Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Mk chỉ biết câu a thôi
a) \(\frac{\frac{5}{7}+\frac{5}{9}-\frac{5}{11}}{\frac{15}{7}+\frac{15}{9}-\frac{15}{11}}\)
= \(\frac{5\cdot\left(\frac{1}{7}+\frac{1}{9}-\frac{1}{11}\right)}{15\cdot\left(\frac{1}{7}+\frac{1}{9}-\frac{1}{11}\right)}\)
= \(\frac{5}{15}\)
= \(\frac{1}{3}\)
Chúc bạn học tốt
a) \(\frac{\frac{5}{7}+\frac{5}{9}-\frac{5}{11}}{\frac{15}{7}+\frac{15}{9}-\frac{15}{11}}=\frac{\frac{5}{7}+\frac{5}{9}-\frac{5}{11}}{\frac{\left(10+5\right)}{7}+\frac{\left(10+5\right)}{9}-\frac{\left(10+5\right)}{11}}\)
\(=\frac{\frac{5}{7}+\frac{5}{9}-\frac{5}{11}}{\left(\frac{10}{7}+\frac{5}{7}\right)+\left(\frac{10}{9}+\frac{5}{9}\right)-\left(\frac{10}{11}+\frac{5}{11}\right)}=\frac{0}{\frac{10}{7}+\frac{10}{9}-\frac{10}{11}}=0\)
b) \(\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{5}{73}-\frac{1}{23}}=\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{1}{73}+\frac{4}{73}-\frac{5}{115}}=\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{1}{73}+\frac{4}{73}-\frac{4}{115}+\frac{1}{115}}\)
\(=\frac{4}{5+\frac{1}{73}-\frac{1}{115}}=0\)
tth làm dài quá, làm gọn hơn nè
a, \(\frac{\frac{5}{7}+\frac{5}{9}-\frac{5}{11}}{\frac{15}{7}+\frac{15}{9}-\frac{15}{11}}=\frac{5\left(\frac{1}{7}+\frac{1}{9}-\frac{1}{11}\right)}{15\left(\frac{1}{7}+\frac{1}{9}-\frac{1}{11}\right)}=\frac{5}{15}=\frac{1}{3}\)
b, \(\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{5}{73}-\frac{1}{23}}=\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{5}{73}-\frac{5}{115}}=\frac{4\left(1+\frac{1}{73}-\frac{1}{115}\right)}{5\left(1+\frac{1}{73}-\frac{1}{115}\right)}=\frac{4}{5}\)
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
1. \(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
= \(\frac{5}{9}\) .(\(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\) )
= \(\frac{5}{9}\) . 1 = \(\frac{5}{9}\)
Ta có:
\(\frac{\frac{5}{7}+\frac{5}{9}-\frac{5}{11}}{\frac{15}{7}+\frac{15}{9}-\frac{15}{11}}+\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{5}{73}-\frac{1}{23}}\)\(=\frac{5.\left(\frac{1}{7}+\frac{1}{9}-\frac{1}{11}\right)}{15.\left(\frac{1}{7}+\frac{1}{9}-\frac{1}{11}\right)}+\frac{4.\left(1+\frac{1}{73}\right)-\frac{4}{115}}{5.\left(1+\frac{1}{73}\right)-\frac{1}{23}}\)\(=\frac{5}{15}+\frac{4-\frac{4}{115}}{5-\frac{1}{23}}\)
bạn đọc lại đề đi là 17/7 k phải là 15/7
trông toán nâng cao và phát triển lớp 6 cũng có bài này nhưng ko có giải
tớ chắc chắn đề ko sai!