tinh M=(\(\frac{4\sqrt{2}}{\sqrt{10-2\sqrt{21}}}\)+\(\frac{3}{\sqrt{15+6\sqrt{6}}}\)-\(\frac{1}{\sqrt{19-6\sqrt{10}}}\))\(\sqrt{6+\sqrt{35}}\)
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ML
22 tháng 5 2016
\(\frac{\sqrt{\sqrt{4+\sqrt{15}}+\sqrt{5-\sqrt{21}}}}{\sqrt{6+\sqrt{35}}}\)+\(\sqrt{\frac{1}{4-2\sqrt{3}}}\)-\(\sqrt{\frac{1}{4+2\sqrt{3}}}\)
=\(\frac{\sqrt{\sqrt{\frac{1}{2}\left(8+2\sqrt{15}\right)}+\sqrt{\frac{1}{2}\left(10-2\sqrt{21}\right)}}}{\sqrt{\frac{1}{2}\left(12+2\sqrt{35}\right)}}\)+\(\sqrt{\frac{1}{3-2\sqrt{3}.1+1}}\)-\(\sqrt{\frac{1}{3+2\sqrt{3}.1+1}}\)
=\(\frac{\sqrt{\sqrt{\frac{1}{2}\left(5+2\sqrt{5}.\sqrt{3}+3\right)}+\sqrt{\frac{1}{2}\left(7-2\sqrt{7}.\sqrt{3}+3\right)}}}{\sqrt{\frac{1}{2}\left(7+2\sqrt{7}.\sqrt{5}+5\right)}}\)+\(\sqrt{\frac{1}{\left(\sqrt{3}-1\right)^2}}\)-\(\sqrt{\frac{1}{\left(\sqrt{3}+1\right)^2}}\)
=\(\frac{\sqrt{\sqrt{\frac{1}{2}\left(\sqrt{5}+\sqrt{3}\right)^2}+\sqrt{\frac{1}{2}\left(\sqrt{7}-\sqrt{3}\right)^2}}}{\sqrt{\frac{1}{2}\left(\sqrt{7}+\sqrt{5}\right)^2}}\)+\(\frac{1}{\sqrt{3}-1}\)-\(\frac{1}{\sqrt{3}+1}\)
=\(\frac{\sqrt{\sqrt{\frac{1}{2}}.\left(\sqrt{5}+\sqrt{3}\right)+\sqrt{\frac{1}{2}}.\left(\sqrt{7}-\sqrt{3}\right)}}{\sqrt{\frac{1}{2}}.\left(\sqrt{7}+\sqrt{5}\right)}\)+\(\frac{\sqrt{3}+1-\sqrt{3}+1}{3-1}\)
=\(\frac{\sqrt{\sqrt{\frac{1}{2}}.\left(\sqrt{7}+\sqrt{5}\right)}}{\sqrt{\frac{1}{2}}.\left(\sqrt{7}+\sqrt{5}\right)}\)+1
=\(\frac{1}{\sqrt{\sqrt{\frac{1}{2}}.\left(\sqrt{7}+\sqrt{5}\right)}}\)+1
20 tháng 10 2018
a) \(\frac{\sqrt{2}\left(\sqrt{3}+\sqrt{5}\right)}{\sqrt{7\left(\sqrt{3}+\sqrt{5}\right)}}=\) \(\frac{\sqrt{2}}{\sqrt{7}}\)
b ) \(\frac{15\sqrt{2}+9\sqrt{3}}{3\sqrt{3}+3\sqrt{5}}=\frac{3\left(5\sqrt{2}+3\sqrt{3}\right)}{3\left(\sqrt{3}+\sqrt{5}\right)}\)\(=\frac{5\sqrt{2}+3\sqrt{3}}{\sqrt{3}+\sqrt{5}}\)
c)\(\frac{\sqrt{2}-\sqrt{6}+\sqrt{3}-\sqrt{9}+\sqrt{4}-\sqrt{12}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\) = \(\frac{\sqrt{2}\left(1-\sqrt{3}\right)+\sqrt{3}\left(1-\sqrt{3}\right)+\sqrt{4}\left(1-\sqrt{3}\right)}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)\(=\frac{\left(1-\sqrt{3}\right)\left(\sqrt{2}+\sqrt{3}+\sqrt{4}\right)}{\sqrt{2}+\sqrt{3}+\sqrt{4}}=1-\sqrt{3}\)
d) \(\frac{\sqrt{\left(\sqrt{5}-1\right)^2}}{\sqrt{5}-1}=\frac{\sqrt{5}-1}{\sqrt{5}-1}=1\)
12 tháng 8 2019
những ai thích xem minecraft và blockman go thì hãy xem kênh youtube của mik kênh mik là M.ichibi các bn nhớ sud và chia sẻ cho nhiều người khác nhé
25 tháng 6 2016
B=\(\frac{6-6\sqrt{3}}{1-\sqrt{3}}+\frac{3\sqrt{3}+3}{\sqrt{3}+1}=\frac{6\left(1-\sqrt{3}\right)}{1-\sqrt{3}}+\frac{3\left(\sqrt{3}+1\right)}{\sqrt{3}+1}=6+3=9\)
C=\(\frac{3+\sqrt{3}}{\sqrt{3}}+\frac{\sqrt{6}-\sqrt{3}}{1-\sqrt{2}}=\frac{3\left(1+\sqrt{3}\right)}{\sqrt{3}}+\frac{\sqrt{3}\left(\sqrt{2}-1\right)}{1-\sqrt{2}}=\sqrt{3}+1-\sqrt{3}=1\)
D=\(\frac{\sqrt{10}-\sqrt{2}}{\sqrt{5}-1}+\frac{2-\sqrt{2}}{\sqrt{2}-1}=\frac{\sqrt{2}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}+\frac{\sqrt{2}\left(\sqrt{2}-1\right)}{\sqrt{2}-1}=\sqrt{2}+\sqrt{2}=2\sqrt{2}\)
E=\(\frac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}+\frac{1}{2-\sqrt{3}}=\frac{\sqrt{3}\left(\sqrt{5}-2\right)}{\sqrt{5}-2}+\frac{1}{2-\sqrt{3}}=\sqrt{3}+\frac{1}{2-\sqrt{3}}=\frac{2\sqrt{3}-1}{2-\sqrt{3}}\)
Làm tới dòng thứ 3 máy đơ, 2 lần rồi T,T
Mình chia làm 2 phần tính nhé
\(A=\frac{4\sqrt{2}}{\sqrt{10-2\sqrt{21}}}+\frac{3}{\sqrt{15+6\sqrt{6}}}-\frac{1}{\sqrt{19-6\sqrt{10}}}\)
\(A=\frac{4\sqrt{2}}{\sqrt{\left(\sqrt{7}-\sqrt{3}\right)^2}}+\frac{3}{\sqrt{\left(\sqrt{9}+\sqrt{6}\right)^2}}-\frac{1}{\sqrt{\left(\sqrt{10}-\sqrt{9}\right)^2}}\)
\(A=\frac{4\sqrt{2}}{\sqrt{7}-\sqrt{3}}+\frac{3}{3+\sqrt{6}}-\frac{1}{\sqrt{10}-3}\)
\(A=\frac{4\sqrt{2}\left(\sqrt{7}+\sqrt{3}\right)}{7-3}+\frac{3\left(3-\sqrt{6}\right)}{9-6}-\frac{1\left(\sqrt{10}+3\right)}{10-9}\)
\(A=\frac{4\sqrt{14}+4\sqrt{6}}{4}+\frac{9-3\sqrt{6}}{3}-\sqrt{10}-3\)
\(A=\sqrt{14}+\sqrt{6}+3-\sqrt{6}-\sqrt{10}-3\)
\(A=\sqrt{14}-\sqrt{10}\)
\(B=\sqrt{6+\sqrt{35}}\)
\(B=\frac{\sqrt{2}\left(\sqrt{6+\sqrt{35}}\right)}{\sqrt{2}}\)
\(B=\frac{\sqrt{12+2\sqrt{35}}}{\sqrt{2}}\)
\(B=\frac{\sqrt{\left(\sqrt{7}+\sqrt{5}\right)^2}}{\sqrt{2}}\)
\(B=\frac{\sqrt{7}+\sqrt{5}}{\sqrt{2}}\)
\(\Rightarrow M=A.B=\left(\sqrt{14}-\sqrt{10}\right).\frac{\sqrt{7}+\sqrt{5}}{\sqrt{2}}\)
\(M=\sqrt{2}\left(\sqrt{7}-\sqrt{5}\right).\frac{\sqrt{7}+\sqrt{5}}{\sqrt{2}}\)
\(M=\left(\sqrt{7}+\sqrt{5}\right)\left(\sqrt{7}-\sqrt{5}\right)\)
\(M=\left(\sqrt{7}\right)^2-\left(\sqrt{5}\right)^2\)
\(M=7-5=2\)