timf X
a)175- (42 : X + 95) =3
b)450: (75 - 13x X) =10
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a) \(175+42-75\)
\(=\left(175-75\right)+42\)
\(=100+42\)
\(=142\)
b) \(12\times\left(12-9\right)\)
\(=12\times3\)
\(=36\)
a 95 x { a - 75 } = 95 x { 100 - 75 }
=>a-75=100-75
vậy a=100
b } 2003 + a x 15 = 2003 x 10 x 3 x5
a x 15 = 10 x 3 x5
a x 15 = 10x(3x5)
a x 15=10x15
Vậy a=10
Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
A) 95.(a-75)=95.(100-75)
=>a-75=100-75
vậy a =100
B) 2003+a.15=2003.10.3.5
a.15=10.3.5
a, 450 - 5x = 75
5x = 450 - 75
5x = 375
x = 75
Vậy...
b, ( 450 - 5x ) . 15 = 75
450 - 5x = 5
5x = 445
x = 89
Vậy ...
c, ( 450 - x ) : 15 = 150
450 - x = 2250
x = 450 - 2250
x = -1800
Vậy...
a) 450 -5 x X =75 b) ( 450 - 5 x X ) x15 =75 c) ( 450 - X ) : 15 =150
5 x X =450-75 450 - 5 x X =75 : 15 450 - X =150x15
5 x X =375 450 - 5 x X =5 450 - X =2250
X=375:5 5 x X =450:5 X =450-2250
X=75 5 x X =90 X =-1800
X =90:5
X =18
a) 175 - (4 - x) : 3 = 95
=> (4 - x) : 3 = 175 - 95
=> (4 - x) : 3 = 80
=> 4 - x = 80 . 3
=> 4 - x = 240
=> x = 4 - 240
=> x = -236
Vậy x = -236
b) (3x - 5) - 14 = 71
=> 3x - 5 = 71 + 14
=> 3x - 5 = 85
=> 3x = 85 + 5
=> 3x = 90
=> x = 90 : 3
=> x = 30
Vậy x = 30
Bài 1:
\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)
\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)
\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)
\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)
\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)
\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)
\(A=\frac{9}{11}\)
Bài 2 :
2) Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15
Mẫu số = 11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x 17 = (1+27+125+729) x 13 x 15 x 17
\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)
\(=\frac{11}{17}\)
\(=\frac{1111}{1717}=B\)
Vậy \(A=B\)
a) \(175-\left(42:x+95\right)=3\)
\(\Rightarrow42:x+95=172\)
\(\Rightarrow42:x=77\)
\(\Rightarrow x=42:77\)
\(\Rightarrow x=\dfrac{6}{11}\)
b) \(450:\left(75-13\cdot x\right)=10\)
\(\Rightarrow75-13\cdot x=450:10\)
\(\Rightarrow75-13\cdot x=45\)
\(\Rightarrow13\cdot x=75-45\)
\(\Rightarrow13\cdot x=30\)
\(\Rightarrow x=\dfrac{30}{13}\)