5/12 x 28/15 + 7/3 là ra bao nhiêu
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
7 tháng 8 2019
\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)
\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{35}{18}+1-\frac{17}{18}\)
\(< =>\frac{53}{18}-\frac{17}{18}\)
\(< =>2\)
\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)
\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)
\(< =>\frac{2}{7}\cdot\frac{1}{3}\)
\(< =>\frac{2}{21}\)
\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)
\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)
\(< =>\frac{15}{4}\)
L
1
8 tháng 5 2019
\(\frac{15}{8}+\frac{7}{12}-\frac{13}{3}\cdot\frac{3}{8}\)
\(=\frac{15}{8}+\frac{7}{12}-\frac{13}{8}\)
\(=\left(\frac{15}{8}-\frac{13}{8}\right)+\frac{7}{12}\)
\(=\frac{1}{4}+\frac{7}{12}\)
\(=\frac{5}{6}\)
Học tốt
NB
1
S
14 tháng 4 2019
\(a)\frac{5}{12}+\frac{3}{14}+\frac{7}{12}=\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)
\(b)\frac{15}{14}\times\frac{17}{18}\times\frac{28}{15}=\frac{15\times17\times28}{14\times18\times15}=\frac{17}{9}\)
\(c)\frac{5}{8}\times\frac{5}{4}+\frac{5}{4}\times\frac{3}{8}=\frac{5}{4}\times\left(\frac{5}{8}+\frac{3}{8}\right)=\frac{5}{4}\times1=\frac{5}{8}\)
DT
1
S
14 tháng 4 2019
\(a)\frac{5}{12}+\frac{3}{14}+\frac{7}{12}=\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)
\(b)\frac{15}{14}\times\frac{17}{18}\times\frac{28}{15}=\frac{15\times17\times28}{14\times18\times15}=\frac{17}{9}\)
\(c)\frac{5}{8}\times\frac{5}{4}+\frac{5}{4}\times\frac{3}{8}=\frac{5}{4}\times\left(\frac{5}{8}+\frac{3}{8}\right)=\frac{5}{4}\times1=\frac{5}{8}\)
~Học tốt~
31 tháng 3 2021
Bài 1:
a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)
\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)
hay \(x=-\dfrac{1}{3}\)
Vậy: \(x=-\dfrac{1}{3}\)
b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)
hay \(x=\dfrac{50}{9}\)
Vậy: \(x=\dfrac{50}{9}\)
c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)
\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)
\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)
hay \(x=\dfrac{22}{15}\)
Vậy: \(x=\dfrac{22}{15}\)
d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)
\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)
\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)
hay \(x=\dfrac{15}{19}\)
Vậy:\(x=\dfrac{15}{19}\)
4 tháng 11 2023
a: \(\left(-11\right)\cdot\left(-28\right)+\left(-9\right)\cdot13\)
\(=308-117\)
=191
b: \(\left(-69\right)\cdot\left(-31\right)-\left(-15\right)\cdot12\)
\(=2139-\left(-180\right)\)
=2139+180
=2319
c: \(\left[16-\left(-5\right)\right]\cdot\left(-7\right)\)
\(=\left(16+5\right)\cdot\left(-7\right)\)
\(=-7\cdot21=-147\)
d: \(\left[\left(-4\right)\cdot\left(-9\right)-6\right]\left[\left(-12\right)-\left(-7\right)\right]\)
\(=\left[36-6\right]\left[-12+7\right]\)
\(=30\cdot\left(-5\right)=-150\)
\(\dfrac{5}{12}\times\dfrac{28}{15}+\dfrac{7}{3}\)
\(=\dfrac{7}{9}+\dfrac{7}{3}\)
\(=\dfrac{7}{9}+\dfrac{21}{9}\)
\(=\dfrac{28}{9}\)
\(\dfrac{5}{12}.\dfrac{28}{15}+\dfrac{7}{3}=\dfrac{7}{9}+\dfrac{7}{3}=\dfrac{7}{9}+\dfrac{21}{9}\)
\(=\dfrac{28}{9}\)