24;36;60)=12
BCNN(24;36;60)=360
\(a.\dfrac{3}{2}+\dfrac{-1}{3}< \dfrac{x}{6}< \dfrac{1}{9}+\dfrac{31}{18}\)
\(\Leftrightarrow\dfrac{7}{6}< \dfrac{x}{6}< \dfrac{11}{6}\)
\(\Leftrightarrow7< x< 11\)
\(\Leftrightarrow x\in\left\{8;9;10\right\}\)
\(b.\dfrac{-5}{12}+\dfrac{7}{12}+\dfrac{-1}{12}< \dfrac{x}{12}< \dfrac{2}{15}+\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{1}{12}< \dfrac{x}{12}< \dfrac{1}{3}\)
\(\Leftrightarrow\dfrac{1}{12}< \dfrac{x}{12}< \dfrac{4}{12}\)
\(\Leftrightarrow1< x< 4\)
\(\Leftrightarrow x\in\left\{2;3\right\}\)
a)12 = 22 x 3 ; 18= 2 x 32
ƯCLN(12;18)=2 x3 = 6
b)13 =13 ; 32 = 25 ; 112 = 24 x 7
ƯCLN(13 ; 32;112) = 1
c) 25 = 52 ; 55 = 5 x11 ; 75 = 3 x 52
ƯCLN(25;55;75)= 5
d) 24 = 23 x 3 ; 36 = 22 x 32 ; 160 = 25 x 5
ƯCLN ( 24;36;160) = 22 = 4