8^x+3 + 7^x . 3 =515
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3 x 5 = 15 15 : 3 = 5 15 : 5 = 3 | 3 x 6 = 18 18 : 3 = 6 18 : 6 = 3 | 3 x 8 = 24 24 : 3 = 8 24 : 8 = 3 |
\(5.\left(x+35\right)=515\)
\(\Rightarrow x+35=515:5\)
\(\Rightarrow x+35=103\)
\(\Rightarrow x=103-35\)
\(\Rightarrow x=68\)
Mấy câu còn lại tương tự nhé !
a, (6x-39) :3= 201
6x-39= 201.3
6x-39= 603
6x= 603+39
6x= 642
x= 642:6
x= 107
\(\left(6x-39\right):3=201\)
\(\Rightarrow6x-39=201.3=603\)
\(\Rightarrow6x=603+39=642\)
\(\Leftrightarrow x=642:6=107\)
Vậy x=107
a) 310-(118-x)=217
118-x=310-217
118-x=93
x=118-93
x=25
b) 814-(x-305)=712
x-305=814-712
x-305=102
x =102+305
x = 407
c)5(x+35)=515
x+35 =515:5
x+35 =103
x =103-35
x =68
\(a,310-\left(118-x\right)=217\) \(c,5\left(x+35\right)=515\)
\(118-x=310-217\) \(x+35=515:5\)
\(118-x=93\) \(x+35=103\)
\(x=118-93\) \(x=103-35\)
\(x=25\) \(x=68\)
\(b,814-\left(x-305\right)=712\) \(\left[\left(6.x-39\right):3\right].28=5628\)
\(x-305=814-712\) \(\left(6.x-39\right):3=5628:28\)
\(x-305=102\) \(\left(6.x-39\right):3=201\)
\(x=102+305\) \(6.x-39=201x3\)
\(x=407\) \(6.x-39=603\)
\(6x=603+39\)
\(6x=642\)
\(x=107\)
\(e,2.x-138=2^3.2^2\)
\(2.x-138=32\)
\(2.x=32+138\)
\(2.x=170\)
\(x=170:2\)
\(x=85\)
a) Bạn xemm lại đề nhé.
b) \(5\left(x+35\right)=515\)
\(x+35=515\div5\)
\(x+35=103\)
\(x=103-35\)
\(x=68\)
Vậy \(x=68\).
c) \(90-3\left(x+1\right)=42\)
\(3\left(x+1\right)=90-42\)
\(3\left(x+1\right)=48\)
\(x+1=48\div3\)
\(x+1=16\)
\(x=16-1\)
\(x=15\)
Vậy \(x=15\).
d) \(12x-33=3^2.3^3\)
\(12x-33=3^5\)
\(12x-33=243\)
\(12x=243+33\)
\(12x=276\)
\(x=276\div12\)
\(x=23\)
Vậy \(x=23\).
e) \(100-7\left(x-5\right)=58\)
\(7\left(x-5\right)=100-58\)
\(7\left(x-5\right)=42\)
\(x-5=42\div7\)
\(x-5=6\)
\(\Rightarrow x=6+5=11\)
Vậy \(x=11\).
j) \(24+5x=7^5\div7^3\)
\(24+5x=7^2\)
\(24+5x=49\)
\(5x=49-24\)
\(5x=25\)
\(\Rightarrow x=25\div5=5\)
Vậy \(x=5\).
541+(218-x)=735
(218-x)=735-541
(218-x)=194
x=218-194
x=24
vậy x=24
5 (x+35)=515
(x+35)=515:5
(x+35=103
x=103-35
x=68
vậy x=68
90-3 (x+1)=42
3 (x+1)=90-42
3 (x+1)=48
(x+1)=48:3
(x+1)=16
x=16-1
x=15
vậy x=15
12x-33=3^2.3^3
12x-33=3^5
12x-33=243
12x=243-33
12x=210
x=210:12
x=17,5
vậy x=17,5
100- 7 (x-5)=58
7 (x-5)=100-58
7 (x-5)=42
(x-5)=42:7
(x-5)=6
x=6-5
x=1
vậy x=1
24+5x=7^5:7^3
24+5x=7^2
24+5x=49
5x=49-24
5x=25
x=25:5
x=5
vậy x=5
a. 283 515 – x = 115 684
x = 283 515 - 115 684
x = 167831
b. x × 8 = 49 656
x = 49 656 : 8
x = 6207
\(8^{x+3}+7^x\cdot3=515\)
=>\(8^x\cdot512+7^x\cdot3=515\)
\(8^x>=1\)
=>\(512\cdot8^x>=512\)
mà \(512\cdot8^x< =515\)
nên \(512\cdot8^x=512\)
=>x=0
Khi x=0 thì ta sẽ có: \(512+7^x\cdot3=515\)
=>\(7^x\cdot3=3\)
=>\(7^x=1\)
=>x=0(nhận)
Vậy: S={0}