12 :{390 :[500 - (125 + 35 . 7)]}
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12:{390:[500-(125+35.7)]}
=12:{390:[500-(125+245)]}
=12:{390:[500-370]}
=12:{390:130}
=12:3
=4
\(12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-370\right]\right\}\)
\(=12:\left[390:130\right]\)
\(=12:3=4\)
12 : ( 390 : ( 500 - ( 125 +35 x 7 )
= 12 : (390 : (500 - (125 + 245) ) )
= 12 : (390 : ( 500 - 370 ) )
= 12 : ( 390 : 130 )
= 12 : 3
= 4
\(12:\left(390:\left(500-\left(125+35\times7\right)\right)\right)\)
\(=12:\left(390:\left(500-370\right)\right)\)
\(=12:\left(390:130\right)\)
\(=12:3\)
\(=4\)
A = 12 : { 390 : [ 500 - ( 125 + 245 ) ] }
A = 12 : { 390 : [ 500 - 370 ] }
A = 12 : { 390 : 130 }
A = 12 : 3
A = 4
Ta có A = 12 : { 390 : [ 500 - 370 ]}
= 12 : { 390 : 130 }
= 12 : 3
= 4
12:(390:(500-(125+245)))
=12:(390:(500-370))
=12:(390:130)
=12:3
=4
12 : {390 : [500 - (125 + 35 . 7)]}
= 12 : {390 : [500 - (125 + 245)]}
= 12 : [390 : (500 - 370)]
= 12 : (390 : 130)
= 12 : 3
= 4
12 : { 390 : [ 500 - ( 125 + 35. 7 ) ] }
= 12 : { 390 : [ 500 - ( 125 + 245 ) ] }
= 12 : { 390 : [ 500 - 370 ] }
= 12 : { 390 : 130 }
= 12 : 3
= 4
a)27.75+25.27-150
=27.(75+25)-150
=27.100-150
=2700-150
=2550
\(a,27.75+25.27-150\)
\(=27.\left(75+25\right)-150\)
\(=27.100-150\)
\(=2700-150\)
\(=2550\)
\(b,12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(=12:\left[390:\left(500-370\right)\right]\)
\(=12:\left(390:130\right)\)
\(=12:3\)
\(=4\)
= 12 : {390 : [500 - (125 + 245)]}
= 12 : [390 : (500 - 370)]
= 12 : (390 : 130)
= 12 : 3
= 4