Tìm x biết { x +1 } + { x +3 } + { x + 5 } + .... + { x + 9 } = 750
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Giải
( x + 1 ) + ( x + 3 ) + ( x + 5 ) + ( x + 7 ) + ( x + 9 ) = 750
x x ( 1 + 3 + 5 + 7 + 9 ) = 750
x x 25 = 750
x = 750 : 25
x = 30
Đúng nha
Lời giải:
a)
$1+3+5+...+(2x-1)=750$
$\frac{(2x-1+1)x}{2}=750$
$x^2=750$
$x=\sqrt{750}$ (vô lý?!!)
b)
$1+5+9+13+...+x=501501$
$\frac{1}{2}(\frac{x-1}{4}+1)(x+1)=501501$
$(x+1)(x+3)=4012008$$x(x+4)=4012005=2001.2005$
$\Rightarrow x=2001$
1
\(\left(x-2\right):2.3=6\)
\(\Leftrightarrow\left(x-2\right):2=2\)
\(\Leftrightarrow\left(x-2\right)=4\)
\(\Leftrightarrow x=4+2=6\)
c) ta có
\(\left[\left(2x+1\right)+1\right]m:2=625\)
\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)
\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)
\(\Leftrightarrow\left(2x+1\right)^2=1250\)
...
2
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)
( x + 1 ) + ( x + 2 ) + ... + ( x + 9 ) = 750
9x + 45 = 750
9x = 750 - 45
9x = 705
x = 705 : 9
x = 78,33333333333333333333333....
Ta có:(x+1)+(x+2)+(x+3)+(x+4)+...+(x+9)=750
suy ra:(x+x+x+x+x+x+x+x+x)+(1+2+...+9)=750
suy ra:9.x+(9+1).9:2=750
suy ra:9x+45=750
suy ra:9x=705
suy ra x =705/9
nhớ bấm đúng cho mình nha
\(5^X+5^{X+1}=750\\ 5^X\cdot\left(1+5\right)=750\\ 5^X\cdot6=750\\ 5^X=125\\X=3 \)
b1
day chu hanoihanoi co 10 chu cai
ta co: 2016:10=201(du 6)
vay chu cai thu 2016 la chu H
a, (x + 2) + (x + 4) + (x + 6) + ... + (x + 50) = 750
=> x + 2 + x + 4 + x + 6 + ... + x + 50 = 750
=> (x + x + x + ... + x) + (2 + 4 + 6 + ... + 50) = 750
=> 25x + (50 + 2).25 : 2 = 750
=> 25x + 52.25 : 2 = 750
=> 25x + 650 = 750
=> 25x = 100
=> x = 4
a) ( x+x+...+x)+(2+4+6+...+50)= 750
( x*25)+ (50+2)*25:2 = 750
(x*25)+ 650 = 750
x* 25 = 750 - 650 = 100
x = 100 :25 = 4
\(5^x+5^{x-1}=750\)
\(\Rightarrow5^x+5^x.\frac{1}{5}=750\)
\(\Rightarrow5^x.\left(1+\frac{1}{5}\right)=750\)
\(\Rightarrow5^x.\frac{6}{5}=750\)
\(\Rightarrow5^x=750:\frac{6}{5}\)
\(\Rightarrow5^x=625\)
\(\Rightarrow5^x=5^4\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
Ta có : 5x + 5x - 1 = 750
\(\Rightarrow\) 5x + 5x - 1 = 625 + 125
\(\Rightarrow\) 5x + 5x - 1 = 54 + 53
\(\Rightarrow\) x = 4
Vậy x = 4
1 )
X x 17 - X x 8 = 405
X x ( 17 - 8 ) = 405
X x 9 = 405
X = 405 : 9
X = 45
2 )
2250 : x + 750 = 8
2250 : x = 8 - 750
2250 : x = ...
Có sai đề không bạn ?
x + 1 + x + 3 +x + 5 + x + 7 + x + 9 = 750
( x + x + x + x + x ) + ( 1 + 3 + 5 + + 7 + 9 ) = 750
x x 5 + 25 = 750
x x 5 = 750 - 25
x x 5 = 725
x = 725 :5
x = 145
x=750:(1+3+5+7+9)
x=750:25
x=30