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Q
15 tháng 12 2021
820 310 – 281 978 = 538 332
700 000 – 499 888 = 200 112
128 982 + 471 018 = 600 000
800 199 + 189 901 = 990 100
999 x 78 = 77922
481 x 102 = 49062
809 x 320 = 258880
1123 x 123 = 138 129
198911 : 7 = 28415.8571429
200011 : 9 = 22223.4444444
890 : 29 = 30.6896551724
710 : 19 = 37.3684210526
176 : 12 = 14.6666666667
798 : 34 = 23.4705882353
278 : 63 = 4.4126984127
309 : 42 = 7.35714285714
Trên này ko đặt tính dc
DU
1
TH
1 tháng 9 2021
Another alternative explanation.
Mark the leftmost square crossed of each row as ‘r’, and the topmost crossed square of each column with ‘c’. Thus, each square can be marked either ‘r’ or ‘c’ or ‘both r and c’ or ‘neither r nor c’. We’ll examine each case.
For a square to be marked both ‘r’ and ‘c’, the diagonal must pass through the upper left corner of the square.
For square to be marked ‘r’, diagonal should pass through its upper edge.
For square to be marked ‘c’, diagonal must pass through its left edge.
For square to be marked neither ‘r’ nor ‘c’, diagonal must pass through it’s upper as well as left edge, which is not possible. Therefore, no triangles are unmarked.
Now, no. of squares crossed = no. of squares marked ‘r’ + no. of squares marked ‘c’ - no. of squares marked both ‘r’ and ‘c’
Now, no. of r’s = no. of rows (only 1 leftmost crossed square in each row)
no. of c’s = no. of columns (only 1 topmost crossed square in each column)
all rows and columns are crossed by the diagonal.
Therefore, squares crossed = rows + columns - (no. of squares marked both ‘r’ and ‘c’)
Now, only 1 square is marked both ‘r’ and ‘c’ as 199 and 991 are coprime.
Therefore squares crossed = 199 + 991 - 1 = 1189
Look at this video if you want a clearer visual explanation:
DU
2
1 tháng 9 2021
Tham khảo:
Another alternative explanation.
Mark the leftmost square crossed of each row as ‘r’, and the topmost crossed square of each column with ‘c’. Thus, each square can be marked either ‘r’ or ‘c’ or ‘both r and c’ or ‘neither r nor c’. We’ll examine each case.
For a square to be marked both ‘r’ and ‘c’, the diagonal must pass through the upper left corner of the square.
For square to be marked ‘r’, diagonal should pass through its upper edge.
For square to be marked ‘c’, diagonal must pass through its left edge.
For square to be marked neither ‘r’ nor ‘c’, diagonal must pass through it’s upper as well as left edge, which is not possible. Therefore, no triangles are unmarked.
Now, no. of squares crossed = no. of squares marked ‘r’ + no. of squares marked ‘c’ - no. of squares marked both ‘r’ and ‘c’
Now, no. of r’s = no. of rows (only 1 leftmost crossed square in each row)
no. of c’s = no. of columns (only 1 topmost crossed square in each column)
all rows and columns are crossed by the diagonal.
Therefore, squares crossed = rows + columns - (no. of squares marked both ‘r’ and ‘c’)
Now, only 1 square is marked both ‘r’ and ‘c’ as 199 and 991 are coprime.
Therefore squares crossed = 199 + 991 - 1 = 1189
22 tháng 1 2022
a) 347 x 298 + 298 + 652 x 298
= 347 x 298 + 298 x 1 + 652 x 298
= 298 x ( 347 + 1 + 652 )
= 298 x ( 348 + 652 )
= 298 x 1000
= 298000
b) 201 x 526 - 526
= 201 x 526 - 526 x 1
= 526 x ( 201 - 1 )
= 526 x 200
= 105.200
(chọn câu mình nhé! CAM ON BẠN!)
TT
22 tháng 1 2022
Bài 3. Tính bằng cách thuận tiện nhất
a) 347 x 298 + 298 + 652 x 298
= 298 x ( 347 + 1 + 652 )
= 298 x 1000
= 298000
b) 201 x 526 - 526
= 526 x ( 201 - 1 )
= 526 x 200
= 105200
NM
3
9 tháng 2 2016
107. 107. 107 + 298 . 298. 298 - 749. 749 .749 +8
=107*3+298*3-749*3+8
=3(107+298-7490+8
=3(-344)+8
=-1032+8
=-1024
MÌNH NHA !
9 tháng 2 2016
107.107.107 + 298.298.298 - 749.749.749 + 8
= 107.3 + 298.3 - 749.3 + 8
= 3. (107 + 298 - 749) + 8
= 3. (-344) +8
= - 1032 + 8 = -1024
H
25 tháng 9 2023
`48/10 = 24/5=4,8`
`213/10=213:10=21,3`
`3/1000=3:1000=0,003`
`25/1000 = 25:1000=0,025`
`647/100=647:100=6,47`
`982/100=982:100=9,82`
`385/10000=385:10000=0,0385`
`982/1000=0,982`
25 tháng 9 2023
a, \(\dfrac{48}{10}\)=4,8 ; b, \(\dfrac{213}{10}\)=2,13 ; c, \(\dfrac{3}{1000}\)=0,003 ; d,\(\dfrac{25}{1000}\)=0,025 ; e,\(\dfrac{647}{100}\)=6,47; f,\(\dfrac{982}{100}\)=9,82 ; g,\(\dfrac{385}{10000}\)=0,0385 ;h,\(\dfrac{982}{1000}\)=0,0982
NA
3
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
13 tháng 12 2022
47 x 298 + 53 x 298
= 298 x (47 + 53)
= 298 x 100
= 29 800
VT
Vũ Thị Minh Ánh
Giáo viên
13 tháng 12 2022
\(47\times298+53\times298=298\times\left(47+53\right)\)
\(=298\times100=29800\)