1 x 1 + 1 x 2 + 1 x 3 + .... + 1 + 1000 = ???
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1/1 x 2 + 1/2 x 3 + 1/3 x 4 + ... + 1/999 x 1000 + 1
= 1/1 - 1/1000 + 1
= 999/1000 + 1
= 1999/1000
Chuc ban may man
\(\frac{1}{3}+\frac{1}{6}=\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{499}{1000}\)
\(\frac{2}{6}+\frac{2}{12}+...+\frac{2}{x\left(x+1\right)}=\frac{499}{1000}\)
\(\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{x\left(x+1\right)}=\frac{499}{1000}\)
\(2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{x\left(x+1\right)}\right)=\frac{499}{1000}\)
\(2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{499}{1000}\)
\(2\left(\frac{1}{2}-\frac{1}{x-1}\right)=\frac{499}{1000}\)
\(\frac{1}{2}-\frac{1}{x-1}=\frac{499}{2000}\)
\(\frac{2000\left(x-1\right)}{2\left(x-1\right)2000}-\frac{2.2000}{\left(x-1\right)2.2000}=\frac{499.2\left(x-1\right)}{2000.2\left(x-1\right)}\)
Khử mẫu
\(2000x-2000-4000=998x-998\)
\(2000x-6000=998x-998\)
\(1002x-5002=0\)
\(1002x=5002\Leftrightarrow x=\frac{2501}{501}\)
Vậy xét là \(\frac{1}{2}+1\)nhé.
a,\(\frac{3}{2}x\frac{4}{3}x\frac{5}{4}x...x\frac{1000}{999}\)
=3x4x5x...x1000/2x3x4x...x999
=1000/2=500
b, c tương tự câu a
)(1/2+1)x(1/3+1)x(1/4+1)x...x(1/999+1)
b)(1/2-1)x(1/3-1)x(1/4-1)x...x(1/1000-1)
c)3/22 x 8/32 x 15/42 x .... x 99/102
mình ko biết làm chép lại de thui
\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{999\times1000}+1\)
\(=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+....+\frac{1}{999000}+1\)
\(=1-\frac{1}{1000}+1\)
\(=\frac{1999}{1000}\)
(1000 - 13) x (1000 - 23) x (1000 - 33) x ... x (1000 - 103) x ... x (1000 - 503)
= (1000 - 13) x (1000 - 23) x (1000 - 33) x ... x (1000 - 1000) x ... x (1000 - 503)
= (1000 - 13) x (1000 - 23) x (1000 - 33) x ... x 0 x ... x (1000 - 503)
= 0
theo bai co 1/3+1/6+...+2/x.x+1=499/1000
(=)2/2.3+2/3.4+...+2/x.(x+1)=499/1000
(=)2(1/2-...-1/x+1)=499/1000
(=)1/2-1/x+1=499/2000
(=)1/x+1=501/2000
den day thi minh chiu roi!
mk kocó hiểu đề bn ạ!
Mình nghĩ đề bài là :1x1+1x2+1x3+...+1x1000
=1+2+3+4+....+1000
=(1+1000)*1000/2
=500500