qiups mình v mình đang vội
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23 tháng 2 2023
Bài 3.2:
Chièu rộng là 45*2/5=18cm
CHiều cao là 18*1/3=6cm
V=18*6*45=270*18=4860cm3
Bài 3.3:
Chiều dài là 40:2-8=20-8=12cm
V=5*8*12=5*96=480cm3
S
17 tháng 2 2023
Bài 3,1
Diện tích xung quanh:
\(2\times0,9\times\left(1,8+1,2\right)=5,4\left(m^2\right)\)
Diện tích toàn phần:
\(5,4+2\times1,8\times1,2=9,72\left(m^2\right)\)
Bài 3,2
Diện tích xung quanh:
\(1,5\times1,5\times4=9\left(cm^2\right)\)
Diện tích toàn phần:
\(1,5\times1,5\times6=13,5\left(cm^2\right)\)
17 tháng 2 2023
Bài 3.2
\(S_{XQ}=1.5^2\cdot4=9\left(cm^2\right)\)
\(S_{TP}=9\cdot1.5=13.5\left(cm^2\right)\)
DT
Đỗ Thanh Hải
CTVVIP
1 tháng 8 2021
1 Where are the picture which were on this wall
2 My father is the person who has great influence on my behavior
3 Do you like the flowers which I bought this morning?
4 All of us are interested in the man who is teaching us PE
5 What's the name of the girl who lent you this book?
6 I don't know the man who wrote lots of good books
7 The girl who has worked here for 5 days will leave me the message
8 All the man who are businessman attended the meeting
9 Do you know the lady who is presenting the topic
10 I haven't read the novel which was written by Nam cao
May bạn giúp mình với mình đang vội.
H
16 tháng 9 2023
\(a,2\left|3x-1\right|+1=5\\ \Rightarrow2\left|3x-1\right|=5-1\\ \Rightarrow2\left|3x-1\right|=4\\ \Rightarrow\left|3x-1\right|=4:2\\ \Rightarrow\left|3x-1\right|=2\\ \Rightarrow\left[{}\begin{matrix}3x-1=2\\3x-1=-2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}3x=3\\3x=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{3}\end{matrix}\right.\)
\(b,\left|\dfrac{x}{2}-1\right|=3\\ \Rightarrow\left[{}\begin{matrix}\dfrac{x}{2}-1=3\\\dfrac{x}{2}-1=-3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\dfrac{x}{2}=4\\\dfrac{x}{2}=-2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=8\\x=-4\end{matrix}\right.\)
\(c,\left|-x+\dfrac{2}{5}\right|+\dfrac{1}{2}=3,5\\ \Rightarrow\left|-x+\dfrac{2}{5}\right|=3,5-\dfrac{1}{2}\\ \Rightarrow\left|-x+\dfrac{2}{5}\right|=3\\ \Rightarrow\left[{}\begin{matrix}-x+\dfrac{2}{5}=3\\-x+\dfrac{2}{5}=-3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}-x=\dfrac{13}{5}\\-x=-\dfrac{17}{5}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{13}{5}\\x=\dfrac{17}{5}\end{matrix}\right.\)
\(d,\left|x-\dfrac{1}{3}\right|=2\dfrac{3}{5}\\ \Rightarrow\left|x-\dfrac{1}{3}\right|=\dfrac{13}{5}\\ \Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{13}{5}\\x-\dfrac{1}{3}=-\dfrac{13}{5}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{13}{5}+\dfrac{1}{3}\\x=-\dfrac{13}{5}+\dfrac{1}{3}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\dfrac{44}{15}\\x=-\dfrac{34}{15}\end{matrix}\right.\)
