tính giá trị biểu thức:
a) \(\dfrac{4}{6}\div\dfrac{4}{3}+5\div\dfrac{4}{3}\)
K
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3
NN
10 tháng 11 2017
\(4\dfrac{1}{3}:\dfrac{x}{4}=6:0,3\)
\(\Leftrightarrow4\dfrac{1}{3}:\dfrac{x}{4}=20\)
\(\Leftrightarrow\dfrac{x}{4}=4\dfrac{1}{3}:20\)
\(\Leftrightarrow\dfrac{x}{4}=\dfrac{13}{60}\)
\(\Leftrightarrow x.60=4.13\)
\(\Leftrightarrow x.60=52\)
\(\Leftrightarrow x=52:60\)
\(\Leftrightarrow x=\dfrac{13}{15}\)
NM
19 tháng 10 2023
\(A=\left(3-\dfrac{1}{4}+\dfrac{3}{2}\right)-\left(5+\dfrac{1}{3}-\dfrac{5}{6}\right)-\left(6-\dfrac{7}{4}+\dfrac{2}{3}\right)\\ \Rightarrow A=3-\dfrac{1}{4}+\dfrac{3}{2}-5-\dfrac{1}{3}+\dfrac{5}{6}-6+\dfrac{7}{4}-\dfrac{2}{3}\\ \Rightarrow A=\left(3-5-6\right)-\left(\dfrac{1}{4}+\dfrac{7}{4}\right)+\left(\dfrac{3}{2}+\dfrac{5}{6}-\dfrac{2}{3}\right)\\ \Rightarrow A=-8-\dfrac{3}{2}+\dfrac{5}{3}\\ =-\dfrac{47}{6}.\\ B=0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)
\(\Rightarrow B=\left(0,5+0,4\right)+\left(\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{5}{7}-\dfrac{4}{35}\right)+\dfrac{1}{41}\\ \Rightarrow B=\dfrac{9}{10}+\dfrac{1}{2}+\dfrac{3}{5}+\dfrac{1}{41}\\ \Rightarrow B=2+\dfrac{1}{41}\\ \Rightarrow B=\dfrac{83}{41}.\)
NH
1 tháng 3 2023
`1/3-2/15+14/15`
`=5/15-2/15+14/15`
`=17/15`
`3/5+4-6/7`
`=21/35+140/35-30/35`
`=131/35`
12 tháng 7 2021
Ta có: \(x=\sqrt{\dfrac{2}{3}}:\sqrt{\dfrac{3}{2}}\)
\(=\sqrt{\dfrac{2}{3}:\dfrac{3}{2}}=\sqrt{\dfrac{2}{3}\cdot\dfrac{2}{3}}=\dfrac{2}{3}\)
Ta có: \(M=\sqrt{6x+5}\)
\(=\sqrt{6\cdot\dfrac{2}{3}+5}=\sqrt{9}=3\)
NT
12 tháng 7 2021
Ta có \(x=\sqrt{\dfrac{2}{3}}:\sqrt{\dfrac{3}{2}}=\sqrt{\dfrac{2}{3}.\dfrac{2}{3}}=\dfrac{2}{3}\)
Thay \(x=\dfrac{2}{3}\) vào biếu thức \(M\), ta được :
\(M=\sqrt{6.\dfrac{2}{3}+5}=\sqrt{4+5}=\sqrt{9}=3\)
27 tháng 9 2021
\(=\dfrac{3}{4}-\dfrac{5}{6}\times\dfrac{7}{24}\times\dfrac{12}{7}=\dfrac{3}{4}-\dfrac{5}{12}=\dfrac{1}{3}\)
27 tháng 9 2021
\(\dfrac{3}{4}-\dfrac{5}{6}\left(\dfrac{1}{6}+\dfrac{1}{8}\right):\dfrac{7}{12}\)
\(=\dfrac{3}{4}-\dfrac{5}{6}\cdot\dfrac{7}{24}\cdot\dfrac{12}{7}\)
\(=\dfrac{3}{4}-\dfrac{5}{12}\)
\(=\dfrac{4}{12}=\dfrac{1}{3}\)
25 tháng 9
Mới thế đã hai năm trôi qua,câu trả lời từ mọi người vẫn KO XUẤT HIỆN.
Ko biết sau này câu trả lời có xuất hiện hay ko...
6 tháng 7 2021
\(=\dfrac{2}{3}+\dfrac{1}{3}.\dfrac{7}{18}.\dfrac{12}{7}\)
\(=\dfrac{2}{3}+\dfrac{7.3.2.2}{3.7.3.2.3}\)
\(=\dfrac{2}{3}+\dfrac{2}{9}=\dfrac{8}{9}\)
VV
6 tháng 7 2021
TICK CHO MÌNH NHÉ
Giải:
\(\dfrac{2}{3}\) + \(\dfrac{1}{3}\) . (\(-\dfrac{4}{9}\) + \(\dfrac{5}{6}\) ) : \(\dfrac{7}{12}\)
= \(\dfrac{2}{3}\) + \(^{\dfrac{1}{3}}\) . \(\dfrac{7}{18}\) : \(\dfrac{7}{12}\)
= \(\dfrac{2}{3}\) + \(\dfrac{7}{54}\) : \(\dfrac{7}{12}\)
= \(\dfrac{2}{3}\) + \(\dfrac{2}{9}\)
= \(\dfrac{8}{9}\)
26 tháng 2 2022
\(=\dfrac{2}{3}+\dfrac{1}{3}.\left(\dfrac{7}{18}\right):\dfrac{7}{12}\)
\(=\dfrac{2}{3}+\dfrac{7}{54}:\dfrac{7}{12}\)
\(=\dfrac{2}{3}+\dfrac{2}{9}\)
\(=\dfrac{8}{9}\)
11 tháng 7 2023
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2^8-2^3}{2^5-1}=\dfrac{2^3\left(2^5-1\right)}{2^5-1}=\dfrac{2^3}{1}=2^3=8\)
_____
\(\dfrac{4^8\cdot9^4}{6^6\cdot8^3}\)
`=`\(\dfrac{\left(2^2\right)^8\cdot\left(3^2\right)^4}{2^6\cdot3^6\cdot\left(2^3\right)^3}\)
`=`\(\dfrac{2^{16}\cdot3^8}{2^6\cdot3^6\cdot2^9}\)
`=`\(\dfrac{2^{16}\cdot3^8}{2^{15}\cdot3^6}\)
`=`\(\dfrac{3^2}{2}\) `=`\(\dfrac{9}{2}\)
______
\(\dfrac{27^4\cdot2^3-3^{10}\cdot4^3}{6^4\cdot9^3}\)
`=`\(\dfrac{\left(3^3\right)^4\cdot2^3-3^{10}\cdot\left(2^2\right)^3}{2^4\cdot3^4\cdot\left(3^2\right)^3}\)
`=`\(\dfrac{3^{12}\cdot2^3-3^{10}\cdot2^6}{2^4\cdot3^4\cdot3^6}\)
`=`\(\dfrac{3^{10}\cdot\left(3^2\cdot2^3-2^6\right)}{3^{10}\cdot2^4}\)
`=`\(\dfrac{72-2^6}{2^4}=\dfrac{8}{16}=\dfrac{1}{2}\)
ND
Nguyễn Đức Trí
VIP
11 tháng 7 2023
\(\dfrac{2^8-2^3}{2^5-1}=\dfrac{2^3\left(2^5-1\right)}{2^5-1}=2^3=8\)
\(\dfrac{4^8.9^4}{6^6.8^3}=\dfrac{2^{16}.3^8}{2^6.3^6.2^9}=2.3^2=18\)
\(\dfrac{27^4.2^3-3^{10}.4^3}{6^4.9^3}=\dfrac{3^{12}.2^3-3^{10}.2^6}{2^4.3^4.3^6}=\dfrac{2^3.3^{10}.\left(3^2-2^3\right)}{2^4.3^{10}}=\dfrac{9-8}{2}=\dfrac{1}{2}\)
`4/6 : 4/3 + 5 : 4/3`
`= 4/6 xx 3/4 + 5 xx 3/4`
`= 3/4 xx ( 4/6 +5)`
`= 3/4 xx 17/3`
`=17/4`
`4/6:4/3+5:4/3`
`=(4/6+5):4/3`
`=(4/6+30/6)xx3/4`
`=34/6xx3/4`
`=17/3xx3/4`
`=17/4`