\(A=\frac{1}{30}+\frac{2}{30}+.....+1\)
Tính A
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Ta có: A=1/11+1/12+1/13+...+1/30
=(1/11+1/12+1/13+..+1/20)+(1/21+1/22+1/23+...+1/30)
\(\Rightarrow\)A<(1/10+1/10+1/10+...+1/10)+(1/20+1/20+1/20+...1/20)
\(\Rightarrow\)A<(1/10)*10+(1/20)*10
\(\Rightarrow\)A<1+1/2
\(\Rightarrow\)A<3/2<11/6
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)
\(=1-\left(\frac{1}{2}-\frac{1}{2}\right)-\left(\frac{1}{3}-\frac{1}{3}\right)-......-\left(\frac{1}{6}-\frac{1}{6}\right)-\frac{1}{7}\)
\(=1-\frac{1}{7}\)
\(=\frac{6}{7}\)
1/2+1/6+1/12+1/20+1/30+1/42
=1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
=1-1/7
=6/7
= 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9
= 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/9
=1-1/9
=8/9
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)
=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\)
= \(1-\frac{1}{9}\)
= \(\frac{8}{9}\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}=1-\frac{1}{10}=\frac{9}{10}\)
\(B=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\)
\(B=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)
\(B=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{7}-\frac{1}{8}=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\)
\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{30}+...+\frac{1}{72}+\frac{1}{81}\)
\(A=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{8\times9}+\frac{1}{81}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{8}-\frac{1}{9}+\frac{1}{81}\)
\(A=1-\frac{1}{9}+\frac{1}{81}=\frac{73}{81}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{81}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}+\frac{1}{81}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{8}-\frac{1}{9}+\frac{1}{81}\)
\(=1-\frac{1}{9}+\frac{1}{81}\)
\(=\frac{8}{9}+\frac{1}{81}\)
\(=\frac{73}{81}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{90}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{9.10}\)
\(=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(\frac{9}{10}\)
\(\frac{1}{2}\)+ \(\frac{1}{6}\)+ \(\frac{1}{12}\)+ \(\frac{1}{20}\)+ \(\frac{1}{30}\)+ ........ + \(\frac{1}{90}\)
= \(\frac{1}{1.2}\)+ \(\frac{1}{2.3}\)+ \(\frac{1}{3.4}\)+ \(\frac{1}{4.5}\)+ \(\frac{1}{5.6}\)+ ....... + \(\frac{1}{9.10}\)
= \(\frac{2-1}{1.2}\)+ \(\frac{3-2}{2.3}\)+ \(\frac{4-3}{3.4}\)+ \(\frac{5-4}{4.5}\)+ \(\frac{6-5}{5.6}\)+ ......... + \(\frac{10-9}{9.10}\)
= \(\frac{2}{1.2}\)- \(\frac{1}{1.2}\)+ \(\frac{3}{2.3}\)- \(\frac{2}{2.3}\)+ \(\frac{4}{3.4}\)- \(\frac{3}{3.4}\)+ \(\frac{5}{4.5}\)- \(\frac{4}{4.5}\)+ \(\frac{6}{5.6}\)- \(\frac{5}{5.6}\)+ ........ + \(\frac{10}{9.10}\)- \(\frac{9}{9.10}\)
= 1 - \(\frac{1}{2}\)+ \(\frac{1}{2}\)- \(\frac{1}{3}\)+ \(\frac{1}{3}\)- \(\frac{1}{4}\)+ \(\frac{1}{4}\)- \(\frac{1}{5}\)+ \(\frac{1}{5}\)- \(\frac{1}{6}\)+ ........... + \(\frac{1}{9}\)- \(\frac{1}{10}\)
Sau đó ta trực tiêu:
= 1 - \(\frac{1}{10}\)
= \(\frac{9}{10}\)
bài 1
\(\frac{13}{19}+5=\frac{108}{19}\)
Bài 2 sai de thi phai
Bài 3
Giải
Số phần bạn A làm xong kế hoạch là:
\(\frac{3}{5}+\frac{1}{4}=\frac{17}{20}\)
Vậy còn \(\frac{3}{20}\)phần kế hoạch chưa làm
Bài 4
\(\frac{47}{15}+\frac{40}{17}-\frac{4}{30}-\frac{6}{17}\)
\(=\left(\frac{40-6}{17}\right)+\left(\frac{47-2}{15}\right)=5\)
Bài 5
a)
\(\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\)VÀ \(\frac{1}{2x3}=\frac{1}{6}\)
Vạy 2 gia trị bằng nhau
b)
\(\frac{2}{3x5}=\frac{2}{15}\)Và \(\frac{1}{3}-\frac{1}{5}=\frac{2}{15}\)
Vậy 2 giá trị bằng nhau
Ta tính tổng của tất cả các tử số
( 30 + 1 ) x ((30 - 1 ) : 1 + 1 ) : 2 = 465
\(\Rightarrow A=\frac{465}{30}\)
\(\Rightarrow A=\frac{31}{2}\)
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Ai lại tự hỏi tự trả lời thế bao giờ??? Ồ! Tớ cũng là Song nhưng là Song ngư chứ không phải Song Tử