\(2xX+\frac{1}{2xX}+\frac{6xX+1}{6xX}+\frac{12xX+1}{12xX}+\frac{20xX+1}{20xX}=5\)
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a)\(\frac{2}{3}\cdot x+\frac{1}{4}=\frac{5}{6}\)
\(\frac{2}{3}\cdot x=\frac{5}{6}-\frac{1}{4}=\frac{7}{12}\)
\(x=\frac{7}{12}:\frac{2}{3}=\frac{7}{8}\)
b) \(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{1}{4}:\frac{2}{3}\)
\(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{3}{8}\)
\(\frac{5}{6}\cdot x=\frac{7}{12}-\frac{3}{8}=\frac{5}{24}\)
\(x=\frac{5}{24}:\frac{5}{6}=\frac{1}{4}\)
c) \(2\frac{1}{3}-\left(x+1\right)=\frac{5}{9}\)
\(\frac{7}{3}-\left(x+1\right)=\frac{5}{9}\)
\(x+1=\frac{7}{3}-\frac{5}{9}=\frac{16}{9}\)
\(x=\frac{16}{9}-1=\frac{7}{9}\)
d) \(\frac{2\cdot x+1}{15}=\frac{3}{5}\)
\(\left(2\cdot x+1\right):15=\frac{3}{5}\)
\(2\cdot x+1=\frac{3}{5}\cdot15=9\)
\(2\cdot x=9-1=8\)
\(x=8:2=4\)
a, 2/3 . x +1/4=5/6
2/3 . x=5/6-1/4
2/3 . x=10/12 -3/12
2/3 . x=7/12
x= 7/12 : 2/3
x=7/8
Vậy x=7/8
Ở chỗ 6xx vs 2xx la 6x 2x nha cac ban
Cac ban lam on giai nhanh gium minh vs nhe
"X"="x" hay khác vậy
\(\left\{{}\begin{matrix}A=\dfrac{2x^2-6x+7}{x^2-2x+1}=\dfrac{2\left(x-1\right)^2-2\left(x-1\right)+3}{\left(x-1\right)^2}\\y=x-1\end{matrix}\right.\)
\(A=\dfrac{2y^2-2y+3}{y^2}=\dfrac{y^2-2.3y+9}{y^2}-\dfrac{5}{3}=\dfrac{\left(y-3\right)^2}{y^2}\ge\dfrac{5}{3}\)
\(A\ge\dfrac{5}{3}\) khi y=3=> x=4
\(6\times x=\frac{4}{7}\)
\(x=\frac{4}{7}\div6\)
\(x=\frac{1}{21}\)
\(x\div2=\frac{1}{5}\)
\(x=\frac{1}{5}\times2\)
\(x=\frac{2}{5}\)
học tốt
X=4/7:6
x=4/7.1/6
X=4/42
Vậy x=2/5
x=1/5.2
X=1/5.2/1
X=2/5
Vậy x=2/5
Ta có: \(\frac{2xX}{3}-\frac{1}{4}:\left(\frac{3}{2}-\frac{3}{4}\right)=\frac{1}{4}.\frac{2}{3}\)
\(\Rightarrow\frac{2xX}{3}-\frac{1}{4}:\frac{3}{4}=\frac{1}{6}\)
\(\Rightarrow\frac{2Xx}{3}-\frac{1}{3}=\frac{1}{6}\)
\(\Rightarrow2xX:3=\frac{1}{6}+\frac{1}{3}=\frac{1}{2}\)
\(\Rightarrow2xX=\frac{1}{2}.3=\frac{3}{2}\)
\(\Rightarrow X=\frac{3}{2}:2=\frac{3}{4}\)
Vậy x = \(\frac{3}{4}\)
đặt 1/2 ra
phần mẫu áp dụng công thức tính tổng còn lại tự làm nhoa bé