Question

[Lê kim thục đoan]

giúp mình với ban ơi 

(っ◔◡◔)っ ♥ Aurora ♥ 

Answer 1

[⭐Hannie⭐]

`!`

`a, x+1/2=3/4`

`=>x=3/4-1/2`

`=>x=3/4-2/4`

`=>x=1/4`

`b, -2/3-x=1`

`=> x=-2/3-1`

`=>x=-2/3 -3/3`

`=>x=-5/3`

`c, (x-1/2)+3/5=1/5`

`=>x-1/2=1/5-3/5`

`=>x-1/2=-2/5`

`=>x=-2/5+1/2`

`=>x= 1/10`

`d, 1/4+3/4 :x=5/2`

`=> 3/4 :x=5/2-1/4`

`=> 3/4 :x=9/4`

`=>x= 3/4 : 9/4`

`=>x= 3/4 . 4/9`

`=>x= 1/3`

`e, (x+1/4).3/4=-5/8`

`=> x+1/4=-5/8 : 3/4`

`=> x+1/4=-5/8 . 4/3`

`=> x+1/4=-5/6`

`=>x=-5/6 -1/4`

`=>x= -13/12`

`f, x/(-24) =2/3`

`=> 3x=2.(-24)`

`=> 3x=-48`

`=>x=-48:3`

`=>x= -16`

Bn tách ra nữa nha , nhiều quá á

Answer 2

[⭐Hannie⭐]

`!`

`g, (x-3)/15=-2/5`

`=> (x-3).5= 15.(-2)`

`=> (x-3).5= -30`

`=>x-3=-30:5`

`=>x-3=-6`

`=>x=-6+3`

`=>x=-3`

`h, x/(-2)=-8/x`

`=> x.x=-2.(-8)`

`=>x^2 =16`

\(\Rightarrow x=\left[{}\begin{matrix}4\\-4\end{matrix}\right.\)

`i, (x+3)/4 =16/(x+3)`

`=> (x+3)^2 =4.16`

`=> (x+3)^2 = 64`

`=> (x+3)^2 = +-8^2`

\(\Rightarrow\left[{}\begin{matrix}x+3=8\\x+3=-8\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=5\\x=-11\end{matrix}\right.\)

`k, (x+2)/3=(x-3)/5`

`=> (x+2).5 = 3(x-3)`

`=> 5x+10 = 3x-9`

`=> 5x-3x=9-10`

`=> 2x= -1`

`=>x=-1/2`

`m, (2x-1)^2=4`

`=>  (2x-1)^2= +-2^2`

\(\Rightarrow\left[{}\begin{matrix}2x-1=2\\2x-1=-2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=3\\2x=-1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)

`p, (x+1/3)^2=4/9`

`=> (x+1/3)^2=(+- 2/3)^2`

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{2}{3}\\x+\dfrac{1}{3}=-\dfrac{2}{3}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-1\end{matrix}\right.\)

`q , (x-2)(2x-1)=0`

`@ TH1`

`x-2=0`

`=>x=0+2`

`=>x=2`

`@ TH2`

`2x-1=0`

`=>2x=0+1`

`=>2x=1`

`=>x=1/2`

`r, (2/3x +1/2)(-2x+3)=0`

`@ TH1`

`2/3x+1/2=0`

`=>2/3x=0-1/2`

`=>2/3x=-1/2`

`=>x=-1/2 : 2/3`

`=>x= -1/12`

`@ TH2`

`-2x+3=0`

`=> -2x=0-3`

`=>-2x=-3`

`=>x=3/2`

`s, (x^2 - 1 9/16 )(x^3+1/8)=0`

`@ TH1`

`x^2 -1 9/16=0`

`=>x^2 - 25/16=0`

`=>x^2=25/16`

`=>x^2=(+- 5/4)^2`

`=> x=(+-5/4)`

`@ TH2`

`x^3+1/8=0`

`=>x^3=1/8`

`=>x^3= (1/2)^3`

`=>x=1/2`