3x + 2012 = 2015
5x - 12 = 3^2.52
2012 - ( 2013 - x) = 12
2002 : [12+(2x-20)]=91
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\(\frac{x+1}{2014}+\frac{x+2}{2013}+\frac{x+3}{2012}=\frac{3x+12}{2011}\)
\(\Leftrightarrow\left(\frac{x+1}{2014}+1\right)+\left(\frac{x+2}{2013}+1\right)+\left(\frac{x+3}{2012}+1\right)=\frac{3x+12}{2011}+3\)
\(\Leftrightarrow\frac{x+2015}{2014}+\frac{x+2015}{2013}+\frac{x+2015}{2012}=\frac{3x+6045}{2011}\)
\(\Leftrightarrow\frac{x+2015}{2014}+\frac{x+2015}{2013}+\frac{x+2015}{2012}-\frac{3\left(x+2015\right)}{2011}=0\)
\(\Leftrightarrow\left(x+2015\right)\left(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}-\frac{3}{2011}\right)=0\)
Mà \(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}-\frac{3}{2011}\ne0\)
\(\Leftrightarrow x+2015=0\)
\(\Leftrightarrow x=-2015\)
Vậy x = -2015
1: =>5(2x+6)=40
=>2x+6=8
=>2x=2
=>x=1
2: =>12-(x+3)=256:64=4
=>(x+3)=8
=>x=5
3: =>2x-1=3 hoặc 2x-1=-3
=>x=2 hoặc x=-1
4: \(\Leftrightarrow3^{x+2017}=3^{2015}\)
=>x+2017=2015
=>x=-2
cac ban oi giup voi
a) Ta có:
3x + 2012 = 2015
3x = 2015 - 2012
3x = 3
x = 3 : 3
x = 1
Vậy x = 1
b) Ta có:
5x - 12 = 32 .52
5x - 12 = 468
5x = 480
x = 96
Vậy x = 96
c) Ta có:
2012 - (2013 - x) = 12
2013 - x = 2000
x = 13
Vậy x = 13
d) Ta có:
2002 : [12+(2x-20)] = 91
12+(2x-20) = 22
2x-20 = 10
2x = 30
x = 15
Vậy x = 15