K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

QT
Quoc Tran Anh Le
Giáo viên
11 tháng 12 2023

b) 7 + 7 = 14

   7 × 2 = 14

c) 6 + 6 + 6 = 18

  6 × 3 = 18.

c: =1/3(14*10-10)

=130*1/3=130/3

loading...

12 tháng 2 2023

`#` `\text{dkhanhqlv}`

`a)1/8-1/2`

`=1/8-4/8`

`=-3/8`

`b)-11/12-(-1)`

`=-11/12+1`

`=-11/12+12/12`

`=1/12`

`c)3/5-5/6`

`=18/30-25/30`

`=-7/30`

`d)-1/16-1/15`

`=-15/240-16/240`

`=-31/240`

`e)11/36-(-7/24)`

`=11/36+7/24`

`=22/72+21/72`

`=43/72`

`g)-5/9-(-5/12)`

`=-5/9+5/12`

`=-20/36+15/36`

`=-5/36`

12 tháng 2 2023

a) \(\dfrac{1}{8}-\dfrac{1}{2}=\dfrac{1}{8}-\dfrac{4}{8}=-\dfrac{3}{8}\)

b) \(-\dfrac{11}{12}-\left(-1\right)=-\dfrac{11}{12}+\dfrac{12}{12}=\dfrac{1}{12}\)

c) \(\dfrac{3}{5}-\dfrac{5}{6}=\dfrac{18}{30}-\dfrac{25}{30}=-\dfrac{7}{30}\)

d) \(-\dfrac{1}{16}-\dfrac{1}{15}=-\dfrac{15}{240}-\dfrac{16}{240}=-\dfrac{31}{240}\)

e) \(\dfrac{11}{36}-\left(-\dfrac{7}{24}\right)=\dfrac{11}{36}+\dfrac{7}{24}=\dfrac{22}{72}+\dfrac{21}{72}=\dfrac{43}{72}\)

g) \(-\dfrac{5}{9}-\left(-\dfrac{5}{12}\right)=-\dfrac{5}{9}+\dfrac{5}{12}=-\dfrac{20}{36}+\dfrac{15}{36}=-\dfrac{5}{36}\)

1 tháng 3 2017

a ,   32 b ,   - 108 c ,   - 24

Sơ đồ con đường

Lời giải chi tiết

Áp dụng tính chất phân phối của phép nhân phân phối đối với phép cộng

a ,   − 6 − 2 . − 6 + 2 = − 8 . − 4 = 32 b ,   7.3 − 3 . − 6 = 3. 7 − 1 . − 6 = 3.6. − 6 = − 108 c ,   − 5 + 9 . − 6 = 4. − 6 = − 24

 

NV
3 tháng 3 2022

Giới hạn đã cho hữu hạn nên \(ax^2+\left(2b-3\right)x+5=0\) có nghiệm \(x=2\)

\(\Rightarrow4a+2\left(2b-3\right)+5=0\Rightarrow4a+4b-1=0\)

\(\Rightarrow2b=\dfrac{1-4a}{2}\)

\(\Rightarrow\lim\limits_{x\rightarrow2}\dfrac{ax^2+\left(\dfrac{1-4a}{2}-3\right)x+5}{\left(x-2\right)\left(x+3\right)}=\lim\limits_{x\rightarrow2}\dfrac{2ax^2-4ax-5x+10}{2\left(x-2\right)\left(x+3\right)}=\lim\limits_{x\rightarrow2}\dfrac{\left(x-2\right)\left(2ax-5\right)}{2\left(x-2\right)\left(x+3\right)}\)

\(=\lim\limits_{x\rightarrow2}\dfrac{2ax-5}{2\left(x+3\right)}=\dfrac{4a-5}{10}=10\Rightarrow a=\dfrac{105}{4}\)

\(\Rightarrow b=\dfrac{1-4a}{4}=-26\Rightarrow a+2b=-\dfrac{103}{4}\)

28 tháng 11 2021
A/4=b/6;b/5=c/8=a/20=b/30=c/48 suy ra 5a-3b-3c/5.20-3.30-3.48=-536/-134=4 a/20=4 a=80b/30=4 b=120 c/48=4 c=192

a: \(\dfrac{18}{24}+\dfrac{35}{-21}-\dfrac{1}{2}\)

\(=\dfrac{3}{4}-\dfrac{5}{3}-\dfrac{1}{2}\)

\(=\dfrac{9-20-6}{12}=\dfrac{-17}{12}\)

b: \(\dfrac{-2}{3}-\dfrac{3}{-4}+\dfrac{5}{-6}\)

\(=-\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{5}{6}\)

\(=\dfrac{-8+9-10}{12}=\dfrac{-9}{12}=\dfrac{-3}{4}\)

c: \(\left(\dfrac{3}{4}+\dfrac{-7}{2}\right)\cdot\left(\dfrac{10}{11}+\dfrac{2}{22}\right)\)

\(=\left(\dfrac{3}{4}-\dfrac{14}{4}\right)\cdot\left(\dfrac{10}{11}+\dfrac{1}{11}\right)\)

\(=-\dfrac{11}{4}\cdot1=-\dfrac{11}{4}\)

d: \(\left(\dfrac{7}{3}-\dfrac{-7}{2}\right):\left(-\dfrac{25}{6}\cdot\dfrac{1}{5}\right)\)

\(=\left(\dfrac{7}{3}+\dfrac{7}{2}\right):\dfrac{-5}{6}\)

\(=\dfrac{35}{6}\cdot\dfrac{6}{-5}=\dfrac{35}{-5}=-7\)

29 tháng 1 2024

a) \(\dfrac{18}{24}+\dfrac{35}{-21}-\dfrac{1}{2}\)

\(=\dfrac{3}{4}-\dfrac{5}{3}-\dfrac{1}{2}\)

\(=\dfrac{9}{12}-\dfrac{20}{12}-\dfrac{6}{12}\)

\(=\dfrac{-17}{12}\)

b) \(\dfrac{-2}{3}-\dfrac{3}{-4}+\dfrac{5}{-6}\)

\(=\dfrac{-8}{12}+\dfrac{9}{12}-\dfrac{10}{12}\)

\(=\dfrac{-9}{12}\)

\(=\dfrac{-3}{4}\)

c) \(\left(\dfrac{3}{4}+\dfrac{-7}{2}\right).\left(\dfrac{10}{11}+\dfrac{2}{22}\right)\)

\(=\dfrac{-11}{4}.1\)

\(=\dfrac{-11}{4}\)

d) \(\left(\dfrac{7}{3}-\dfrac{-7}{2}\right):\left(-\dfrac{25}{6}.\dfrac{1}{5}\right)\)

\(=\dfrac{35}{6}:\dfrac{-5}{6}\)

\(=-7\)

a: \(\dfrac{3}{5}-\left(-\dfrac{1}{2}\right)=\dfrac{3}{5}+\dfrac{1}{2}=\dfrac{6+5}{10}=\dfrac{11}{10}\)

b: \(-\dfrac{48}{96}+\dfrac{37}{148}\)

\(=-\dfrac{1}{2}+\dfrac{1}{4}=\dfrac{-2}{4}+\dfrac{1}{4}=-\dfrac{1}{4}\)

c: \(\dfrac{1}{5}+\dfrac{-1}{6}+\dfrac{1}{7}+\dfrac{-1}{8}+\dfrac{1}{9}+\dfrac{1}{8}+\dfrac{-1}{7}+\dfrac{1}{6}+\dfrac{-1}{5}\)

\(=\left(\dfrac{1}{5}-\dfrac{1}{5}\right)+\left(-\dfrac{1}{6}+\dfrac{1}{6}\right)+\left(\dfrac{1}{7}-\dfrac{1}{7}\right)+\left(-\dfrac{1}{8}+\dfrac{1}{8}\right)+\dfrac{1}{9}\)

\(=0+0+0+0+\dfrac{1}{9}=\dfrac{1}{9}\)