Tìm x , biết :
a. \(2\frac{1}{3}\):\(\frac{1}{3}\)= \(\frac{7}{9}\): x
b. x : \(\frac{1}{3}\)= \(\frac{12}{99}\):\(\frac{15}{90}\)
c. 0,15 :x = \(3\frac{1}{3}\): 2,25
d. \(\frac{3}{4}\): 0,75 = x: \(\frac{75}{90}\)
e. \(\frac{x}{-15}\)= \(\frac{-60}{x}\)
f. \(\frac{-2}{x}\)=\(\frac{-x}{8}\)
Mong các bạn giúp mình . Ai làm trước mình tk cho nhé!
a, 2/1/3:1/3=7/9:x b, x:1/3=12/99:15/90
7 = 7/9 : x x :1/3= 8/11
x = 7/9:7 x = 8/11 * 1/3
x = 1/9 x = 8/33
c, 0,15:x=3/1/3:2,25 d, 3/4:0,75=x:75/90
0,15:x =40/27 1 =x:75/90
x = 0,15:40/27 x = 1*75/90
x = 81/800 x = 75/90
e, x/-15=-60/x f, -2/x=-x/8
=>x*x=-15*(-60) => (-2)*8=x*-x
=>x2=900 => -16 = -x2
=>x2=302 hoặc x2=(-30)2 => 16=x2
=> x=30 hoặc x= -30 => x2=42 hoặc x2=(-4)2
=> x=4 hoặc x=-4
a)\(2\frac{1}{3}:\frac{1}{3}=\frac{7}{9}:x\)
\(\frac{7}{3}\times3=\frac{7}{9}:x\)
\(7=\frac{7}{9}:x\)
\(x=\frac{7}{9}:7\)
\(x=\frac{7}{9}\times\frac{1}{7}\)
\(x=\frac{1}{9}\)