Bài 1: Tình nhanh
75 + 25.7 - 247 : 19
Bài 2 Tìm x biết:
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Bài 1:
a)-54
b)-8
Bài 2:
a)(x-14):5=415:413
⇔(x-14):5=42
⇔(x-14):5=16
⇔x-14=80
⇔x=94
b)7x-15x=15-175
⇔-8x=-160
⇔x=20
a. (x - 2)(x + 2) - (x - 3)2 = 9
<=> x2 - 22 - (x - 3)2 = 32
<=> x - 2 - (x - 3) = 3
<=> x - 2 - x + 3 = 3
<=> x - x = 3 - 3 + 2
<=> 0 = 2 (Vô lí)
Vậy nghiệm của PT là S = \(\varnothing\)
b: Ta có: \(\left(x-1\right)\left(x^2+1\right)-\left(x+1\right)\left(x^2-x+1\right)=x\left(2-x\right)\)
\(\Leftrightarrow x^3+x-x^2-1-x^3-1=2x-x^2\)
\(\Leftrightarrow-x^2+x-2-2x+x^2=0\)
\(\Leftrightarrow-x=2\)
hay x=-2
\(\frac{75}{100}+\frac{3}{4}x29+75\%x30+0,75x40\)
\(=\frac{3}{4}+\frac{3}{4}x29+\frac{75}{100}x30+\frac{75}{100}x40\)
\(=\frac{3}{4}+\frac{3}{4}x29+\frac{3}{4}x30+\frac{3}{4}x40\)
\(=\frac{3}{4}x\left(1+29+30+40\right)\)
\(=\frac{3}{4}x100\)
= 75
\(\left(x-1\right)^3-\left(\dfrac{2}{2023}-\dfrac{7}{247}+\dfrac{1}{8}\right)=\dfrac{7}{247}-\dfrac{2}{2023}\)
\(\Rightarrow\left(x-1\right)^3-\dfrac{2}{2023}+\dfrac{7}{247}-\dfrac{1}{8}=\dfrac{7}{247}-\dfrac{2}{2023}\)
\(\Rightarrow\left(x-1\right)^3=\dfrac{7}{247}-\dfrac{7}{247}-\dfrac{2}{2023}+\dfrac{2}{2023}+\dfrac{1}{8}\)
\(\Rightarrow\left(x-1\right)^3=\dfrac{1}{8}\)
\(\Rightarrow\left(x-1\right)^3=\left(\dfrac{1}{2}\right)^3\)
\(\Rightarrow x-1=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{2}+1\)
\(\Rightarrow x=\dfrac{3}{2}\)
Lời gải:
$(x-1)^3=\frac{7}{247}-\frac{2}{2023}+\frac{2}{2023}-\frac{7}{247}+\frac{1}{8}=\frac{1}{8}$
$x-1=\frac{1}{2}$
$x=\frac{1}{2}+1=\frac{3}{2}$
1.
a, (x+50)*2=220
=> 2x+100=220
=> 2x = 120
=> x= 60
b, (2x-75)*12=144
=> 24x-900=144
=> 24x=1044
=> x= 43,5
c, (47-3x)=5
=> 47-3x=5
=> 3x=42
=> x= 14
A. ( x + 50 ) x 2= 220
=> 2x + 100 = 220
=> 2x = 220 - 100
=> 2x = 120
=> x = 120 : 2
=> x = 60
B. ( 2x - 75 ) x 12 = 144
=> (2x - 75) x 12 = 144
=> 2x - 75 = 144 : 12
=> 2x - 75 = 12
=> 2x = 75 + 12
=> 2x = 87
=> x = 87 : 2 = 43,5
C. 47 - 3x = 5
=> 3x = 47 - 5 = 42
=> x = 42 : 3
=> x = 14.
2)1 + 2 + 3 + 4 + 5 +..+ X = 2550
=> \(\frac{x.\left(x+1\right)}{2}\)=2550
=> x.(x+1) = 2550 x 2 = 5100. Mà không có 2 số liên tiếp nào nhân với nhau bằng 5100 nên x không thỏa mãn đề bài.
3)Đề sai nha bạn.
Bài 1:
a) =25,97+(6,54+103,46)
=25,97+110
=135,97
b)136x75+75x64
=75x(136+64)
=75x200
=15 000
c) (21/8+1/2):5/16
=(21/8+4/8)x16/5
=25/8x16/5
=10
d)3/17-4/5+14/17
=(3/17+14/17)-4/5
=1-4/5
=1/5
Bài 2:
a)720:\([41-(2x-5)]\)=120
41 - (2x-5) =720:120
41 - (2x-5) =6
2x-5 =41-6
2x-5 =35
2x =35+5
2x =40
x =40:2
x =20
b)2/3 x X +3/4=3
2/3 x X =3-3/4
2/3 x X =12/4-3/4
2/3 x X =9/4
x =9/4:2/3
x =9/4x3/2
x =27/8
c) x+0,34=1,19x1,02
x+0,34=1,2138
x =1,2138-0,34
x =0,8738
(x-7).(2x-8)=0
suy ra :(x-7)=0 suy ra x=7
2x-8=0 suy ra x=4
Câu b:
( x-40) .15 =15.3
(x-40) .15=45
(x-40) = 45:15
x-40 = 3
x=43
Bài 1: Tìm x biết:
a ) (x-7).(2x-8)=0
=>x-7=0 hoặc 2x-8=0
=>x=7 hoặc x=4
b) (x-40).15=15.3
=>(x-40).15=45
=>x-40=45:15
=>x-40=3
=>x=3+40
=>x=43
Bài 1:
\(75+25\cdot7-247:19\)
\(=25\cdot\left(7+3\right)-13\)
\(=25\cdot\left(3+7\right)-13\)
\(=25\cdot10-13\)
\(=250-13\)
\(=237\)
Bài 2:
c) \(2^5\cdot\left(2x+1\right)+1=41\)
\(\Rightarrow2^5\cdot\left(2x+1\right)=41-1\)
\(\Rightarrow32\cdot\left(2x+1\right)=40\)
\(\Rightarrow2x+1=\dfrac{40}{32}\)
\(\Rightarrow2x=\dfrac{5}{4}-1\)
\(\Rightarrow2x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{1}{4}:2\)
\(\Rightarrow x=\dfrac{1}{8}\)
d) \(2^2\cdot5^2-\left(3x-2\right)^3=6^2\)
\(\Rightarrow10^2-\left(3x-2\right)^3=6^2\)
\(\Rightarrow\left(3x-2\right)^3=10^2-6^2\)
\(\Rightarrow\left(3x-2\right)^3=100-36\)
\(\Rightarrow\left(3x-2\right)^3=64\)
\(\Rightarrow\left(3x-2\right)^3=4^3\)
\(\Rightarrow3x-2=4\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=\dfrac{6}{3}\)
\(\Rightarrow x=2\)